Button Add with modal ajax - php

Question

I'm trying to add a button to add a row in a table adding the values also in a database but when i click the button it refresh my page and doesn't add any row and in my database doesn't add any values.
This is the html form:
<div class="modal fade" id="modaladdWork" tabindex="-1" role="dialog" aria-
labelledby="exampleModalLabel" aria-hidden="true" >
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<h5 class="modal-title" id="modaladdWorkLabel">New Work</h5>
<button type="button" class="close" data-dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span>
</button>
</div>
<form name="formaddWork">
<div class="modal-body">
<div class="container w-75">
<select id="roleaddWork" name="role" class="form-control" aria-label="Role" aria-describedby="basic-addon1">
<option>Direttore</option>
<option>Vice Direttore</option>
<option>Capo Settore</option>
<option>Dipendente</option>
<option>Stagista</option>
</select> <br>
<input type="number" id="yearaddWork" name="year" min="1900" class="form-control" placeholder="Year" aria-label="Year" aria-describedby="basic-addon1">
<br/>
<input type="text" id="placeaddWork" name="place" class="form-control" placeholder="Place" aria-label="Place" aria-describedby="basic-addon1">
<br />
<?php
$query = "select * from company;";
$result=mysqli_query($connessione, $query);
echo mysqli_error($connessione);
if(mysqli_num_rows($result) > 0){
echo "<div style='float:left';><select id='companyaddWork' name='company' class='form-control' aria-label='Company' aria-describedby='basic-addon1'>";
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){
echo "<option>".$row["name"]."</option>";
}
echo "</select></div> <div class='modal-footer'><div style='float:right';>
<button type='button' class='btn btn-primary float-right' data-toggle='modal' data-target='#modalCompany'>
Add Company
</button>
</div></div>";
}
else{
echo "Inserisci prima una compagnia";
}
?>
</div>
</div>
<div class="modal-footer">
<button type="submit" id="submitaddWork" class="btn btn-primary">Save</button>
</div>
</form>
</div>
</div>
</div>
and this the javascript code :
function openmodal_addWork()
{
$('#modaladdWork').find('.modal-title').text("Add Work row");
$('#modaladdWork').find(':submit').text("Add");
$('#submitaddWork').click(function() {
op_addWork();
});
$('#modaladdWork').modal('show');
}
function op_addWork()
{
role = $('#roleaddWork').val();
year = $('#yearaddWork').val();
place = $('#placeaddWork').val();
company = $('#companyaddWork').val();
$('#modaladdWork').modal('hide');
$.ajax({
type: "POST",
url: "json/Lavoro.php",
data: {
'role': role,
'year': year,
'place': place,
'company': company
},
success: function(data){
console.log(data);
columns = $(button).closest('tr').find('td');
columns[0].innerHTML = role;
columns[1].innerHTML = year;
columns[2].innerHTML = place;
columns[3].innerHTML = company;
}
});
}
and this one the file "Lavoro.php" that is in the folder "json" :
<?php
if(strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) != 'xmlhttprequest')
{
header("Location: ../Principale.php");
exit();
}
if(!isset($_COOKIE["id"]))
{
$json_data = array(
'draw' => 0,
'recordsTotal' => 0,
'recordsFiltered' => 0,
'data' => [],
'error' => 'Laravel Error Handler',
);
$json = json_encode($json_data);
echo $json;
exit();
}
include("../DB.php"); //dati configurazione del database
if(isset($_POST["role"]) && isset($_POST["year"]) && isset($_POST["place"]) && isset($_POST["company"]))
{
$role = mysqli_real_escape_string($connessione, $_POST["role"]);
$year = mysqli_real_escape_string($connessione, $_POST["year"]);
$place = mysqli_real_escape_string($connessione, $_POST["place"]);
$company = mysqli_real_escape_string($connessione, $_POST["company"]);
$result=mysqli_query($connessione,"select company_id from company where name='".$company."';");
$row=mysqli_fetch_array($result,MYSQLI_NUM);
$comp_id=$row[0];
$eeid=$_COOKIE['id'];
$result = mysqli_query($connessione, "INSERT into WORK_EXPERIENCE (role,year,place,company_id,user_id) VALUES ('$role','$year','$place','$comp_id,'$eeid')");
$json_data = array(
//"id" => $id,
"result" => 1
);
$json = json_encode($json_data);
echo $json;
}
?>
What i'm doing of wrong?

Answer 1

Solved. In this line :
$result = mysqli_query($connessione, "INSERT into WORK_EXPERIENCE
(role,year,place,company_id,user_id) VALUES
('$role','$year','$place','$comp_id,'$eeid')")
there was no summit in $comp_id.