How to fix it? i was get error - php

Question

[29-Jul-2018 21:05:03 UTC] PHP Notice: Undefined variable: statusCode in /home2/postgram/public_html/app/vendor/mgp25/instagram-php/src/Utils.php on line 361
[29-Jul-2018 21:05:04 UTC] PHP Notice: Undefined variable: statusCode in /home2/postgram/public_html/app/vendor/mgp25/instagram-php/src/Utils.php on line 361
[29-Jul-2018 21:07:23 UTC] PHP Notice: Undefined variable: statusCode in /home2/postgram/public_html/app/vendor/mgp25/instagram-php/src/Utils.php on line 361
[29-Jul-2018 21:07:24 UTC] PHP Notice: Undefined variable: statusCode in /home2/postgram/public_html/app/vendor/mgp25/instagram-php/src/Utils.php on line 361
how to fix it?
this sc
https://raw.githubusercontent.com/mgp25/Instagram-API/master/src/Utils.php

Answer 1

Code of function is:
public static function checkFFPROBE()
{
// We only resolve this once per session and then cache the result.
if (self::$ffprobeBin === null) {
#exec('ffprobe -version 2>&1', $output, $statusCode);
if ($statusCode === 0) { // <-- line nr 361
self::$ffprobeBin = 'ffprobe';
} else {
self::$ffprobeBin = false; // Nothing found!
}
}
return self::$ffprobeBin;
}
You dont get error, it is just a php notice.
exec() as 3rd argument return status of the executed command (see more exec )
I think, you can resolve it in 3 ways:
Declare $statusCode just before 361 line ( e.g. $statusCode = null; )
Change exec() to shell_exec() ( see more shell_exec )
You can ignore php notices by setting error reporting level error_reporting( E_ALL & ~E_NOTICE );