I have this HTML code:
<form action="index.php" method="post">
<input id="firstCheck" type="checkbox" name="test[]" value="first" checked>
<label for="firstCheck">1</label><br>
<input id="secondCheck" type="checkbox" name="test[]" value="second" checked>
<label for="secondCheck">2</label><br>
<input type="submit" name="test_submit" value="Send">
</form>
Also I have this PHP code:
function create_cookies()
{
if (isset($_POST['test_submit'])) {
$checkboxes_array = $_POST['test'];
setcookie("testcookie1234556", json_encode($checkboxes_array), time()+3600);
}
}
create_cookies();
function check_cookies()
{
if (isset($_COOKIE['testcookie1234556'])) {
$my_cookie_array = json_decode($_COOKIE['testcookie1234556']);
return $my_cookie_array;
} else {
return false;
}
}
check_cookies();
As you can see, I have got all checked checkboxes and stored it to the php cookie.
Now, when someone is logging to the system, all checkboxes is checked by default. But I need them to be checked or unchecked based on the info from php cookie!
I mean, for example, if user logged on to the system and unchecked some checkboxes, logged off, then logged in again, previously unchecked checkboxes must remains unchecked.
Please, give me some advices for doing it.
Put your cookie in an array say
$cookie_aray=check_cookies();
and check it every time you load a check box, whether it was selected or not.
<html><form action="abc.php" method="post">
<input id="firstCheck" type="checkbox" name="test[]" value="first" <?php if(in_array('first',$cookie_aray)) echo 'checked';?>>
<label for="firstCheck">1</label><br>
<input id="secondCheck" type="checkbox" name="test[]" value="second" <?php if(in_array('first',$cookie_aray)) echo 'checked';?>>
<label for="secondCheck">2</label><br>
<input type="submit" name="test_submit" value="Send">
Related
I have html checkbox like this:
<form action="" method="post">
<input type="checkbox" name="language[]" value="php" />PHP<br />
<input type="checkbox" name="language[]" value="html" />HTML<br />
<input type="checkbox" name="language[]" value="java" />Java<br />
<input type="checkbox" name="language[]" value="c++" />C++<br />
<input type="submit" value="send" />
</form>
Now I want to detect the checkbox is not checked using this PHP
if($_POST)
{
if(empty($_POST['language']))
{
echo "bla";
}
else
{
foreach($_POST['language'] as $value)
{
echo 'Checked: '.$value.'
';
}
}
}
The output is always show the checbox checked.
My question is, how can I detect the checkbox is not checked?
Example I do not check PHP and Java.
You don't need to validate checkbox by checkbox in order to determine if they are checked or not, you won't get the unchecked checkboxes values at the time you send the form, so, sending the form like this:
<form action="" method="post">
<input type="checkbox" name="language[]" value="php" />PHP<br /> <!-- checked -->
<input type="checkbox" name="language[]" value="html" />HTML<br /><!-- checked -->
<input type="checkbox" name="language[]" value="java" />Java<br /><!-- unchecked -->
<input type="checkbox" name="language[]" value="c++" />C++<br /><!-- unchecked -->
<input type="submit" value="send" />
</form>
In your PHP, you will get an array as follows:
$_POST['languages'] = array("php", "html");
Now, lets say you have an array of all the values in order to check which ones you need to delete, and which ones you need to add, a rough code example would be as follows:
$allValues = array('php', 'html', 'java', 'c++');
$valuesForAdd = $_POST['language'];
$valuesForDeletion = array_diff($allValues, $valuesForAdd);
First you need the selectable items array in the backend:
$items = array('php','html','java','c++');
You have the posted (selected) languages array here:
$_POST['language']
Not selected languages array:
$not_selected_languages = array_diff($items,$_POST['language']);
I hope it helps.
Only 'checked' checkboxes get sent as parameters in a POST request.
If you want to know which aren't checked, you could have the value list stored on PHP side; then once you receive POST data - compare the array on PHP side with POST array.
$all_vals = array('php', 'c++', 'html', 'java');
$post_vals = $_POST['languages'];
foreach ($post_vals as $post_val)
if in_array($post_val, $all_vals)
$checkbox checked
else
$checkbox not checked
I assume this gives you enough liberty to do what you need.
I have a problem with my form. I need it to redirect user to different pages basing on which radio button was selected. User has to choose one of two options and click next, and according to his choice, page should redirect him to other page.
Here is the code as it looks for now
<fieldset>
<legend>Select option</legend>
<center>
<form method="post" action="">
<input type="radio" name="radio1" value="Osoba fizyczna"/>Non-company
</br>
<input type="radio" name="radio2" value="Firma"/>Company
</br>
<input type = "submit", class = "buttonStyle2", value=""/>
</form>
</center>
</fieldset>
and then php code
if(isset($_POST['Company'])
header("Location: http://myaddress.com/company.php");
Big thanks in advance for your help
Here is one way to achieve this.
Sidenote: Make sure you're not outputting before header. Consult this page on Stack about possible Headers already sent..., should this occur and making sure error reporting is set/on.
Otherwise, PHP will fail silently.
if(isset($_POST['radio1']) && ($_POST['radio1']) == "Osoba fizyczna"){
header("Location: http://www.example.com/non_company.php");
}
elseif(isset($_POST['radio1']) && ($_POST['radio1']) == "Firma"){
header("Location: http://www.example.com/company.php");
}
else{
header("Location: http://www.example.com/redirect_to_home.php");
}
Nota: The else would be if the person did not make a choice and simply clicked on submit without making a selection.
while using radio buttons of the same group name in your form:
<input type="radio" name="radio1" value="Osoba fizyczna"/>Non-company
</br>
<input type="radio" name="radio1" value="Firma"/>Company
Note about
<input type = "submit", class = "buttonStyle2", value=""/>
remove the commas
<input type = "submit" class = "buttonStyle2" value=""/>
Since HTML source in FF will reveal No space between attributes in red/as an error.
