I am working with php. I have some dynamic string. Now I want to add some number after some string. Like, I have a string this is me (1). Now I want to add -7 after 1. So that string should be print like this this is me (1-7).
I have done this properly by using substr_replace. like this
substr_replace('this is me (1)','-59',-1,-1)
Now if there is more than one number like this this is me(2,3,1). I want to add -7 after each number. like this one this is me(2-7,3-7,1-7).
Please help. TIA
I dont know if there is a good way to do this in one or two lines, but the solution I came up with looks something like this:
$subject = "this is me (2,3,1)";
if (preg_match('[(?<text>.*)\((?<numbers>[0-9,]+)\)]', $subject, $matches)) {
$numbers = explode(",", $matches['numbers']);
$numbers = array_map(function($item) {
return $item.'-7';
}, $numbers);
echo $matches['text'].'('.implode(",", $numbers).')';
}
What happens here is the following:
preg_match checks whether the text is in our desired format
We generate an array from our captured named group numbers with explode
We add our "Magic Value" (-7) to every array element
We're joining the text back together
Related
I have an array of arrays like:
$array = [["1.","COTV_LITE(1800)"],["2.","COTV_PREMIUM(2200)"]]
Now, I want to implode this array such that it would return something like this:
COTV_LITE(1800)
COTV_PREMIUM(2200)
How do I achieve this? Calling just the implode() function did not work:
implode ('<br>', $array);
You can call array_map() to implode the nested arrays:
echo implode('<br>', array_map(function($a) { return implode(' ', $a); }, $array));
DEMO
output:
1. COTV_LITE(1800)<br>2. COTV_PREMIUM(2200)
You can use variable length arguments variadic in PHP >= 5.6
Option1
$items = [["1.","COTV_LITE(1800)"],["2.","COTV_PREMIUM(2200)"]];
echo implode(' ',array_merge(...$items));
Output
1. COTV_LITE(1800) 2. COTV_PREMIUM(2200)
This is more of a precursor for the next option.
Option2
If you want to get a bit more creative you can use preg_replace too:
$items = [["1.","COTV_LITE(1800)"],["2.","COTV_PREMIUM(2200)"]];
$replace = [
'/^(\d+\.)$/' => '<li>\1 ',
'/^(\w+\(\d+\))$/' => '\1</li>'
];
echo '<ul>'.implode(preg_replace(array_keys($replace),$replace,array_merge(...$items))).'</ul>';
Output
<ul><li>1. COTV_LITE(1800)</li><li>2. COTV_PREMIUM(2200)</li></ul>
Option3
And lastly using an olordered list, which does the numbers for you. In this case we only need the second item from the array (index 1):
$items = [["1.","COTV_LITE(1800)"],["2.","COTV_PREMIUM(2200)"]];
echo '<ol><li>'.implode('</li><li>',array_column($items,1)).'</li></ol>';
Output
<ol><li>COTV_LITE(1800)</li><li>COTV_PREMIUM(2200)</li></ol>
Personally, I would put it in the ol that way you don't have to worry about the order of the numbers, you can let HTML + CSS handle them. Also it's probably the easiest and most semantically correct way, But I don't know if the numbering in the array has any special meaning or not.
In any case I would most definitely put this into a list to render it to HTML. This will give you a lot more options for styling it, later.
Update
want to use option 1. But how do I put each option on a different line using <br>
That one will put the <br> between each array element:
echo implode('<br>',array_merge(...$items));
Output
1.<br>COTV_LITE(1800)<br>2.<br>COTV_PREMIUM(2200)
The only way to easily fix that (while keeping the array_merge) is with preg_replace, which is the second one. So I will call this:
Option 1.2
$items = [["1.","COTV_LITE(1800)"],["2.","COTV_PREMIUM(2200)"]];
echo implode(preg_replace('/^(\w+\(\d+\))$/',' \1<br>',array_merge(...$items)));
Output
1. COTV_LITE(1800)<br>2. COTV_PREMIUM(2200)<br>
Sandbox
Basically there is no way to tell where the end item is after merging them. That operation effectively flattens the array out and gives us something like this:
["1.","COTV_LITE(1800)","2.","COTV_PREMIUM(2200)"]
So that Regex does this 'COTV_PREMIUM(2200)' becomes ' COTV_PREMIUM(2200)<br>'. This is just a way of changing that without having to dip into the array with some logic or something. WE wind up with this modification to the array:
["1."," COTV_LITE(1800)<br>","2."," COTV_PREMIUM(2200)<br>"]
Then with implode we just flatten it again into a string:
"1. COTV_LITE(1800)<br>2. COTV_PREMIUM(2200)<br>"
The Regex ^(\w+\(\d+\))$
^ - Match start of string
(...) - capture group 1
\w+ - match any working character a-zA-Z0-9_ one or more, eg. COTV_PREMIUM
\( - match the ( literally
\d+ - match digits 0-9 one or more, eg 2200
\) - match the ) literally
$ - match end of string
So this matches the pattern of the second (or even) items in the array, then we replace that with this:
The Replacement ' \1<br>'
{space} - adds a leading space
\1 - the value of capture group 1 (from above)
<br> - append a line break
Hope that makes sense. This should work as long as they meet that pattern. Obviously we can adjust the pattern, but with such a small sample size it's hard for me to know what variations will be there.
