I am trying to access to a folder using "include $path" inside a php file.
Inside the folder, it includes a lot of images, and in php, it includes many tags of img that accesses to the images inside the folder.
Is there any way to access to a image's path inside folder using "include"?
That is not what include is for.
Include let you include another piece of PHP (some class, some functions, whatever), it is not for 'accessing' some folder.
If you want to see the contents (images) of that folder, try scandir:
https://secure.php.net/manual/en/function.scandir.php
Also make sure your webserver has rights to read those files.
On *nix/apache this user is often named www-data (I have seen 'nobody' and 'apache' too as usernames). On IIS it is typically something like IUSR.
Related
I have a PHP page on my site in a sub folder called Articles.
The page is article.php.
The article.php page requires a common php page called _head.php. This provides the header for the pages.
_head.php is located in the root directory.
The /Articles directory is a subdirectory within the root.
I've included this _head.php page in article.php this way:
<?php include("../_head.php"); ?>
And this works fine.
The problem, however, is that the image elements within _head.php are located in the 'images' subdirectory (also off the root) and are referenced relative to the _head.php being in the root, like this...
<img src="images/services.gif">
So if I use _head.php for files on the root, it works great and shows all the images correctly. But when I include _head.php into a php file that is not in the root, but instead in a subdirectory like /Articles (/Articles/articles.php), the images do not show up.
Do I need to change the _head.php file in how it references the images or is there some code I'm supposed to include in articles.php when including _head.php that tells it how to use _head.php?
I'm concerned about using all absolute paths because if I have to move this site to another server this is going to cause me issues.
Mentioning what I follow not going to the hierarchical complexity,
For any PHP file that is being imported into another PHP file in root simple include/require_once (<path>).
For any file below root accessing other file anywhere within the root I use include/require_once (../<path>).
For accessing files which are outside the root, I use the absolute path of that file.
Working on few php files what I have seen using absolute path is the best thing in two ways, a) you are free from remembering the paths of different files and b) if you are using CDN or if your files are on different servers then this is very helpful. Anyways opinions may vary, this is my personal view/choice.
I'm creating a .php file that will be uploaded to the root directory of a server. I need that .php file to then figure out the path to the public_html folder or it's equivalent.
I need to do this because I want my .php file to be able to be uploaded to the root and used on any hosting account. Because many hosting companies use different file paths to the public_html folder or even call it something different, I'm trying to figure out how to detect it.
Preferable there is a server variable or easy test to do this. If not, the public_html folder will always contain a particular file so maybe I could search for this particular file and get the path that way. I'm just worried about a filename search being heavy on memory.
The .php file that is being executed is located inside the ROOT directory and needs to locate the public_html folder.
Like this: /home/user/file.php
needs to detect
/home/user/public_html/ or /home/user/var/www/ or /home/user/website.com/html/ etc.
The challenge with this is that a server can have very many public_html's so outside of the context of a request there is no real way to find out what that is.
One thing that you might be able to do to get this information from a php script (if you know the url to get to the host) is to create a php file called docroot.php that looks like this.
<?php
if ($_SERVER["REMOTE_ADDR"] == '127.0.0.1'){
echo $_SERVER["DOCUMENT_ROOT"];
}
Then within your file.php your would do something like
$docRoot = trim(file_get_contents("http://www.mydomain.com/docroot.php"));
This makes the assumption that the server can resolve to itself via the local interface by name.
I found this website which provided me with the only good solution I have found after scouring the web...
$root = preg_replace("!${_SERVER['SCRIPT_NAME']}$!", "", $_SERVER['SCRIPT_FILENAME']);
The way this works is by getting the full path of the file and then removing the relative path of the file from the full path.
I have a problem on linking files such as stylesheets, images, database connection file(db.php), script files and etc.. because they are located outside the file where they are included/linked.
For example assuming this is the location of the main file where everything will be called:
my website directory/admin/thefilewhereeverythingwillbecalled.php
in thefilewhereeverythingwillbecalled.php, I must call the db.php which is located outside the folder that contains thefilewhereeverythingwillbecalled.php
e.g. my website directory/-this is the directory where the db.php is located-/thefilewhereeverythingwillbecalled.php - ditto the style sheets and script.
However the stylesheets and script are in the folder cssandjs (contains all stylesheets and script files) which this folder are located before the location of the thefilewhereeverythingwillbecalled.php
e.g. my website directory/-here is where the cssandjs folder is located-/thefilewhereeverythingwillbecalled.php
Generally I'm just having a problem on linking files which is outside from the file where it called those files. Can someone give me an idea how to link it please?
I tried this:
../cssandjs/style.cssand ./cssandjs/jquery.js but none of them work
If I'm correct, it's 2 directories up. Try this :
../../cssandjs/style.css
This will work if /cssandjs/ is in your website directory.
You should be a bit more specific with your directory names instead of -here is where this is located-
Can't seem to figure out which are in the same folder.
try to include full path to the files.
Try referencing the files like including the directories and files with
$_SERVER['DOCUMENT_ROOT']."/dirName/file.ext";
or use relative paths "../dirnName/file.ext";
first method is preferred
I have a folder that contains many different files:
folder1:
somthing.php
somthingelse.php
blah.php
ect ect....
Now, I don't want the files in that folder to access (include) files outside the folder. So it's okay to include('blah.php') but not okay to include('../blah.php')..
Any ideas on how I'd go about doing this?
This is only possible on the CLI and in a Unix environment. You would have to use chroot to hide other folders.
http://php.net/manual/en/function.chroot.php
I have a folder named "repository" in my admin folders. This folder holds 2 files: index.html and content.php. When a user creates a new page the php creates a new folder specified by the user then will need to copy the two files into that folder while leaving them in the repository.
copy(file,dest) does not work.
rename(file,dest) moves the files to the new folder but I lose them in the repository.
How do I copy the files in one folder to the new folder without losing the files in the original folder?
$dest = '../'.$menuLocation.'/'.$pageName;
$file1= "repository/index.html";
$file2= "repository/content.php";
mkdir($dest,0777);
rename($file1,$dest.'/index.html');
rename($file2,$dest.'/content.php');
$menuLocation and $pageName are supplied by the user. The files are there, file_exists returns back true. Also, the directory is created with no issues. rename() also works I just lose the files in repository.
For anyone hunting for the solution to this:
when using copy() in php you also need to include the file name.
copy(orginalfile,destination_with_filename);
for example:
wrong:
copy('/temp/sports/basketball.jpg','/images/sports/')
Correct:
copy('/temp/sports/basketball.jpg','/images/sports/basketball.jpg')
Use copy(). Make sure you capture the return value so that your program knows if it worked or not. Also check permission of the files and directory to confirm that the user executing the PHP script is able to create the new file in the place you specified. You might want use is_writable() on the directory to confirm these assumptions.