Conversion issue after MySQL query - php

Question

What is the problem with my code I can make it work but the error Notice: Object of class mysqli_result could not be converted to int in C:\xampp\htdocs\PHP\index.php on line 50 is appearing above.
The real problem is if I make if($check_email > 0){ to if($check_email_row > 0){ I can't make the error message "Email is already registered" to show below the email textbox and adding the same existing email.
<?php
include("connection.php");
$name = $address = $email = $password = $cpassword = "";
$nameErr = $addressErr = $emailErr = $passwordErr = $cpasswordErr = "";
if($_SERVER["REQUEST_METHOD"] == "POST"){
if(empty($_POST["name"])){
$nameErr = "Name is required!";
}
else{
$name = $_POST["name"];
}
if(empty($_POST["address"])){
$addressErr = "address is required!";
}
else{
$address = $_POST["address"];
}
if(empty($_POST["email"])){
$emailErr = "email is required!";
}
else{
$email = $_POST["email"];
}
if(empty($_POST["password"])){
$passwordErr = "Password is required!";
}
else{
$password = $_POST["password"];
}
if(empty($_POST["cpassword"])){
$cpasswordErr = "Confirm Password is required!";
}
else{
$cpassword = $_POST["cpassword"];
}
if($name && $address && $email && $password && $cpassword){
$check_email = mysqli_query($connections,"SELECT email FROM mytbl WHERE email='$email'");
$check_email_row = mysqli_num_rows($check_email);
if($check_email > 0){
$emailErr = "Email is already registered!";
}else{
$query = mysqli_query($connections, "INSERT INTO mytbl (name,address,email,password,account_type)
VALUES ('$name','$address','$email','$cpassword','2')");
echo "<script language='javascript'>alert('New Record Has Been Added!')</script>";
echo "<script>window.location.href='index.php';</script>";
}
}
}
?>
<style>
.error{
color:red;
}
</style>
<?php include("nav.php");?>
<br>
<br>
<form method="POST" action="<?php htmlspecialchars("PHP_SELF"); ?>">
Name:<input type="text" name="name" value="<?php echo $name; ?>"> <br>
<span class="error"><?php echo $nameErr; ?></span><br>
Address:<input type="text" name="address" value="<?php echo $address; ?>"> <br>
<span class="error"><?php echo $addressErr; ?></span><br>
Email:<input type="text" name="email" value="<?php echo $email; ?>"> <br>
<span class="error"><?php echo $emailErr; ?></span><br>
Password:<input type="password" name="password" value="<?php echo $password; ?>"> <br>
<span class="error"><?php echo $passwordErr; ?></span><br>
Confirm Password:<input type="password" name="cpassword" value="<?php echo $cpassword; ?>"> <br>
<span class="error"><?php echo $cpasswordErr; ?></span><br>
<input type="submit" value="Submit">
</form>
<hr>
<?php
$view_query = mysqli_query($connections, "SELECT * FROM mytbl");
echo "<table border='1' width='50%'>";
echo "<tr>
<td>Name</td>
<td>Address</td>
<td>Email</td>
<td>Option</td>
</tr>";
while($row = mysqli_fetch_assoc($view_query)){
$user_id = $row["id"];
$db_name = $row["name"];
$db_address = $row["address"];
$db_email = $row["email"];
echo "<tr>
<td>$db_name</td>
<td>$db_address</td>
<td>$db_email</td>
<td>
<a href='Edit.php?id=$user_id'>Update</a>
<a href='ConfirmDelete.php?id=$user_id'>Delete</a>
</td>
</tr>";
}
echo"</table>";
?>
<hr>
<?php
$names = array("ian","Joshua","vinoya");
foreach($names as $display_names) {
echo $display_names . "<br>";
}
?>