I am familiar with using if else statement but my problem is how to display either if the condition is met.
if ($a == 1) {
echo 'B' OR 'C'; // just for reference
}
I have finally figure this out using nested loop
if ($a == 1) {
choiceresult = mt_rand(1,2)
if (choiceresult == 1) {
echo 'B';
}
if ( choiceresult == 2) {
echo 'C';
}
}
you have to fix your condition first :
if($a == 1)
Instead pf
if($a = 1)
Related
This question already has answers here:
The 3 different equals
(5 answers)
Closed 4 years ago.
I am trying to apply some if else statements in my code but getting a bit confused. I want a result if I got value=0 answer should be One. if I got value=1 answer should be Two and if I got any value greater then 1 value should be Three. Following is my code: -
$value = 1
if($value < 1)
{
echo "One";
}
else if($value === '1')
{
echo "Two";
}
else if($value >= 2)
{
echo "Three";
}
The problem is that it is not giving me results if value is = 1.
change this else if($value === '1') to else if($value == 1)
=== matched both value and type that's why 1==='1' is false, See Ref.
$a === $b Identical TRUE if $a is equal to $b, and they are of the same type.
<?php
$value = 1;
if($value < 1)
{
echo "One";
}
else if($value == '1')
{
echo "Two";
}
else if($value >= 2)
{
echo "Three";
}
?>
DEMO: https://3v4l.org/avOWc
I am trying to reduce/simplify the following code as it looks to have repeated elements:
<?php
if ($condition == true) {
if ($a > $b*0.5) {
echo "successful";
}
else {
echo "missed";
}
}
else {
if ($a > $b) {
echo "successful";
}
else {
echo "missed";
}
}
I don't want to use functions because if I did, I would have to define all the database things again.
<?php
if ( (condition1 && ($a > $b*0.5)) || (!condition1 && ($a > $b)) ) {
echo "successful";
else {
echo "missed";
}
?>
Your Code is missed Two (Semicoloumns)}.
Try By this
<?php
$a == 2;
$b == 4;
if ($a == 2 && $a > $b*0.5) {
echo "Suuccess";
}elseif($a != 2 && $a > $b){
echo "Suuccess";
}else{
echo "Fails";
}
In order to simplify your conditions, if the output is boolean (so only two outcomes possible) you could go with either one as default and only change it to the other depending on your decisions.
<?php
$outcome = false;
if($condition1 && ($a > ($b * 0.5))) {
$outcome = true;
}
else if($a > $b) {
$outcome = true;
}
if($outcome) {
echo "succesful";
}
else {
echo "missed";
}
This also combines the technique proposed by Sofyan Thayf to use boolean operators to merge conditions.
Another approach is to put the condition into a function and return early if succesful and have a missed fallthrough like
<?php
function decide($a, $b, $condition1) {
if($condition1 && ($a > ($b * 0.5)))
return true;
if($a > $b)
return true;
return false;
}
if(decide($a, $b, $condition1)) {
echo "succesful";
}
else {
echo "missed";
}
Both approaches enable you to extract the "same code" (being the echo) and IMHO add to readability and extensibility.
<?php
$factor = $condition ? 0.5 : 1;
if ($a > $b * $factor) {
echo "Hit";
}
else {
echo "Miss";
}
Could be further reduced using two ternary operators:
echo $a > $b * ($condition ? 0.5 : 1)
? 'Hit'
: 'Miss';
Ternary operators are useful shorthand for if/else conditionals.
I have two questions
1) how can i make php to check getnext() function,if it exists or what value it has ???
$a = 1;
if($a == 1 or getnext()== 1){
echo "yeap"; //this works
}
2)i want to write condition -- if $a or $b is equal to 1 , print the variable name that has the value of 1.
Is it possible to do in php ??can i do it this way???
if($a ==1 or $b==1){
print($a or $b);
}
thanks in advance:)
You could for example do as follows :
if($a ==1 || $b==1){
print (($a == 1)? $a : $b);
}
For your first question,
your getnext() function must be return some valid integer value then only you can compare it with integer 1.
for second,
You should write
if($a == 1 && $b == 1){
echo 'both are 1';
}
else if($a == 1){
echo '$a is 1';
}
else if($b == 1){
echo '$b is 1';
}else{
// both are not 1
}
also see this links,
logical operators or vs || (double pipe) in php
PHP: return value from function and echo it directly?
