I get a string in PHP from an external database which looks like this:
$myStr = '<br>To send a note'
As you can see this string is encoded too many times, is there is a way to decode it all the way back using PHP?
What happened that your str passed lots of times through htmlentities().
The original string probably was <br>To send a note, then, the 1st time it become <br>To send a note, the secong it replace all & with & and so on.
In order to put it inside text area you should to decode it using:
<textarea><?php echo html_entity_decode($myStr); ?></textarea>
The code bellow will pass as many times it's necessary to solve your issue:
$modStr = $myStr = '&amp;amp;amp;amp;amp;lt;br&amp;amp;amp;amp;amp;gt;To send a note';
do {
$myStr = $modStr;
$modStr = html_entity_decode($myStr);
} while( $modStr != $myStr );
[]s Andrei
When "descriptions" field has "enter" (newline) API is failing.
Image to check all parameter sent by users
Below code to get the data from posted JSON.
// get posted data
$jason_value = json_decode(file_get_contents("php://input"));
$crm_id = $jason_value->data->crmId;
$descriptions = $jason_value->data->descriptions;
I would like to accept descriptions as a string one line.
descriptions = "10+ windows modern style 7057655959".
I do not have access to the program where the user enters the description where I can add validation and convert it to \n.
Getting below string after conversion
{ "jwt": "eyJ0", "data": { "crmId": "15876047", "geoconceptAppointmentId": "15876","geoconceptCustomerId": "15876047","status": "Rejected","appointmentDateTime": "","firstName": "Nick Test","lastName": "PA","address": "9112 RUE Tom","city": "MONTREAL","state": "QC","zip": "H2N1T1","country": "CAN","phoneNumber1": "5148332222","phoneNumber2": "5148332222","email": "nbskgg#gmail.com","dateEntry": "2019-06-20 12:02","dateModify": "2019-06-20 12:02","preferredWayToContact": "","textMsgFlag": "Y","hearAboutUs": "Referral","perferredTime": "Anytime","descriptions": "I have to call at 5" pm. ","worklog": "This is the comment ","rejectReason": "Area | Region","referredByDC": "09999","referredByStoreUsername": "store215","assignedUsername": "","createdByUsername": "np","modifiedByUsername": "np","btgMarket": "Montreal"}}
You're correct that in PHP7+, a literal tab or newline is going to cause the json parsing to fail. file_get_contents("php://input") returns a single string so I see no reason why you couldn't just filter that before you attempt to parse it. But maybe I'm missing something.
//Catch Unix OR DOS line endings, but not both
$filter = Array("\n","\n\r");
$replace = " ";
$cleanJSON = str_replace($filter, $replace, file_get_contents("php://input");
$data = json_decode($cleanJSON));
I want to point out that after this point, your code is referencing a variable that does not exist: $jason_value
$crm_id = $jason_value->data->crmId;
$descriptions = $jason_value->data->descriptions;
To reference properties of the object you just created, go directly to $data:
$crm_id = $data->crmId;
$descriptions = $data->descriptions;
I expect that you'd want to replace the newline with a space but you may just want an empty string if what you're actually encountering has a space before the newline but that's impossible to tell from what we have.
I have the following PHP code (I'll post the important part of it):
// objID
$objects->objID = generateRandomID();
$objects->pointer = array('type'=>'__pointer','objID'=>'dgFg45dG','className'=>'Users');
$jsonStr = file_get_contents($className.'.json'); // This calls a Users.json file stored in my server
$jsonObjs = json_decode($jsonStr, true);
...
$jsonStr = file_get_contents($className.'.json'); // This calls a Users.json file stored in my server
$jsonObjs = json_decode($jsonStr, true);
array_push($jsonObjs, $objects);
// Encode the array back into a JSON string and save it.
$jsonData = json_encode($jsonObjs);
file_put_contents($className.'.json', $jsonData);
// echo JSON data
echo $jsonData;
// ISSUE HERE :(
$jsonStr = file_get_contents($className.'.json');
// Decode the JSON string into a PHP array.
$jsonObjs = json_decode($jsonStr, true);
foreach($jsonObjs as $i=>$obj) {
print_r('<br><br>'.$i.'-- ');
echo
$obj['objID'].', <br>'
.$obj['pointer']["$i"]['objID']. ', '
.$obj['pointer']["$i"]['type']. ', '
.$obj['pointer']["$i"]['className']. '<br><br>'
;
}
// ./ ISSUE
The code above creates a new JSON object into my own Users.json file.