<fieldset>
<legend>Select option</legend>
<center>
<form method="post" action="">
<input type="radio" name="radio1" value="Osoba fizyczna"/>Non-company
</br>
<input type="radio" name="radio1" value="Firma"/>Company
</br>
<input type = "submit" class = "buttonStyle2" value=""/>
</form>
</center>
</fieldset>
and
if ( isset($_POST['radio1']) ) {
$filename = $_POST['radio1'] . "php";
header("Location: http://myaddress.com/".$filename);
}
Might be even better to set up an array with allowed values and check if radio1 is in that array.
I have a input in a form
<form name="frmAdd" method="POST" action="/index.php?a=save">
Status : <input type="checkbox" id="status" name="chkActive" value="" ><label for="status">Active</label>
</form>
but when I am calling the value of it, via $_POST['chkActive'], it's giving same value on that page. Whether I have checked the value or not.
Please tell me how can I know that this checkbox is checked or not (in PHP).
If you are using just a single checkbox you can do this :
<input type="checkbox" id="status" name="chkActive" value="1" >
within PHP
if (isset($_POST['chkActive'])) {
//its checked
}
but you need to ensure there is a value set within the HTML
<form name="frmAdd" method="POST" action="/index.php?a=save">
Status : <input type="checkbox" id="status" name="chkActive" value="1" ><label for="status">Active</label>
</form>
<?php if($_POST['chkActive']=='1'){
echo "is Active";
}else{
echo "not Active";
}
Checkbox only passes the value if is checked.
to clarify how it works.
<input type="checkbox" id="status" name="chkActive"
if the checkbox not ticked (checked by user) nothing sent to server. "chkActive" will not exist. So we use isset() to check it.
I have a list of emails with a checkbox next to it, the user will be able to select which address he/she wants to email. Now i've added another checkbox that when checked will check all the other checkbox. Below is the code i wrote (with help from stackoverflow of course) :
<SCRIPT LANGUAGE="JavaScript">
function selectFunction (checkall,field)
{
if(checkall.checked==true){
for (i = 0; i < field.length; i++)
field[i].checked = true ;
}else{
for (i = 0; i < field.length; i++)
field[i].checked = false ;
}
}
</script>
<form name="myform" action="profile-invite.html" method="post">
<b>Your Favorite Scripts & Languages</b><br>
<input type="checkbox" name="list" value="1">aaa#xxx.com<br>
<input type="checkbox" name="list" value="2">bbb#xxx.com<br>
<input type="checkbox" name="list" value="3">ccc#xxx.com<br>
<input type="checkbox" name="list" value="4">ddd#xxx.com<br>
<input type="checkbox" name="list" value="5">eee#xxx.com<br>
<input type="checkbox" name="selectallcb" value="Check All"
onClick="selectFunction(document.myform.selectallcb,document.myform.list)">
<input type="submit" name="formSubmit" value="Submit" />
</form>
The "select all" function works fine, but using print_r i saw that when the submit button is clicked, the submited value is the last checkbox that i selected. For example if i click 5-3-1-2, the value in $_POST is "2" and not the rest.
i realized that my code can only register ONE selected checkbox, therefore only the last one is taken into account. So I rewrote the code by adding [] behind the name of the checkbox :
<form name="myform" action="profile-invite.html" method="post">
<b>Your Favorite Scripts & Languages</b><br>
<input type="checkbox" name="list[]" value="1">aaa#xxx.com<br>
<input type="checkbox" name="list[]" value="2">bbb#xxx.com<br>
<input type="checkbox" name="list[]" value="3">ccc#xxx.com<br>
<input type="checkbox" name="list[]" value="4">ddd#xxx.com<br>
<input type="checkbox" name="list[]" value="5">eee#xxx.com<br>
<input type="checkbox" name="selectallcb" value="Check All"
onClick="selectFunction(document.myform.selectallcb,document.myform.list)">
<input type="submit" name="formSubmit" value="Submit" />
</form>
Now, it registers the multiple selections when i checked with print_r.(if i click 5-3-1-2, the value in $_POST is now [0]=>5,[1]=>3,[2]=>1,[3]=>2.)
But the "select all" checkbox doesn't work anymore. I assume is due to the [] which transformed the field into an array. I tried various methods (by replacing "document.myform.list" with "document.myform.list[]" etc. ) None is working so far, i'll continue experimenting but if anybody have a clear idea on how to merge the 2 codes above please help.
Thank You
Change this:
onClick="selectFunction(document.myform.selectallcb,document.myform.list)"
to this:
onClick="selectFunction(document.myform.selectallcb,document.myform['list[]'])"
Here's the fiddle: http://jsfiddle.net/NxfH6/
How do I check a checkbox?
I've tried 1, On, and Yes. That doesn't work. Putting the worked "checked" alone works, but then how do I check with PHP after a form post of the checkbox is checked?
<input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" />
A checkbox will only be a successful control if it is checked.
Controls that are not successful are not submitted as data.
Therefore, you can tell if a checkbox is checked by seeing if its value has been submitted.
E.g.
if ($_POST['chk']['newmsg2'] == 1) {
<input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" <?php if ($_POST['chk']['newmsg2']): ?>checked="checked"<?php endif; ?> />
Here is the code;
<form action="test.php" method="POST">
<input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" />
<input type="submit">
</form>
<?php
$check = $_POST['chk']['newmsg2'];
echo "***$check****"
?>
If it is checked $check will show 1.