I am trying to design a scoreboard for a project for my local youth club and would like to be able to click a button onto a wordpress page that will run a PHP script to update a value by 1 in a sql db table, then i can grab the value and display it else where.
Not too worried about passwords being used in scripts at this will only be used within the local network that nobody else has access to, have looked around and found a few bits of code but im not able to actually get it working, here's what i've got so far.
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "sot";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = UPDATE wp_sotstats SET CaptainChest=CaptainChest+1 WHERE id=1
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
The database name is 'sot' the table i want to update is called 'wp_sotstats' and the field within the table is 'CaptainChest' i only need this to really work with just the one entry which the id is '1'
Any thoughts?
$sql = UPDATE wp_sotstats SET CaptainChest=CaptainChest+1 WHERE id=1
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
Is not creating record, it updating it. For me, I will take current value from database as Select, then do ++ to it and do Update query.
$sql = UPDATE wp_sotstats SET CaptainChest=CaptainChest+1 WHERE id=1
Please wrap it in quotes and finish statement with semicolon
Related
I am working with a coupon code website, it has a products section. Instead of pulling data from API server of shopping sites every time a visitor loads the page, I want to store the data in SQL and use it..
But the data should update every hour or only if an hour is passed.
cron job is not required as I dont want to happen it automatically.
If there is 100 webpage users in an hour, they will get the same data, but when the first user comes after 1 hour time, it should overwrite the products's information in SQL.
I got the following code from w3schools.com and it work fine for saving data in SQL.
I hope some can help me to overwrite data only if it the data older than 1 hour. Otherwise it should act as "data already exists".
<?php
$servername = "localhost";
$username = "nuser";
$password = "pass";
$dbname = "db";
$ProductId = "smartphone";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$check=mysqli_query($conn,"select * from testdb where productid='$ProductId'");
$checkrows=mysqli_num_rows($check);
if($checkrows>0) {
echo "Data Already Exists";
} else {
//insert results from the form input
$sql = "INSERT INTO Flipkart (productid, title, price)
VALUES ('productid','title','price')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();}
?>
The above code saves data in database, it can also detect duplicate data. but I want to add just one more function, which will overwrite data if the current data time is older than 1 hour. database has a TIMESTAMP "reg_date" column, which stores created date and time in YYYY-MM-DD HH:MM:SS format.
I am new to SQL and php, so pardon me if there is any problems with the question...
You can use a cron job.
This is the best explanation with code for PHP I have found so far for cron job:
https://code.tutsplus.com/tutorials/managing-cron-jobs-with-php--net-19428
Problem:
I want to get the MAX "SID" from my Database and add one. I handle the input via an Form that i submit through the HTTP Post Method. I get the current MAX "SID" from my database, then i put the value into an HTML input field and add one. For some reason this just works every other time. So the output i get is:
Try = 1
Try = 1
Try = 2
Try = 2
and so on. Would be nice if someone could point me in the right direction.
PHP get MAX(ID):
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "soccer";
$conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
echo "Connected successfully";
$sql = "SELECT MAX(SID) FROM spieler";
$result = mysqli_query($conn, $sql);
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_assoc($result))
{
$lastID = $row["MAX(SID)"];
}
}
mysqli_close($conn);
PHP insert in database:
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "soccer";
$conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
echo "Connected successfully";
?><br><?php
$sql = "INSERT INTO spieler VALUES ('$sid', '$name', '$verein',
'$position', '$einsaetze', '$startelf', '$tore',
'$torschuesse', '$eigentore', '$vorlagen', '$elfmeter',
'$verwandelt', '$gegentore', '$gelb',
'$rot', '$fouls', '$zweikampf', '$pass', '$note')";
if(mysqli_query($conn, $sql)){
echo "Success";
}else{
echo "Failed" . mysqli_error($conn);
}
mysqli_close($conn);
HTML & PHP Input Field:
<tr>
<td><input id="SID" name="SID" readonly value="<?php echo $lastID += 1;
?>"></td>
</tr>
Screenshot of the page:
The paragraph "Spieler ID:" is where I put the "SID" so that everytime the page loads the next free ID gets automatically loaded into the input field.
I want to get the MAX "SID" from my Database and add one
No. You don't. You really, really don't.
This is the XY Problem.
You can do it by running a system wide lock and a autonomous transaction. It would be a bit safer and a lot more efficient to maintain the last assigned value (or the next) as a state variable in a table rather than polling the assigned values. But this still ignores the fact that you going to great efforts to assign rules to what is a surrogate identifier and hence contains no meaningful data. It also massively limits the capacity and poses significant risks of both accidental and deliberate denial of service.
To further compound the error here, MySQL provides a mechanism to avoid all this pain out of the box using auto-increment ids.
While someone might argue that these are not portable, hence there may be merit in pursuing another solution, that clearly does not apply here, where your code has no other abstraction from the underlying DBMS.
I am currently working on a project which will sell a product to a user, and on checkout completion, the user will enter an email address. I have been trying (but to no avail so far) to use MySQL to put this data into a database. Only in a certain way. I need the input data to use the UPDATE method to be put into an already existing row. This row should match the following criteria. It should not have already been used, the email should not already exist within the database. I have tried so many different pieces of MySQL, I get all sorts from syntax errors to it updating every record in my table, I have gotten as far as it updating just one, but not checking if it already exists. I was hoping for a little insight as to how I can improve!
