I have a mysql table structure like this (lets say tableA):
unitID, Value1, Value2, Value3, Value4, Value5, Value6, Value7, Value8.
I create a data table using the following code.
<html>
<head>
<style>
.tbstyle {
border: 1px solid #CCC;
font-family: Arial, Helvetica, sans-serif;
font-size: 14px;
border-collapse: collapse;
float: left;
}
.tbstyle td {
padding: 3px;
margin: 2px;
border: 1px solid #ccc;
text-align: center;
height: 13px;
}
</style>
</head>
<body>
<table class="tbstyle" id="">
<?php
include ("config.php");
$sql = "SELECT Value1, Value2, Value3, Value4, Value5, Value6, Value7, Value8 FROM tableA ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc())
{
echo "</td><td>". $row["Value1"] . "</td><td>" . $row["Value2"]. "</td><td>" . $row["Value3"]."</td><td>" . $row["Value4"]."</td><td>" . $row["Value5"].
"</td><td>" . $row["Value6"]."</td><td>" . $row["Value7"]."</td><td>" . $row["Value8"]. "</td></tr>";
}
echo "</table>";
} else { echo "0 results"; }
$conn->close();
?>
</table>
</body>
</html>
I have another mysql table (lets say tableB) which has saleID. I would like to generate above table side by side as many as the number of saleIDs on tableB.
and I need to make each generated <table id=""> to have a unique saleID. I mean table IDs should be named with saleID. I left the table id in the code blank. <table class="tbstyle" id="">
I'd really appreciate any help I can get. Thanks.
Here is my current code which is not complete and doesn't give the expected result:
<table class="tbstyle" id="">
<?php
$conn=mysqli_connect("localhost","root","","mydb");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql="SELECT saleID FROM tableB";
if ($result=mysqli_query($conn,$sql))
{
$rowcount=mysqli_num_rows($result);
}
$sql = "SELECT Value1, Value2, Value3, Value4, Value5, Value6, Value7, Value8 FROM tableA ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc())
for ($x = 0; $x <= $rowcount; $x++)
{
echo "</td><td>". $row["Value1"] . "</td><td>" . $row["Value2"]. "</td><td>" . $row["Value3"]."</td><td>" . $row["Value4"]."</td><td>" . $row["Value5"].
"</td><td>" . $row["Value6"]."</td><td>" . $row["Value7"]."</td><td>" . $row["Value8"]. "</td></tr>";
}
echo "</table>";
} else { echo "0 results"; }
$conn->close();
?>
</table>
Ok, so here is my suggestion.
SELECT saleID FROM tableB ORDER BY saleID.
loop on the results. For each saleID, do...
echo the start your table (<table>, <thead> ... </thead><tbody>)
SELECT * FROM tableA.
Loop on these results. For each row, echo one row of the table (<tr><td>...</td>...</tr>).
Close your table (</tbody></table>).
So you loop twice, once for tableB, again for tableA. Each saleID is a new table, in the inner loop.
One detail which is still unclear to me, is where is the link between tableA and tableB. How do you know the values in tableA apply to the saleID you just read? Anyway my answer is strictly or the HTML-PHP version, no database logic here.
Related
I have a problem in inserting table from my database to div.
html code:
<div class="content">
<?php
$query = "SELECT name, surname FROM players";
$response = #mysqli_query($dbc, $query);
if($response) {
echo' <table align="left"
cellspacing="5" cellpadding="8" >
<tr><td align="left"><b>First Name</b></td>
<td align="left"><b>Last Name</b></td></tr>';
while($row = mysqli_fetch_array($response)) {
echo '<tr><td align="left">' .
$row['imie'] . '</td><td align="left">' .
$row['nazwisko'] . '</td><td align="left">';
echo '</tr>';
}
echo '</table>';
} else {
echo "Couldn't issue database query";
echo mysqli_error($dbc);
}
mysqli_close($dbc);
?>
</div>
css code:
.content {
width: 1000px;
margin-left: auto;
margin-right: auto;
background-color: #ffffff;
color: #000000;
border-bottom: 14px solid #333333;}
Is there a way to insert this table to this div? Because when I'm loading this, the table is under my div'content'. The table should be in blank field 'a'.