For example something as simple as (.+\))$ will work TestIt. This one just looks for the ending ). We just need somethng to capture all of the even ones, while not matching the odd. Regular expressions can be very confusing the first few times you see them, but they are extremely powerful.
PS - I added a few links to the function names, these go the the PHP documentation page for them.
Cheers!
Try this
$items = [["1.","COTV_LITE(1800)"],["2.","COTV_PREMIUM(2200)"]];
$imploded = [];
foreach($items as $item) {
$item_entry = implode(' ', $item);
echo $item_entry . '<br/>'; // display items
$imploded[] = $item_entry;
}
// your desired result is in $imploded variable for further use
I know there are lots of tutorials and question on replacing something in a string.
But I can't find a single one on what I want to do!
Lets say I have a string like this
$string="Hi! [num:0]";
And an example array like this
$array=array();
$array[0]=array('name'=>"na");
$array[1]=array('name'=>"nam");
Now what I want is that PHP should first search for the pattern like [num:x] where x is a valid key from the array.
And then replace it with the matching key of the array. For example, the string given above should become: Hi! na
I was thinking of doing this way:
Search for the pattern.
If found, call a function which checks if the number is valid or not.
If valid, returns the name from the array of that key like 0 or 1 etc.
PHP replaces the value returned from the function in the string in place of the pattern.
But I can't find a way to execute the idea. How do I match that pattern and call the function for every match?
This is just the way that I am thinking to do. Any other method will also work.
If you have any doubts about my question, please ask in comments.
Try this
$string="Hi! [num:0]";
$array=array();
$array[0]=array('name'=>"na");
$array[1]=array('name'=>"nam");
echo preg_replace('#(\!)?\s+\[num:(\d+)\]#ie','isset($array[\2]) ? "\1 ".$array[\2]["name"] : " "',$string);
If you don't want the overhead of Regex, and your string format remains same; you could use:
<?php
$string="Hi! [num:0]";
echo_name($string); // Hi John
echo "<br />";
$string="Hello! [num:10]";
echo_name($string); // No names, only Hello
// Will echo Hi + Name
function echo_name($string){
$array=array();
$array[0]=array('name'=>"John");
$array[1]=array('name'=>"Doe");
$string = explode(" ", $string);
$string[1] = str_replace("[num:", "", $string[1]);
$string[1] = str_replace("]", "", $string[1]);
if(array_key_exists($string[1], $array)){
echo $string[0]." ".$array[$string[1]]["name"];
} else {
echo $string[0]." ";
}
}// function echo_sal ENDs
?>
Live: http://codepad.viper-7.com/qy2uwW
Assumptions:
$string always will have only one space, exactly before [num:X].
[num:X] is always in the same format.
Of course you could skip the str_replace lines if you could make your input to simple
Hi! 0 or Hello! 10
I want to insert a text string inside another one after certain number or words. For example:
$text_to_add = "#Some Text to Add#";
$text_original = "This is the complete text in which I want to insert the other text";
$number_words = 7; // Variable that will define after how many words I must put $text_to_add
I want to get the following result when I print $text_original:
This is the complete text in which #Some Text to Add# I want to insert the other text
I can use this function http://php.net/manual/en/function.str-word-count.php to get an array of words, go through it building a new string with the $text_to_add inserted, but I wondering if there is a better way to accomplish this, since some of my $text_original texts are very long.
Thanks in advance.
Try this:
$arr = explode(" ",$text,$number_words+1);
$last = array_pop($arr);
return implode(" ",$arr)." ".$text_to_add." ".$last;
I have a list of items that are in this format:
05/01 – Some Basic: Text Here (Alpha, Bravo, Charli)
The first part is a date, then its always followed by a - . Then some text which represents a title or location of some sort and then some keywords that may or may not be in the parentheses.
I want to be able to extract the $month the $day the $title (including any colons) and the $keyword1 $keyword2 $keyword3 if they are there. Then assign them all to individual variables like the ones I've created so I can add them into my database. Getting it to do one of these at a time would be a great start but ultimately I want to be able to paste in multiple items in that format(without any spaces or characters to mark the difference besides whats already there) and be able to bulk extract them.