So, when I call this PHP file with a URL string in my browser, just as a test, and I refresh the page a few times, I get the following echo:
0-- VUDjCZX8QX, , ,
1-- 1uWH17OoJP, , ,
[{"objID":"VUDjCZX8QX","pointer":{"type":"__pointer","objID":"dgFg45dG","className":"Users"},"string":"mark","createdOn":"2018-09-17 05:36:49","updatedOn":"2018-09-17 05:36:49","number":111,"boolean":true,"array":["john","sarah"]},{"objID":"1uWH17OoJP","pointer":{"type":"__pointer","objID":"dgFg45dG","className":"Users"},"string":"mark","createdOn":"2018-09-17 05:36:51","updatedOn":"2018-09-17 05:36:51","number":111,"boolean":true,"array":["john","sarah"]},{"objID":"RkubyQPvqR","pointer":{"type":"__pointer","objID":"dgFg45dG","className":"Users"},"string":"mark","createdOn":"2018-09-17 05:36:54","updatedOn":"2018-09-17 05:36:54","number":111,"boolean":true,"array":["john","sarah"]}]
So, what I need to fix is basically the following:
What's the right code to properly get the list of items of the
"pointer" object that's inside each object of my Users.json file?
I try to track the index of my foreach loop, but it doesn't work properly as you can see by the echo posted above when I first execute my PHP code, I get the JSON string of my 1st object, I don't get any print_r(). Then, when I refresh the page a 2nd time, I get the print of the objID string of my 1st object, and again, if I refresh the page a 3rd time, I get the objID of my 2nd object, while there are 3 objects stored in my json file. And so on, in other words, I never get the first object's print info.
What am I doing wrong?
You are passing $i as a string, not as a variable. Use double quotes (") or remove single quotes (') to pass as a variable. This will solve your issue, pointer objects not printing properly.
$obj['pointer'][$i]['objID']
Update
[{"objID":"VUDjCZX8QX","pointer":{"type":"__pointer","objID":"dgFg45dG","className":"Users"},"string":"mark","createdOn":"2018-09-17 05:36:49","updatedOn":"2018-09-17 05:36:49","number":111,"boolean":true,"array":["john","sarah"]},{"objID":"1uWH17OoJP","pointer":{"type":"__pointer","objID":"dgFg45dG","className":"Users"},"string":"mark","createdOn":"2018-09-17 05:36:51","updatedOn":"2018-09-17 05:36:51","number":111,"boolean":true,"array":["john","sarah"]},{"objID":"RkubyQPvqR","pointer":{"type":"__pointer","objID":"dgFg45dG","className":"Users"},"string":"mark","createdOn":"2018-09-17 05:36:54","updatedOn":"2018-09-17 05:36:54","number":111,"boolean":true,"array":["john","sarah"]}]
According to above JSON string, you don't need specify $i.
$obj['pointer']['objID'] should work, since it is associate array.
Thanks to #saumini-navaratnam, I have to use the following foreach:
foreach($jsonObjs as $i=>$obj) {
print_r('<br><br>'.$i.'-- ');
echo
$obj['objID'].', '
.$obj['pointer']['objID']. ', '
.$obj['pointer']['type']. ', '
.$obj['pointer']['className']. '<br><br>'
;
}
In this way, I can properly get the objects of this object:
{"pointer":{"type":"__pointer","objID":"dgFg45dG","className":"Users"}
In fact, here's the echo I get:
[
{"objID":"pkO8NesS5S","pointer":{"type":"__pointer","objID":"dgFg45dG","className":"Users"},"string":"bobby","createdOn":"2018-09-17 07:03:27","updatedOn":"2018-09-17 07:03:27","number":111,"boolean":true,"array":["john","sarah"]},
{"objID":"rdwJl20krC","pointer":{"type":"__pointer","objID":"dgFg45dG","className":"Users"},"string":"bobby","createdOn":"2018-09-17 07:03:31","updatedOn":"2018-09-17 07:03:31","number":111,"boolean":true,"array":["john","sarah"]},
{"objID":"3WspzmuwMK","pointer":{"type":"__pointer","objID":"dgFg45dG","className":"Users"},"string":"bobby","createdOn":"2018-09-17 07:07:39","updatedOn":"2018-09-17 07:07:39","number":111,"boolean":true,"array":["john","sarah"]}
]
0-- pkO8NesS5S, dgFg45dG, __pointer, Users
1-- rdwJl20krC, dgFg45dG, __pointer, Users
2-- 3WspzmuwMK, dgFg45dG, __pointer, Users
I am making a price crawler for a project but am running into a bit of an issue. I am using the below code to extract values from an html page:
$content = file_get_contents($_POST['url']);
$resultsArray = array();
$sqlresult = array();
$priceElement = explode( '<div>value I want to extract</div>' , $content );
Now when I use this to get certain elements I only get back
Finance: {{value * value2}}
I want to get the actual value that would be displayed on the screen e.g
Finance: 7.96
The other php methods I have tried are:
curl
file_get_html(using simple_html_dom library)
None of these work either :( Any ideas what I can do?
