how to echo out every item in table using PDO? - php

Question

I want to echo everything from table that matched the criteria, currently it should be 3 rows that match, but it echoes out only 1.
public function fetchInventoryItems($user_id)
{
try
{
$stmt = $this->db->prepare("SELECT * FROM items WHERE item_owner=?
AND inventory=?");
$stmt->execute([$user_id,'1']);
if ($stmt->rowCount() > 0)
{
while($userRows = $stmt->fetch(PDO::FETCH_ASSOC))
{
$itemId = $userRows['item_id'];
$stmt = $this->db->prepare("SELECT * FROM items_db WHERE
item_id=?");
$stmt->execute([$itemId]);
while($itemRows = $stmt->fetch(PDO::FETCH_ASSOC))
{
echo '<div class="dragcontainer inventory" ><div
id="'.$itemRows['item_id'].'" class="item '.$itemRows['item_type'].'"
style="background-image:url('.$itemRows['item_icon'].')" draggable="true">
</div></div>';
}
}
}
}
catch(PDOException $e)
{
echo $e->getMessage();
}
}
first fetch should retrieve 3 rows but the while loop only cycles once.
i guess it has something to do with PDO but i dont know what exactly

Answer 1

In the line...
$stmt = $this->db->prepare("SELECT * FROM items_db WHERE item_id=?");
Your overwriting the use of $stmt in the outer loop. Change this and any uses of this version to something else ($stmt1 would do)...
$stmt1= $this->db->prepare("SELECT * FROM items_db WHERE item_id=?");
You could rework both these SQL queries into 1 SQL statement, which would reduce the overhead and stop this sort of issue.