Code as follows:
<?php
$servername = "localhost";
$username = "Josh";
$password = "10584066";
$dbname = "customers";
// Get email address from input form
$Email = $_GET['keyword'];
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "UPDATE list SET Email='$Email' , In_Use='1' WHERE In_Use='0' LIMIT 1";
if ($conn->query($sql) === TRUE) {
echo "Record updated successfully";
header('Location: /liteservers/logon/wood.php');
} else {
echo "Error updating record: " . $conn->error;
}
$conn->close();
?>
So, as you can see. The code is working almost as intended, I just want it to also check to see IF the email is already in the database and if it is, perhaps add the time that it attempted to record a new email within the same row as the already found existing email. I hope this actually makes sense if you need any more info that I haven't provided, let me know!
Use INSERT ON DUPLICATE KEY UPDATE syntax and mysql_affected_rows will tell you if its and insert or update.
I'm fairly new to stack overflow. i am creating a site were you type text in to 2 text boxes and it sends it to a database. i need it then to tell me what the id of that was save it as a session and then upload it to another database. sounds confusing. but I'm stuck of one part. its viewing the result thats from just that user. i have tried just showing the the last id of the last uploaded but it can be very unreliable if multiple people are trying to upload data and know there exact session. I'm also having trouble linking the session with the id. below is the code for the forum saving to the database. I'm pretty confident with sending the id of that users inputed data to another database. I'm just stuck on finding that users inputed texts id and creating a session holding the id number
<?php
header("Location:myscorenum.php");
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "score";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
session_start();
if (isset($_SESSION['username'])){
$username = $_SESSION['username'];
echo "working";
}else{
//3.2 When the user visits the page first time, simple login form will be displayed.
}
$value = $_POST['name'];
$value1 = $_POST['description'];
$sql = "INSERT INTO all_scores (name, description) VALUES ('$value','$value1')";
if ($conn->query($sql) === TRUE) {
echo "<a href=https://twitter.com/angela_bradley>My Twitter</a>";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
ill have the processing to inset to another database in another file. I'm confident with uploading a specific session.
any questions don't hesitate to message me. thanks for your kind help.
You can use this:
mysqli::$insert_id -- mysqli_insert_id — Returns the auto generated id used in the last query
Like: echo $conn->insert_id;
Since you call it on $conn which is a mysqli instance that already has a connection, it will return your last inserted id, irregardless of other activities on the db (other queries do not affect the correctness of the output)
I edited my answer. This is the final part of your code and I've just added one line of code to it. Look if this is what you're looking for.
If this isn't working than make sure your database id field is AI.
if ($conn->query($sql) === TRUE) {
$id=$conn->insert_id; //this is where you get the last inserted id.
echo "<a href=https://twitter.com/angela_bradley>My Twitter</a>";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
To use a session and set the ->insert_id to a session variable and use it in any other page, you can do this:
if ($conn->query($sql) === TRUE) {
session_start();
$_SESSION['id']=$conn->insert_id;
echo "<a href=https://twitter.com/angela_bradley>My Twitter</a>";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
and now in any other page do this to retrieve the session variable:
session_start();
$id=$_SESSION['id'];
here you go and you get the id.
Are you still confused?
I am working on an academy website here at www.grmaedu.com
Web Specs: Built on Wordpress with the following plugins, Visual Form Builder Pro & Revolution Slider
So i have managed to do 90% of the work. My query is I want to assign automatic roll numbers to students who are submitting the application form here at www.grmaedu.com/application
Here are the remaining things I want to do:
Automatically assign Roll Number to students "after or on " form submission
Submit the form to the concerned mySql Database, Right now it emails correctly to the designated email address with no issues. All thanks to Visual Form Builder Pro
The date picker field is not working in the application form(I even updated my jQueryUI file)
I hope the provided details are enough for the solution.
I finally figured a way out. Here are the steps which i performed.
I installed a WP Plugin named Contact Form DB. This plugin saves all the form submitted values and stores them in a mySQL database.
I opened up phpmyadmin to see how it was stored and found it in one of the tables. I noticed that each entry had an unique id number. That is what I was trying to do. This plugin made it easier for me.
Then i created a Page template file name rollnumber.php and inserted the following code in
<?php
/* Define Connection properties */
$servername = "localhost";
$username = "grmaedu_wp2";
$password = "******";
$dbname = "grmaedu_wp2";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT entries_id FROM `wp_vfb_pro_entries` ORDER BY entries_id DESC LIMIT 1";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
$a = $row["entries_id"];
$a++;
echo "<h3>Your Roll Number assigned is: " . $a . "</h3>";
//echo "id: " . $row["entries_id"] . "<br>";
}
} else {
echo "0 results";
}
mysqli_close($conn);
?>
So now when the page loads it automatically fetches the unique id and adds 1 to the last submitted id and voila a new roll number is generated.
Index key is the best option to set as roll number. because it is unique and then you can get user data directly form this id.
<?php
/* Define Connection properties */
$servername = "localhost";
$username = "grmaedu_wp2";
$password = "******";
$dbname = "grmaedu_wp2";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT entries_id FROM `wp_vfb_pro_entries` ORDER BY entries_id DESC LIMIT 1";
$result = mysqli_query($conn, $sql);
echo "<h3>Your Roll Number assigned is: " . mysqli_insert_id() . "</h3>";
//echo "id: " . mysql_insert_id() . "<br>";
}
} else {
echo "0 results";
}
mysqli_close($conn);
?>