Screenshot
Correctly indenting your code would have allowed you o spot the error relatively easily - there is an open td element. Either remove the last td from the echo statement in the loop or add additional td pair to first row in table so that they balance ( unless you use colspan attributes )
<style>
.content table tr td{ align:left;padding:5px;color:black;background:white; }
</style>
<div class='content'>
<?php
$sql = 'select `name`, `surname` from `players`';
$response = mysqli_query( $dbc, $sql );
if( $response ) {
echo "
<table align='left' cellspacing='5' cellpadding='8' >
<tr>
<td><b>First Name</b></td>
<td><b>Last Name</b></td>
</tr>";
while( $row = mysqli_fetch_array( $response ) ) {
echo "
<tr>
<td>{$row['imie']}</td>
<td>{$row['nazwisko']}</td>
</tr>";
}
echo "
</table>";
} else {
printf( 'Couldn\'t issue database query: %s', mysqli_error( $dbc ) );
}
mysqli_close( $dbc );
?>
</div>
There is an open <td> tag in your code you should close it before closing the <tr>
I am just starting with SQL, PHP, and HTML and I plan to take some courses, but I need a basic working model before I can move forward. I have an SQL database that has a few fields. I can display this data without a problem. I would like to filter this data with a drop-down box. Currently, I have the drop-down box populated with a Select Distinct command. I can not seem to figure out the syntax to modify my SQL Select command to only show records that match my pull-down box. Ha, I will be the first to admit that I have no clue what I am doing, but my problem is that I might not know the term I need to look up how to solve my problem. Google and I are tight, but we just can't put our finger on this one. Can you point me in the right direction? Thanks!
<!DOCTYPE html>
<head>
<style>
table {
font-family: arial, sans-serif;
border-collapse: collapse;
width: 100%;
}
td, th {
border: 1px solid #dddddd;
text-align: left;
padding: 8px;
}
tr:nth-child(even){
background-color: #dddddd;
}
</style>
<body>
<form action='new1.php' method="get" name='fPIC'>
<select class="form-dropdown validate[required]" style="width:150px" id="input_PIC" name="sPIC">
<?php
$link = mysqli_connect("localhost", "root", "**********", "pd4poc");
mysqli_select_db($link,'pd4poc');
$query = "SELECT DISTINCT PIC FROM dummydata order by PIC asc";
$result = mysqli_query($link,$query);
$menu=" ";
while($row = mysqli_fetch_array($result))
{
$menu .= "<option value=".$row['PIC'].">" .$row['PIC']. "</option>";
}
echo $menu;
echo "<table>";
while($row = mysqli_fetch_array($result))
{
echo "<tr><td>" . $row['PIC'] . "<td><td>" , $row['Reason'] . "<td><td>", $row['Status'] . "</td></tr>";
}
echo "</table>";
mysqli_close($link);
?>
</select>
<input type="submit" name="nPIC" value="Filter">
</form>
<?php
$link = mysqli_connect("localhost", "root", "**********", "pd4poc");
mysqli_select_db($link,'pd4poc');
$query = "SELECT * FROM dummydata"; //need to be picked from the pull down
$result = mysqli_query($link,$query);
echo "<table>";
echo "<tr>
<th>PIC</th>
<th>Reason</th>
<th>PlanApply</th>
<th>HOT</th>
<th>Status</th>
<th>Comments</th>
</tr>\n";
while($row = mysqli_fetch_array($result))
{
echo "<tr><td>" .
$row['PIC'] . "<td>",
$row['Reason'] . "<td>",
$row['PlanApply'] . "<td>",
$row['HOT'] . "<td>",
$row['Status'] . "<td>",
$row['Comments'] . "</td>\n</tr>";
}
echo "</table>";
mysqli_close($link);
?>
</body>
</head>
I have read all the post about coding three columns for PHP. However, I can't seem to find any that will allow me to create three column loop. Everything I do either gives me an error or a blank white page. I also need to have a little space between the column loops. Here is what I have so far, can you tell me what I am missing?