You just set the <div>value I want to extract</div> as a delimiter, which means PHP looks for it to separate your string to array whenever this occurs.
In the following code we use , character as a delimiter:
<?php
$string = "apple,banana,lemon";
$array = explode(',', $string);
echo $array[1];
?>
The output should be this:
banana
In your example you set the value you want to extract as a delimiter. That's why this happens to you. You'll need to set a delimiter between your string you want to obtain and other string you won't need at the moment.
For example:
<?php
$string = "iDontNeedThis-dontExtractNow-value I want to extract-dontNeedEither";
$priceElement = explode('-', $string);
echo "<div>".$priceElement[2]."</div>";
?>
The code should output this to your HTML page:
<div>value I want to extract</div>
And it will appear on your page like this:
value I want to extract
If you don't need to save the whole array in a variable, you can save the one index of it to variable instead:
$priceElement = explode('-', $string)[2];
echo $priceElement;
This will save only value I want to extract so you won't have to deal with arrays later on.
So I got a HTML page with a button. When I click the button, a separate javascript file sends a GET request to my PHP file, expecting a JSON object in return. My PHP reads a JSON formatted text file and should convert it into a JSONObject and echo it out for my javascipt. I had some code working before, but it doesn't seem to do it anymore since I changed to a Ajax aproach instead of having everything in the same file. This is my code:
readLog.php
<?php
class test{
function clean($string){
return json_decode(rtrim(trim($string),','),true);
}
function getLog(){
header('Content-Type: application/json');
$logLines = file('../../../home/shares/flower_hum/humid.log');
$entries = array_map("clean",$logLines);
$finalOutput = ['log' => $entries];
echo json_encode($logLines);
}
}
?>
My humid.log file looks like this:
{"date":"26/09/2016", "time":"22:40:46","temp":"16.0", "humidity":"71.0" }
{"date":"26/09/2016", "time":"23:10:47","temp":"16.0", "humidity":"71.0" }
Now If I press my button, this is the response I get checking the console in my web browser:
Response:
["{\"date\":\"26\/09\/2016\", \"time\":\"22:40:46\",\"temp\":\"16.0\", \"humidity\":\"71.0\" }{\"date\":\"26\/09\/2016\", \"time\":\"23:10:47\",\"temp\":\"16.0\", \"humidity\":\"71.0\" }\n"]
JSON:
"{"date":"26/09/2016", "time":"22:40:46","temp":"16.0", "humidity":"71.0" }{"date":"26/09/2016", "time":"23:10:47","temp":"16.0", "humidity":"71.0" }\n"
obviously something is wrong with the formatting, but I don't know what. As I said, this code worked just fine when I had my php and HTML in the same file.
EDIT:
I have also tried formatting the JSON with something like this, but it just prints the brackets:
function getLog(){
$text = file('../../../home/shares/flower_hum/humid.log');
$textRemoved ="["; //Add opening bracket.
$textRemoved .= substr($text, 0, strlen($text)-1); (Remove last comma)
$textRemoved .="]";//Add closing bracket
$json = json_encode($textRemoved);
echo $json;
}
So I managed to solve it myself. Basicly The formatting of the textfile was wrong and as some commentors said, I don't need to encode it if I am doing it myself. What I ended up doing was in my application that generates the log file to add comma after each row. Then in my PHP I added brackets and removed the last comma.
function getLog(){
header('Content-Type: application/json');
$file = file_get_contents('../../../home/shares/flower_hum/humid.log');
$lengthOfFile = strlen($file)-2;
$subFile = substr($file, 0, $lengthOfFile);
$res ="[";
$res .= $subFile;
$res .="]";
echo $res;
}
You can't just jam two+ JSON strings togther. It's JSON, which means it HAS to be syntactically correct Javascript CODE. If you want to join two json strings together, you HAVE to decode them to a native data structure, join those structures together, then re-encode the new merged structure:
$temp1 = json_decode('{"foo":"bar"}', true);
$temp2 = json_decode('{"baz":"qux"}', true);
$new = array_merge($temp1, $temp2);
echo json_encode($new);
which will produce:
{"foo":"bar","baz":"qux"}
and remain valid JSON/Javascript.
Why? Consider that bare integers are valid json:
json_encode(42) -> 42
json_encode(123) -> 123
If you have two json-encoded integers and jam together, you get a "new" integer:
42123
and on the receiving end, you'll be going "Ok, so where is the split between the two", because 4 and 2123 are just as valid as possible original values as 4212 and 3.
Sending the two integers as distinct and SEPARATABLE values would require an array:
[42,123]