I am using Laravel to fetch records from the database for which I have created an apiResource controller. I have setup the following code inside routes.
Route::apiResource('/MyController',MyController::class)->middleware('auth:api');
In MyController.php my code to display a specific data is:
/**
* Display the specified resource.
*
* #param \App\Models\ContentType $contentType
* #return \Illuminate\Http\Response
*/
public function show(MyModel $Model)
{
// show content type info
return response([
'data' => new MyControllerResource($Model)
],200);
}
I get the data when I place an api call like this:
http://localhost:8000/api/MyController/1
What I want is a record getting fetched by passing other field value instead of id in the route. For example.
http://localhost:8000/api/MyController/mypost
Any idea how can I achieve this?
The route key name defaults to id for all models. You will want to update this to name or whatever field "mypost" is by adding a getRouteKeyName() method.
<?php
namespace App;
...
class Post extends Model
{
public function getRouteKeyName()
{
return 'name';
}
...
}
You are using route model binding. And in laravel its default behaviour is to find model with id and return collection. It will not search for any other field. Of course you can change this behaviour but it can only search data by one field. To change this behaviour use getRouteKeyName method in model like:
public function getRouteKeyName()
{
return 'another_field_in_my_table';
}
You can also use explicit binding like:
Route::bind('MyController', function($value) {
return \App\MyModel::where('id', $value)->orWhere('another_field_in_my_table', $value)->first();
});
To learn more about explicit binding check docs.
You'll have to define route separately. You can group the routes by controller and middleware though. And once done, then, Inside your route, you need to change to this:
Route::get('/show/{post:columnName}', [ MyController::class, 'show' ])->middleware('auth:api');
Now your data will be fetched on the basis of your column name defined in the route.
I have added a custom primary key within the table and now the Laravel is not even finding the result at all. giving error that the page could not be found.
NotFoundHttpException
No query results for model [App\usersinformation].
Controller --------------------
public function show(usersinformation $usersinformation)
{
//
// $users = $user = usersinformation::where('user-id','=',$usersinformation) -> first();
return view('usersinformation.show');
}
Model -------------------
class usersinformation extends Model
{
//
public $table = "usersinformation";
public $incrementing = false;
protected $fillable = [
'fname','lname', 'user-picture', 'phone-number', 'user-id', 'place-id'
];
protected $primaryKey = 'user-info-id';
public function users(){
$this -> belongsTo('App\users');
}
route ---- web.php
Route::post('/show','App\Http\Controllers\usersinformationController#show');
Still facing the same issue, if I comment the primary key, it will give error that the id field is not found within the table when I add the custom primary key in the model, it will give error page not found.
You're typehinting usersinformation $usersinformation, so it's trying to find the record for the ID you're passing in. In the next line, you're trying to pass the id into the user-id, so I'm guessing you're actually passing in the user-id to the route, and not the id of the user information row. If that is the case, then you need to change the typehinting so it won't try to find the record before it enters the function.
public function show($user_id)
{
$user_information = usersinformation::where('user-id','=',$user_id) -> first();
return view('usersinformation.show', ['userinformation' => $user_information]);
}
Your primaryKey line is fine and should work, but know that dashes in table and column names are strongly discouraged because it leads to all sorts of confusion. Underscores are much better. See this link for more information.
I have this route:
Route::get('subscribers/{subscriber}', 'SubscriberController#show');
In my controller's show method, I want it to use the email as a lookup to my table instead of the default id. Is this possible?
public function show(Subscriber $subscriber)
{
// I need this to do like
// $subscriber = Subscriber::findOrFail(<email>);
//
// instead of the default
// $subscriber = Subscriber::finaOrFail(<id>);
return $subscriber;
}
I tried to look for an answer here in StackOverflow but my limited knowledge about Laravel does not seem to allow me to use the right keywords.
Add the following method to your Subscriber Model.
public function getRouteKeyName()
{
return 'email';
}
You can read more about Route Model Binding in the Laravel Documentation.
I am trying to make a one-to-many relationship, but I get the following error
Undefined property: stdClass::$client (View:
C:\wamp\www\intranet\resources\views\users\list.blade.php)
The problem is that I am working with an existing database that in the tables does not have id fields, and the foreign keys would also be the typical ones like client_id
My model Client.php
class Client extends Model
{
protected $connection = 'dpnmwin';
protected $table = 'nmundfunc';
public function employee(){
return $this->hasMany('App\Employee');
}
}
My model Employee.php
class Employee extends Model
{
protected $connection = 'dpnmwin';
protected $table = 'nmtrabajador';
public function client(){
return $this->belongsTo('App\Client', 'COD_UND');
}
}
In nmtrabajador COD_UND field would be the foreign key that relates to nmundfunc.
