php array to json sting conversion - php

Hi every one i am pretty new to programming and my worry is as follows.
I have the following php code where students' averages are calculated and the result filled in an asssociative array. This array should later on be converted to json format.
require_once("functions.inc"); // all my functions are here
$conn = mysqli_connect(DBHOST,DBUSER,DBPASS,DB); // connects to my database
if (!$conn) {
error_log("Cannot connect to MySQL: " .$mysqli->connect_error);
return false;
}
$query = "SELECT distinct exam.student_matricule from exam join student on exam.student_matricule=student.student_matricule where student.class_id=3"; //
$result=mysqli_query($conn,$query);
if(false===$result)
{
printf("error: %s \n",mysqli_error($conn));
}
while($row= $result->fetch_assoc())
{
$studentmatricule = $row['student_matricule'];
$average=student_average(3,$studentmatricule,1); // this function call calculates students' averages
$stud_averages[$studentmatricule]=$average; //associative array that has **$studentmatricule** as key and **$average** as value
}
foreach($stud_averages as $student => $av)
{
$data=array('student_matricule'=>"$student",'average'=>"$av");
print json_encode($data);
}
My worry now is, print json_encode($data) prints
{"student_matricule":"17A002NA","average":"12.52"}{"student_matricule":"17A001NA","average":"10.53"}{"student_matricule":"17A003NA","average":"12.69"}
But i want something like
[{"student_matricule":"17A002NA","average":"12.52"},{"student_matricule":"17A001NA","average":"10.53"},{"student_matricule":"17A003NA","average":"12.69"}]
Please what should i do?
Thanks in advance!

You're printing single dimensional Array inside loop so it is printing as a JSON
If you want it as a JSON array you need to store it in a multidimensional array like this
$data = [];
foreach($stud_averages as $student => $av)
{
$data[]=array('student_matricule'=>"$student",'average'=>"$av");
}
print json_encode($data); // It prints JSON Array

You are printing every array seperately in foreach loop. You need to add every loop data in a array that defined outside the loop. You can try like this :
$res = array();
foreach($stud_averages as $student => $av)
{
$data=array('student_matricule'=>"$student",'average'=>"$av");
array_push($res, $data);
}
print json_encode($res);

you can also try like this
$data = [];
$std = array();
foreach($stud_averages as $student => $av)
{
$std['student_matricule']= "$student";
$std['average'] ="$av";
}
array_push($data,$std);
print json_encode($data); // It prints JSON Array

Related

PHP invalid JSON encoding

I'm trying to GET a JSON format back when I POST a specific ID to my database. As I get more than one result I have multiple rows, which I want to get back. I do get different arrays back, but it is not a valid JSON Format. Instead of
[{...},{...},{...}]
it comes back as
{...}{...}{...}
Therefore the [...] are missing and the arrays are not separated by commas.
My code is down below. The function "getUserBookingsKl" is defined in a different php.
//get user bookings
public function getUserBookingsKl($id) {
//sql command
$sql = "SELECT * FROM `***` WHERE `hf_id`=$id AND `alloc_to`>DATE(NOW()) AND NOT `confirmation`=0000-00-00 ORDER BY `alloc_from`";
//assign result we got from $sql to $result var
$result = $this->conn->query($sql);
// at least one result
if ($result !=null && (mysqli_num_rows($result) >= 1 ))
{
while ($row = $result->fetch_array())
{
$returArray[] = $row;
}
}
return $returArray;
}
...
...
foreach($userdb as $dataset)
{
$returnArray["group"] = $dataset["kf_id"];
$returnArray["from"] = $dataset["alloc_from"];
$returnArray["to"] = $dataset["alloc_to"];
echo json_encode($returnArray);
# return;
}
// Close connection after registration
$access->disconnect();
It looks like you're sequentially emitting the values, not pushing into an array. You need to make an array, push into it, then call json_encode on the resulting structure:
$final = [ ];
foreach ($userdb as $dataset)
{
$returnArray = [ ];
$returnArray["group"] = $dataset["kf_id"];
$returnArray["from"] = $dataset["alloc_from"];
$returnArray["to"] = $dataset["alloc_to"];
$final[] = $returnArray;
}
echo json_encode($final);
Note that it's important here to not use the same variable inside the loop each time through or you're just pushing the same array in multiple times.

