How to send customer popup value in the controller - php

Question

I am using CodeIgniter. I have a view button on the view page. If someone clicks on it then a custom popup will open and It will ask for feedback and approve. Also, I set input type hidden in this popup. After filling the form user will click on submit button.
But I am not getting the value in the controller but I am getting the hidden input value.
View
<?php echo form_open('Employee_control/admin_action_leave','id="admin_action_leave"'); ?>
View
<div class="view_popup_profile" id="popup-2" style="display: none;">
<div class="opacity"></div>
<div class="profile_content">
<div class="profile_header clearfix">
<div class="profile_header_right">
<input type="hidden" name="roster_id_send" id="roster_id_send" value="2">
<select name="admin_approved_status" id="admin_approved_status">
<option value="" disabled selected>Status</option>
<option value="1">Approved</option>
<option value="0">Pending</option>
<option value="-1">Reject</option>
</select>
<?php echo form_error('admin_approved_status'); ?>
</div>
</div>
<div class="profile_body">
<div class="row">
<div class="col-md-6 text_area_box">
<div class="admin_feedback">
<h3>Feedback</h3>
<textarea class="form_control" name="admin_feedback" id="admin_feedback"></textarea>
<?php echo form_error('admin_feedback'); ?>
<button type="submit" class="btn">Submit</button>
</div>
</div>
</div>
</div>
<div class="profile_footer">
Close
</div>
</div>
</div>
<?php echo form_close(); ?>
Controller
public function admin_feedback_leave(){
echo $admin_approved_status=$this->input->post('admin_approved_status');
echo $admin_feedback=$this->input->post('admin_feedback');
echo $roster_id_send=$this->input->post('roster_id_send');
}
I tried using ajax instated of form
Same issue I am getting. It's display only hiddle value
$("#admin_action_leave").validate({
// Specify the validation rules
rules: {
admin_approved_status:{
required:true
},
admin_feedback:{
required:true,
minlength:15,
maxlength:250
}
},
submitHandler: function(form) {
//form.submit();
//var a= document.getElementById("admin_approved_status").value;
//alert(a);
var admin_approved_status = $('#admin_approved_status').val();
var admin_feedback = $('#admin_feedback').val();
var roster_id_send = $('#roster_id_send').val();
// alert(admin_feedback);
//alert(roster_id_send);
//alert(admin_approved_status);
$.ajax({
url: baseUrl + "/Employee_control/admin_feedback_leave",
method: "POST",
data: {
admin_approved_status: admin_approved_status,
admin_feedback:admin_feedback,
roster_id_send:roster_id_send
},
success: function(data)
{
alert(data);
}
}); //AJAX
}
});
After implementing the code. I am just sharing the small part of the code.
My issue is I am not able to send the data to the controller. I tried two-way one using ajax and second using form submit. I am sharing the form submit code.
When I am adding the below code then it's not sending the data to the controller. If I remove the if and foreach condition then I am getting the output.
<?php $n=1; if(isset($admin_data_leave)){foreach ($admin_data_leave as $row) {?>
<!--some html code here-->
<?php $n++;}}else{echo "No data found";}?>
Whole code
<?php echo form_open('Employee_control/admin_feedback_leave', 'id="admin_action_leave"'); ?>
<table cellspacing="0" class="applied_leave_list_table">
<tbody>
<?php
$n = 1;
if (isset($admin_data_leave)) {
foreach ($admin_data_leave as $row) {
?>
<tr>
<td><?php echo $n; ?></td>
<td> View </td>
</tr>
<div class="view_popup_profile" id="popup-<?= $row->roster_id; ?>" style="display: none;">
<div class="profile_content">
<div class="profile_header_right">
<input type="hidden" name="roster_id_send" id="roster_id_send" value="<?php echo $row->roster_id; ?>">
</div>
</div>
<h3>Admin Feedback</h3>
<textarea class="form_control" name="admin_feedback" id="admin_feedback"></textarea>
<?php echo form_error('admin_feedback'); ?>
<button type="submit" class="btn">Submit</button>
</div>
<?php
$n++;
}
} else {
echo "No data found";
}
?>
</tbody>
</table>
<?php echo form_close(); ?>
Jquery validation
$('#admin_action_leave').each( function(){
var form = $(this);
form.validate({
rules: {
admin_approved_status:{
required:true
},
admin_feedback:{
required:true,
minlength:15,
maxlength:250
}
}
});
});

Answer 1

When I am adding the below code then it's not sending the data to the
controller. If I remove the if and foreach condition then I am getting
the output.
...which means, the content of the variable $admin_data_leave is not fulfilling the condition, ie. Either it is not set(not defined) or its not a traversible object or its empty.
Try putting the following code before the condition and look at the output...
echo "<pre>";
var_dump($_POST);
echo "</pre>";
die();