And I try to get the data out like this: {{$user->client->CEN_DESCRI}}.
but it does not throw me the error, how can I solve it?
My Controller where I send in sight
public function index(){
$users = DB::connection('dpnmwin')->table('nmtrabajador')->where('CONDICION', '=', 'A')->get();
return view('users.list',array(
'users' => $users
));
}
You have to call basis on relations.
This code will return you data.
If you have id then you can find by id like below
$employee=Employee::find(1);
Or if you want to fetch all data then you can call all method.
Employee::all();
And then you can just get it by relation as you define in models.
$client=$employee->client->CEN_DESCRI;
Retrieving data from the instance is based on the methods which we have use.
Here in this answer, you can get that
Property [title] does not exist on this collection instance
I hope it will work.
If table doesn't have 'id' as primary key you should specify what the primary key is inside your model:
protected $primaryKey = 'your_primary_key';
Relation looks good, after that you must make sure $user is a defined instance of Employee, because your error probably means that your instance wasn't even defined, so for example if you are using list.blade.php, you need to change the return of your controller and indicate that you want to pass data to your view, for example you could do it like this:
return view('users.list', compact('user'));
Where user is an instance of Employee saved on '$user'
Update
First you should check your user is retrieved properly, you can check it by placing a dd($user)
And when you return a view you can pass information to it, a cleaner way of doing what you are trying to do is what I wrote earlier so you would end up having something like this:
public function index()
{
$users = DB::table('nmtrabajador')
->where('CONDICION', '=', 'A')
->get();
// dd($user) for debugging you are retrieving the user properly
return view('users.list', compact($users));
}
I have two tables, User and Post. One User can have many posts and one post belongs to only one user.
In my User model I have a hasMany relation...
public function post(){
return $this->hasmany('post');
}
And in my post model I have a belongsTo relation...
public function user(){
return $this->belongsTo('user');
}
Now I want to join these two tables using Eloquent with() but want specific columns from the second table. I know I can use the Query Builder but I don't want to.
When in the Post model I write...
public function getAllPosts() {
return Post::with('user')->get();
}
It runs the following queries...
select * from `posts`
select * from `users` where `users`.`id` in (<1>, <2>)
But what I want is...
select * from `posts`
select id,username from `users` where `users`.`id` in (<1>, <2>)
When I use...
Post::with('user')->get(array('columns'....));
It only returns the column from the first table. I want specific columns using with() from the second table. How can I do that?
Well I found the solution. It can be done one by passing a closure function in with() as second index of array like
Post::query()
->with(['user' => function ($query) {
$query->select('id', 'username');
}])
->get()
It will only select id and username from other table. I hope this will help others.
Remember that the primary key (id in this case) needs to be the first param in the
$query->select() to actually retrieve the necessary results.*
You can do it like this since Laravel 5.5:
Post::with('user:id,username')->get();
Care for the id field and foreign keys as stated in the docs:
When using this feature, you should always include the id column and
any relevant foreign key columns in the list of columns you wish to
retrieve.
For example, if the user belongs to a team and has a team_id as a foreign key column, then $post->user->team is empty if you don't specifiy team_id
Post::with('user:id,username,team_id')->get();
Also, if the user belongs to the post (i.e. there is a column post_id in the users table), then you need to specify it like this:
Post::with('user:id,username,post_id')->get();
Otherwise $post->user will be empty.
For loading models with specific column, though not eager loading, you could:
In your Post model
public function user()
{
return $this->belongsTo('User')->select(['id', 'username']);
}
Original credit goes to Laravel Eager Loading - Load only specific columns
When going the other way (hasMany):
User::with(['post'=>function($query){
$query->select('id','user_id');
}])->get();
Don't forget to include the foreign key (assuming it is user_id in this example) to resolve the relationship, otherwise you'll get zero results for your relation.
In Laravel 5.7 you can call specific field like this
$users = App\Book::with('author:id,name')->get();
It is important to add foreign_key field in the selection.
