How to display total number of days between two dates using php - php

Question

I want to count the total number of days between two date.
Note: I am not talking about the difference between two date
I found lots of answer on google and Stack Overflow. I am sharing here
$now = time(); // or your date as well
$your_date = strtotime("2018-06-01");
$datediff = $now - $your_date;
echo round($datediff / (60 * 60 * 24));
Output is 9
$now = strtotime("2018-06-09");
$your_date = strtotime("2018-06-01");
$datediff = $now - $your_date;
echo $numberDays= round($datediff / (60 * 60 * 24));
Output is 8
$dStart = new DateTime('2018-06-01');
$dEnd = new DateTime('2018-06-09');
$dDiff = $dStart->diff($dEnd);
echo $dDiff->days;
Output is 8
$date1=date_create("2018-06-01");
$date2=date_create("2018-06-09");
$diff=date_diff($date1,$date2);
echo $diff->format("%a");
Output is 8
$startTimeStamp = strtotime("2018-06-01");
$endTimeStamp = strtotime("2018-06-09");
$timeDiff = abs($endTimeStamp - $startTimeStamp);
$numberDays = $timeDiff/86400; // 86400 seconds in one day
// and you might want to convert to integer
echo $numberDays = intval($numberDays);
Output is 8
The correct answer for me is the first one 9 because it displays the total number of days from 1 to 9, not a difference.
I just want to know how to get the count because I don't want to use the time() because it's taking the current date.
For example: If I select the first date 2018-05-01 and my second date in 2018-05-31. So total days is 31, not 30.
Example:
I am working on a project which is related to the working days and salary. So employee will select the date. for example. I am the employee and in the last month May, I select the date 2018-05-01 and 2018-05-31 so I have to display the total working days.So the according to the date I worked 31 days and using above code in the question I am getting 30 days.
Hope you understand my issue. Would you help me out in this?

Answer 1

You can try this-
$dateOne = new DateTime("01-01-2018");
$dateTwo = new DateTime("09-06-2018");
echo $diff = $dateTwo->diff($dateOne)->format("%a");
Output- 159

Answer 2

Use the DateTime class and compare them via diff() method. $date1->diff($date2). The output will give you an accurate result of days:
$date1 = new DateTime('2018-01-01');
$date2 = new DateTime('2018-02-15');
print_r($date1->diff($date2));
Output:
DateInterval Object
(
[y] => 0
[m] => 1
[d] => 14
[h] => 0
[i] => 0
[s] => 0
[f] => 0
[weekday] => 0
[weekday_behavior] => 0
[first_last_day_of] => 0
[invert] => 0
[days] => 45
[special_type] => 0
[special_amount] => 0
[have_weekday_relative] => 0
[have_special_relative] => 0
)

Answer 3

<?php
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
?>
Output : 272 days.

Answer 4

You can try this:
<?php
$start_date = "2020-12-24";
$end_date = "2020-12-31";
$dateDiff = strtotime($end_date) - strtotime($start_date);
$numOfDays = $dateDiff / 86400;
echo $numOfDays;
?>
Output: 7

Answer 5

First compile and print $now and write down out put after some minutes 2nd time compile and print $now you will ge a difference

Answer 6

here i got your solution in first program php time(); function is dynamically change as per current time in millisecond (In PHP you can simply call time() to get the time passed since January 1 1970 00:00:00 GMT in seconds) here you are using round function to get rounded value after 12pm it your calculation will increase more then 8.5 and you get a rounded value which is 9
here brief explanation Getting unix timestamp in milliseconds in PHP5 and Actionscript3
in rest of program you are taking static time or custom time which are not effected by system time
$now = time(); // or your date as well
$your_date = strtotime("2018-06-01");
$datediff = $now - $your_date;
echo round($datediff / (60 * 60 * 24));
try above program before 12pm maybe you got your answer