table, td, th {
border: 1px solid #000;
text-align: left;
}
table {
border-collapse: initial;
width: 100%;
}
td {
padding: 10px;
width: 5%;
line-height: 2;
}
th {
background-color: grey;
color: white;
padding: 15px;
width: auto;
}
$sql = "SELECT name, email, dropdown, description FROM basic";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<table>";
$columns=3;
// output data of each row
while($row = $result->fetch_assoc()) {
if ($row > 0 && ($columns) == 3) {
echo "<th>". $row["name"]. "</th><tr> <td>email: ". $row["email"]. "</td><tr> <td>category: " . $row["dropdown"] . "</td><tr><td>Announcement: " . $row["description"] . "</td></tr>";
}
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
$sql = "SELECT name, email, dropdown, description FROM basic";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<table>";
$columns=3;
$x = 0;
// output data of each row
echo "<tr>";
while($row = $result->fetch_assoc()) {
if ($row > 0 && ($columns) == 3) {
echo "<th>". $row["name"]. "</th><tr> <td>email: ". $row["email"]. "</td><tr> <td>category: " . $row["dropdown"] . "</td><tr><td>Announcement: " . $row["description"] . "</td></tr>";
if ($x == 3) {
echo "</tr>";
$x = 0;
}
$x++;
}
}
if ($x < 3) {
echo "</tr>";
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
Explaination :-
within the while loop , we will check the variable $x which we set it to 0 outside the loop and increment it for every iteration ,
when that variable be equal to 3 we will print the end of row </tr>
I need my table to include submissions into three columns then a new row start with three more columns, etc. So submission 1, first column, submission 2, second column, submission 3, 3 column. Then a new row and the process starts again. (HTML Example Code below)
Every time I try with my php code my page comes up blank so I am missing something somewhere.
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, name, website, url, email, date, description FROM basic";
$result = $conn->query($sql);
if ($result->num_rows>0){
<tr>
while ($row=$result->fetch_assoc()) {
echo "<table><tr><th><b>Company:</b> " . $row["name"]. "</th></tr><tr><td>
<b>URL:</b> <a href='".$row["url"]."'>".$row["url"]."</a></td></tr><tr><td>
<b>Email:</b> " . $row["email"]. "</td></tr><tr><td><b>Launch Date:</b> " .
$row["date"]. "</td></tr><tr><td><b>Announcement:</b> " .
$row["description"]. "</td>
</tr>";
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
?>
Example: This is what I am trying to get it to look like.
<style>
table, td, th {
border: 10px solid #ffffff;
text-align: left;
}
table {
border-collapse: initial;
width: 100%;
}
td {
padding: 15px;
width: 25%;
line-height: 2;
}
th {
background-color: grey;
color: white;
padding: 5px;
width: 25%;
}
</style>
<body>
<table class="ex1">
<tr>
<th>Company</th>
<th>Company</th>
<th>Company</th>
</tr>
<tr>
<td>
<b>URL:</b><br>
<b>Location:</b><br>
<b>Inductry:</b><br>
<b>Start Date:</b><br>
<b>Announcement:</b><br>
<br>
</td>
<td>
<b>URL:</b><br>
<b>Location:</b><br>
<b>Inductry:</b><br>
<b>Start Date:</b><br>
<b>Announcement:</b><br>
<br>
</td>
<td>
<b>URL:</b><br>
<b>Location:</b><br>
<b>Inductry:</b><br>
<b>Start Date:</b><br>
<b>Announcement:</b><br>
<br>
</td>
</table>
Your PHP code is not generating HTML in proper format. Please try below:
// Query executed here and resultset returned
if ($result->num_rows>0){
echo "<table>";
while ($row=$result->fetch_assoc()) {
echo "<tr><th><b>Company:</b> " . $row["name"]. "</th></tr>
<tr><td><b>URL:</b> <a href='".$row["url"]."'>".$row["url"]."</a></td></tr>
<tr><td><b>Email:</b> " . $row["email"]. "</td></tr>
<tr><td><b>Launch Date:</b> " . $row["date"]. "</td></tr>
<tr><td><b>Announcement:</b> " . $row["description"]. "</td></tr>";
}
echo "</table>";
} else {
echo "0 results";
}
Is there a PHP code that let's you compare 2 MySQL tables with each other and lets you add missing entries into one?