Concatenate JSON in php with read Database

I read user from the database but I return json to ajax only return the last user because I cant concatenate the json encode.
$myObj = new \stdClass();
while ($fila = $bd->fila()) {
$myObj->NOMBRE = $fila["NOMBRE"];
$myObj->ROLENAME = $fila["ROLENAME"];
$myObj->IDUSER = $fila["IDUSER"];
$myJSON = json_encode($myObj);
}
echo $myJSON;
You are now overwriting $myJson in each iteration. We can also not "concatanate" two jsons (well, we could, but we shouldn't, cause it's laborious..).
Better put everything in one array/object and json_encode() at the very end.
$myObj = new \stdClass();
$users = array(); // instantiate a new array
while ($fila = $bd->fila()) {
$myObj->NOMBRE = $fila["NOMBRE"];
$myObj->ROLENAME = $fila["ROLENAME"];
$myObj->IDUSER = $fila["IDUSER"];
// add objects to that array
$users[] = $myObj;
}
// then at the end encode the whole thing to json:
echo json_encode($users);
Now here are some variants:
If you want everything that your db is returning in this items you could shorten that to:
$users = array(); // instantiate a new array
while ($fila = $bd->fila()) {
// add the whole item (cast as Object) to that array
$users[] = (Object) $fila;
}
// then at the end encode the whole thing to json:
echo json_encode($users);
If you don't care if the items are objects or arrays you could skip the casting and just add the array to the big array:
$users[] = $fila;
Maybe if you concatenate it as array like this
$myJSON[] = $myObj;
and then after the while
echo json_encode($myJSON);
You just have to collect data to big array and then encode whole array. Also there's no reason for creating new StdObjects instead of usual arrays.
// define empty array
$result = [];
while ($fila = $bd->fila()) {
// add to the array all needed elements one by one
$result[] = [
'NOMBRE' => $fila["NOMBRE"],
'ROLENAME' => $fila["ROLENAME"],
'IDUSER' => $fila["IDUSER"],
];
}
// encode whole result
echo json_encode($result);

json_enode() returns array of objects for singular values

The below code has only array like ["a","b","c"] but returns [Object,Object,Object]. The result of which I need to use nested $each loop in ajax success function. Is there any better way to do it?
if($_GET['semValue'])
{
$sem_value = $_GET['semValue'];
try
{
$stmt = $dbConn->prepare("SELECT Semester FROM CourseInfo");
$semArray = array();
if ($stmt->execute())
{
while ($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
$semArray[] = $row;
}
}
echo json_encode($semArray);
exit();
}
catch(PDOException $e)
{
echo 'Exception -> ';
var_dump($e->getMessage());
}
You're inserting entire row in main array so it will return multidimensional array instead of array of string.
To get the array of string replace the following lines.
while ($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
$semArray[] = $row["Semester"];
}
Explanation:
$row would be like this,
$row= Array("semester"=>1);
$row= Array("semester"=>2);
// And so on
If you follow your current code then your final array would be like this,
$semArray = Array ( [0]=> Array("semester"=>1), [1]=> Array("semester"=>2));
So it becomes multidimensional array, that's why we use $row["Semester"] to make it single dimensional array of string/integer values.

Need proper json response

I need json response in different array, but below code not give all the result.
while ($row=mysqli_fetch_assoc($result))
{
//$data[]=$row;
$data['id']=$row['id'];
$data['name']=$row['name'];
$data['Latitude']=$row['Latitude'];
$data['Longitude']=$row['Latitude'];
$lat_user=$row['Latitude'];
$long_user=$row['Longitude'];
$res=file_get_contents("https://maps.googleapis.com/maps/api/distancematrix/json".
"?units=imperial&origins=$lat,$long&destinations=$latuser,$longuser");
$json_res=json_decode($res);
$data['time']=$json_res->{'rows'}{0}->{'elements'}{0}->{'duration'}->{'text'};
}
echo json_encode($data,true);
You need to save your items into some array, e.g $dataArray at the end of each iteration and after cycle use this array to create json
$dataArray = array();
while ($row=mysqli_fetch_assoc($result))
{
//$data[]=$row;
$data['id']=$row['id'];
$data['name']=$row['name'];
$data['Latitude']=$row['Latitude'];
$data['Longitude']=$row['Latitude'];
$lat_user=$row['Latitude'];
$long_user=$row['Longitude'];
$res=file_get_contents("https://maps.googleapis.com/maps/api/distancematrix/json".
"?units=imperial&origins=$lat,$long&destinations=$latuser,$longuser");
$json_res=json_decode($res);
$data['time']=$json_res->{'rows'}{0}->{'elements'}{0}->{'duration'}->{'text'};
$dataArray[] = $data;
}
echo json_encode($dataArray,true);

how to add extra element to array with array_push in PHP?

I am developing in PHP/MS SQL for getting JSON Response.
Code which I wrote is:
while( $result = sqlsrv_fetch_object($sql_Gpo_Carr)) {
$array_res[] = $result; // add result to array
array_push($array_res, array('unidad' => $uni)); // add extra element
$jsonObj = json_encode($array_res); // encode JSON
}
echo $jsonObj;
exit();
This is what I want in result:
[{"idperiodo":"37","idgrupo":"1963","idhorario":"12832","unidades":null,"unidad":1}]
but the result shows me this:
[{"idperiodo":"37","idgrupo":"1963","idhorario":"12832","unidades":null},{"unidad":1}]
You're fetching an object. Add $uni to $result first and then add to $array_res:
while( $result = sqlsrv_fetch_object($sql_Gpo_Carr)) {
$result->unidad = $uni;
$array_res[] = $result;
}
Also, you probably want the json_encode() after the loop not in the loop:
echo json_encode($array_res);

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