Find how many numbers are greater than N in an array - php

Question

If I have an indexed PHP array:
$array = array(2, 12, 23, 34, 36, 36, 36, 56);
And I have a variable:
$number = 30;
How do I calculate the number of "array positions" that are higher than $number?
For example, the function should return 5, because there are 5 numbers (34, 36, 36, 36 and 56) that are higher than 30.
Edit: I've already tried different methods of counting the array values, but I have no idea how to count the positions. It has me stumped.

Answer 1

Can also use
array_reduce — Iteratively reduce the array to a single value using a callback function
Example:
$array = array(2, 12, 23, 34, 36, 36, 36, 56);
$number = 30;
echo array_reduce($array, function($ret, $val) use ($number) {
return $ret += $val > $number;
});
Or hardcode the number into the callback
echo array_reduce($array, function($ret, $val) {
return $ret += $val > 30;
});

Answer 2

As another alternative, use array_filter() to remove the elements from the array that you don't want, then just count() the remaining list...
$array = array(2, 12, 23, 34, 36, 36, 36, 56);
$number = 30;
$gtn = array_filter($array, function($value) use ($number) { return $value > $number; });
echo count($gtn);
$gtn will contain the numbers (34, 36, 36, 36, 56), which may be useful for other things in your code.

Answer 3

You don't need to iterate the full array.
If you first sort the array then as soon as you find a larger number you can break the loop and use the key value from there.
$array = array(2, 12, 23, 34, 36, 36, 36, 56);
Sort($array);
$number = 30;
Foreach($array as $key => $val) If($val >= $number) break;
$larger = array_slice($array, $key);
Echo count($larger) . "\n";
Var_dump($larger);
Output:
5 //echo
array(5) { // var_dump
[0] => 34
[1] => 36
[2] => 36
[3] => 36
[4] => 56
}
https://3v4l.org/8FoOP

Answer 4

You can use array_reduce for this task:
$array = array(2, 12, 23, 34, 36, 36, 36, 56);
$number = 30;
$cnt = array_reduce($array, function ($carry, $item) use ($number) {
if ( $item > $number ) {
$carry++;
}
return $carry;
});
echo $cnt;

Answer 5

Try this code:
function findGreaterNumberCount($array, $number) {
$count = 0;
foreach ($array as $value) {
if ($value > $number) {
$count++;
}
}
return $count;
}
echo findGreaterNumberCount(array(2, 12, 23, 34, 36, 36, 36, 56), 30);
This platform doesn't recommend to write code. So you should try something before asking a question. Be careful next time.

Answer 6

use array reduce and make your code short
$array = [2, 12, 23, 34, 36, 36, 36, 56];
$number = 30;
$totalNumberOfItems = array_reduce($array, function ($sum, $item) use ($number) {
if($item > $number)
$sum++;
return $sum;
});
Var_dump($cnt);

Answer 7

You can iterate array with array_filter to find the greatest array element.
$num = 30;
$array = array(2, 12, 23, 34, 36, 36, 36, 56);
$a = array_filter($array, function($value) use( $num ){
return $num < $value;
});
print_r($a);
Out put
Array
(
[3] => 34
[4] => 36
[5] => 36
[6] => 36
[7] => 56
)