If you want to get specific columns using with() in laravel eloquent then you can use code as below which is originally answered by #Adam in his answer here in response of this same question, the answer's main code is as below :
Post::with('user:id,username')->get();
So i have used it in my code but it was giving me error of 1052: Column 'id' in field list is ambiguous, so if you guys are also facing same problem
Then for solving it you have to specify table name before the id column in with() method as below code:
Post::with('user:user.id,username')->get();
I came across this issue but with a second layer of related objects. #Awais Qarni's answer holds up with the inclusion of the appropriate foreign key in the nested select statement. Just as an id is required in the first nested select statement to reference the related model, the foreign key is required to reference the second degree of related models; in this example the Company model.
Post::with(['user' => function ($query) {
$query->select('id','company_id', 'username');
}, 'user.company' => function ($query) {
$query->select('id', 'name');
}])->get();
Additionally, if you want to select specific columns from the Post model you would need to include the user_id column in the select statement in order to reference it.
Post::with(['user' => function ($query) {
$query->select('id', 'username');
}])
->select('title', 'content', 'user_id')
->get();
In your Post model:
public function userWithName()
{
return $this->belongsTo('User')->select(array('id', 'first_name', 'last_name'));
}
Now you can use $post->userWithName
There is another alternative you can eager load specific columns
public function show(Post $post)
{
$posts = $post->has('user')->with('user:id,name,email,picture')->findOrFail($post->id);
return view('your_blade_file_path',compact('posts);
}
In your Post model you should have user relationship also
public function user()
{
return $this->belongsTo( User::class, 'user_id')->withDefault();
}
Note: It is mentioned in Laravel docs.
https://laravel.com/docs/8.x/eloquent-relationships#eager-loading-specific-columns
Note that if you only need one column from the table then using 'lists' is quite nice. In my case i am retrieving a user's favourite articles but i only want the article id's:
$favourites = $user->favourites->lists('id');
Returns an array of ids, eg:
Array
(
[0] => 3
[1] => 7
[2] => 8
)
If you use PHP 7.4 or later you can also do it using arrow function so it looks cleaner:
Post::with(['user' => fn ($query) => $query->select('id','username')])->get();
I faced the same issue while using belongsToMany relationship with my user model (Laravel 8.x.x).
After a long search and trial and test method. I found out this answer
You have to make sure you are selecting the id's and any foreign keys that would be needed for the relationship from either side of that relationship. This allows Eloquent to match up parents to their children.
Original credit goes to https://stackoverflow.com/a/64233242/1551102
So I included
Groups::select('groupid')
...
And it worked like a charm. Although now I want to know how to hide the groupid field after fetching.
I know I can simply loop through the array and remove it. But is there any other method? potentially a simpler and better one.
You can also specify columns on related model at the time of accessing it.
Post::first()->user()->get(['columns....']);
You can try this code . It is tested in laravel 6 version.
Controller code
public function getSection(Request $request)
{
Section::with(['sectionType' => function($q) {
$q->select('id', 'name');
}])->where('position',1)->orderBy('serial_no', 'asc')->get(['id','name','','description']);
return response()->json($getSection);
}
Model code
public function sectionType(){
return $this->belongsTo(Section_Type::class, 'type_id');
}
Be careful that if you don't add the key column(s) it won't return anything. If you want to show only the username without the id you could instead define the $visible/$hidden properties within the Model, like so:
app/Models/User.php
protected $visible = ['username'];
Then it will retrieve only username column with:
Post::with('user')->get();
Hiding the key columns:
Alternatively you could hide the key column(s) and then retrieve only the columns you wish.
app/Models/User.php
protected $hidden = ['id'];
Specify which columns you want including the key or else it won't return anything, but this will actually only return the username, because id is $hidden.
Post::with('user:id,username')->get();
Now you can use the pluckmethod on a Collection instance:
This will return only the uuid attribute of the Post model
App\Models\User::find(2)->posts->pluck('uuid')
=> Illuminate\Support\Collection {#983
all: [
"1",
"2",
"3",
],
}
Try with conditions.
$id = 1;
Post::with(array('user'=>function($query) use ($id){
$query->where('id','=',$id);
$query->select('id','username');
}))->get();
So, similar to other solutions here is mine:
// For example you have this relation defined with "user()" method
public function user()
{
return $this->belongsTo('User');
}
// Just make another one defined with "user_frontend()" method
public function user_frontend()
{
return $this->belongsTo('User')->select(array('id', 'username'));
}
// Then use it later like this
$thing = new Thing();
$thing->with('user_frontend');
// This way, you get only id and username,
// and if you want all fields you can do this
$thing = new Thing();
$thing->with('user');
EmployeeGatePassStatus::with('user:id,name')->get();