I have two tables. hs_hr_employee and rights. I want to add data from certain columns from the hs_hr_employee table so that they would be the same in the rights tables.
hs_hr_employee has multiple rows, whereas the rights table has 5 rows. The rights table gets the info from 4 columns from the hs_hr_employee table, emp_number, employee_id, emp_firstname, emp_lastname
Below is the code:
<?php
$connection = mysql_connect('localhost','admin','root');
if( isset($_POST['submit']) )
{
if( isset( $_POST['cb_change'] ) && is_array( $_POST['cb_change'] ))
{
foreach( $_POST['cb_change'] as $emp_number => $permission)
{
$sql = "UPDATE `rights` SET Permission='".mysql_real_escape_string($permission)."' WHERE emp_number='".mysql_real_escape_string($emp_number)."'";
echo __LINE__.": sql: {$sql}\n";
mysql_query( $sql );
}
}
}
?>
<p style="text-align: center;">
<span style="font-size:36px;"><strong><span style="font-family: trebuchet ms,helvetica,sans-serif;"><span style="color: rgb(0, 128, 128);">File Database - Administration Panel</span></span></strong></span></p>
<p style="text-align: center;">
</p>
<head>
<style type="text/css">
table, td, th
{
border:1px solid #666;
font-style:Calibri;
}
th
{
background-color:#666;
color:white;
font-style:Calibri;
}
</style>
</head>
<form method="post" action="admin.php">
<?php
if (!$connection)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db('users', $connection);
//mysql_query('INSERT into rights(Emp_num, ID, Name, Surname) SELECT emp_number, employee_id, emp_firstname, emp_lastname FROM hs_hr_employee');
$result = mysql_query("SELECT emp_number, employee_id, emp_firstname, emp_lastname, Permissions FROM rights");
mysql_query("INSERT INTO rights (emp_number, employee_id, emp_firstname, emp_lastname)
SELECT emp_number, employee_id, emp_firstname, emp_lastname
FROM hs_hr_employee
ON DUPLICATE KEY UPDATE employee_id = VALUES(employee_id), emp_number = VALUES(emp_number)
");
echo "<center>";
echo "<table >
<tr>
<th>Employee Number</th>
<th>ID</th>
<th>Name</th>
<th>Surname</th>
<th>Permissions</th>
<th>Change</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['emp_number'] . "</td>";
echo "<td>" . $row['employee_id'] . "</td>";
echo "<td>" . $row['emp_firstname'] . "</td>";
echo "<td>" . $row['emp_lastname'] . "</td>";
echo "<td>" . $row['Permissions'] . "</td>";
echo "<td> <select name='cb_change[]'><option value='all'>All</option> <option value='remote'>Remote Gaming</option> <option value='landbased'>Landbased Gaming</option> <option value='general'>General Gaming</option> </select> </td>";
echo "</tr>" ;
}
#echo "<td>" . $row['Change'] . "</td>";
echo "</table>";
echo "</center>";
#$_POST['cb_permissions'];
mysql_close($connection);
?>
<p style="text-align: center;">
</p>
<p style="text-align: center;">
</p>
<p style="text-align: right;">
<input name="Save_Btn" type="button" value="Save" />
</p>
</form>
Any idea how to do it?
Thanks,
Brian
I'd go with an INSERT INTO SELECT here.
Assume you recognize an employee by the Social Security Number (ssn), and you use this value to update, for instance, name and birthyear:
mysql_query("
INSERT INTO hs_hr_employee (ssn, name, birthyear)
SELECT ssn, name, birthyear
FROM hs_hr_rights
ON DUPLICATE KEY UPDATE name = VALUES(name), birthyear = VALUES(birthyear)
");
You can also add a WHERE in between FROM and ON DUPLICATE. Like so:
...
FROM hs_hr_rights
WHERE birthyear IS NULL
ON DUPLICATE KEY UPDATE name = VALUES(name), birthyear = VALUES(birthyear)
...
Although, I don't see the need of copying values since in most cases you can fetch them through JOINs.
select * from table a where a.common not in (select b.common from table b where a.common = b.common)
And run this as well
select * from table b where b.common not in (select a.common from table a where a.common = b.common)
Not possible in php but in mysql its ans is as above