You write condition? You use if and else, if no else in if you put return. Goodluck
Any ideas how to shorten if statment in an elegant way.
My if statement:
if(getfoo1() == getfoo2() && getfoo2() == 1)
{
}
EDIT:
I'm looking for something like:
if(getfoo1() == getfoo2() ==1)
{
}
But I suppose we can't do this.
$a = getfoo1();
$b = getfoo2(); // less operations, while it not produces duplicate calls
if($a == $b && $b == 1){
// do something
}
$variable = ((getfoo1() == getfoo2() && getfoo2() == 1) ? $value1 : $value2);
More elegant, combined:
$a = getfoo1();
$b = getfoo2();
$variable = (($a == $b && $b == 1) ? $value1 : $value2);
Since we don't know the possible return values from the functions, if you assume they are integers then you can say:
$a = getfoo1();
$b = getfoo2();
if (($a * $b) === 1) { // strict equality for the win
echo 'hi';
}
The result would only be true iff both $a AND $b are 1.
Another way:
$both = array(getfoo1(), getfoo2());
// use array_diff_assoc so it checks multiple occurrences of the same value
$diffCount = count(array_diff_assoc($both, array(1, 1)));
if ($diffCount === 0) {
echo 'hi';
}
Since anyway getfoo2() == 1 must be true, a better approach is to first check whether getfoo2() is equal to 1. If it false no matter about 2nd condition. But If you first check getfoo1() == getfoo2() and and then check getfoo2() == 1 you have to check 2 conditions all the times.
Therefore go for
$a = getfoo1();
$b = getfoo2();
if($b == 1 && $a == $b)
{
// logiv
}
else
{
}
Try this.
$a = getfoo1();
$b = getfoo2();
if( intval($a && $b) === 1) {
echo 'hi';
}
I am doing the following if else statement below but number (//1) and number (//4) get executed at the same time, I am finding it abit hard to understand why.
<?php
//1
if($a == 1 && count($b) == 0) {
// do this
}
//2
elseif ($a == 1 && count($b) > 0) {
// do that
}
//3
if($a== 0 && count($b) == 0) {
// do a different thing
}
//4
else {
// do the last thing
}
?>
I have done this and it works but i think the should be a more suitable way for not using elseif for this.
else if($a== 0 && count($b) > 0) {
// do the last thing
}
but number (//1) and number (//4) get executed at the same time
It's because you don't have else before the if on //3
//3
if($a== 0 &&
Change to elseif($a== 0 &&
At the moment you have two separate IF conditions
You're missing a closing brace after your first if.
Also, you have a weird operator inside your first condition : $$. Maybe you intended to type &&?
$a = 10;
if ($a == 5) {
echo 'ok';
} elseif ($a == 10) { // $a is equal to 10, so it executes;
echo 'not_ok';
}
if ($a > 20) {
echo 'ok_ok';
} else { // $a is not >20 so else statement executes
echo 'not_not';
}
final result: not_oknot_not
If you are performing such tests on one and the same assignee, but different values, you might not want to execute more than one?
I guess you need elseif where third block is if
if ($a == 5) {
echo 'ok';
} elseif ($a == 10) { // $a is equal to 10, so it executes and stops the block;
echo 'not_ok';
} elseif ($a > 20) {
echo 'ok_ok';
} else { // $a is not >20, but the block was stopped on first elseif
echo 'not_not';
}
produces not_ok
Even if you move the else statement after the first elseif block as was suggested
if ($a > 20) {
echo 'ok_ok';
}
will execute, and if it's true, it will produce result, which again will result in double result
You might want to do this...
if ($a == 1 && count($b) == 0) {
// do this
}
//2
elseif ($a == 1 && count($b) > 0) {
// do that
}
elseif ($a== 0 && count($b) == 0) {
// do a different thing
}
else {
// do the last thing
}
The reason they get executed at the same time is that... Well technically they're not executed at the same time since it's procedural, but they both get executed because they are both different if else conditions. If you want only 1 execution, you should combine them :)