I've tried to use Preg_Match_all and things like stristr() but am having difficulty. I don't really understand how to use them to get the specific parts.
For example
$month = stristr($listItem, '/', true);
echo"$month<br />";
$preDay = stristr($listItem, 'The', true);
echo"$preDay<br />";
$day = stristr($preDay, '/', false);
echo"$day<br />";
This only outputs this:
05
05/01 –
/01 –
^ I can't have the / or any weird –.
Actual code and an explanation of how to do this would be awesome! If you are using pregmatch I would really appreciate a breakdown of how your filtering this. Thank you much.
The easiest way is using explode().
The explode() function provides a fast way to break strings into arrays. See the manual: http://php.net/manual/pt_BR/function.explode.php
With this format of string, you can break it into an array as follows.
$string = '05/01 - Some Basic: Text Here (Alpha, Bravo, Charli)';
$array = explode('-',$string);
$date = $array[0]; //Date 05/01
$array= explode('(',$array[1]);
$title = $array[0];
$tags = $array[1];
//Now you have
$date = '05/01';
$title = 'Some Basic: Text Here';
$tags = 'Alpha, Bravo, Charli)';
//Notice that the first parenthesis of tags was exploded.
//This is valid if and only if you have your string in the format
// [date] - [title] ([tags]
I don't know if this is the best way but it works. You can also try using preg_split() function. This function makes a split using regular expressions. If you need help on regular expressions see http://www.phpf1.com/tutorial/php-regular-expression.html
EDIT 1 I noticed that you string contains this symbol "–" after the date. This is not a hyphen as I know it. I use the minus signal to write it on my keyboard.
Your simbol / mine = –-
They are a little bit different.
I have a really long string in a certain pattern such as:
userAccountName: abc userCompany: xyz userEmail: a#xyz.com userAddress1: userAddress2: userAddress3: userTown: ...
and so on. This pattern repeats.
I need to find a way to process this string so that I have the values of userAccountName:, userCompany:, etc. (i.e. preferably in an associative array or some such convenient format).
Is there an easy way to do this or will I have to write my own logic to split this string up into different parts?
Simple regular expressions like this userAccountName:\s*(\w+)\s+ can be used to capture matches and then use the captured matches to create a data structure.
If you can arrange for the data to be formatted as it is in a URL (ie, var=data&var2=data2) then you could use parse_str, which does almost exactly what you want, I think. Some mangling of your input data would do this in a straightforward manner.
You might have to use regex or your own logic.
Are you guaranteed that the string ": " does not appear anywhere within the values themselves? If so, you possibly could use implode to split the string into an array of alternating keys and values. You'd then have to walk through this array and format it the way you want. Here's a rough (probably inefficient) example I threw together quickly:
<?php
$keysAndValuesArray = implode(': ', $dataString);
$firstKeyName = 'userAccountName';
$associativeDataArray = array();
$currentIndex = -1;
$numItems = count($keysAndValuesArray);
for($i=0;$i<$numItems;i+=2) {
if($keysAndValuesArray[$i] == $firstKeyName) {
$associativeDataArray[] = array();
++$currentIndex;
}
$associativeDataArray[$currentIndex][$keysAndValuesArray[$i]] = $keysAndValuesArray[$i+1];
}
var_dump($associativeDataArray);
If you can write a regexp (for my example I'm considering there're no semicolons in values), you can parse it with preg_split or preg_match_all like this:
<?php
$raw_data = "userAccountName: abc userCompany: xyz";
$raw_data .= " userEmail: a#xyz.com userAddress1: userAddress2: ";
$data = array();
// /([^:]*\s+)?/ part works because the regexp is "greedy"
if (preg_match_all('/([a-z0-9_]+):\s+([^:]*\s+)?/i', $raw_data,
$items, PREG_SET_ORDER)) {
foreach ($items as $item) {
$data[$item[1]] = $item[2];
}
print_r($data);
}
?>
If that's not the case, please describe the grammar of your string in a bit more detail.
PCRE is included in PHP and can respond to your needs using regexp like:
if ($c=preg_match_all ("/userAccountName: (<userAccountName>\w+) userCompany: (<userCompany>\w+) userEmail: /", $txt, $matches))
{
$userAccountName = $matches['userAccountName'];
$userCompany = $matches['userCompany'];
// and so on...
}
the most difficult is to get the good regexp for your needs.
you can have a look at http://txt2re.com for some help
I think the solution closest to what I was looking for, I found at http://www.justin-cook.com/wp/2006/03/31/php-parse-a-string-between-two-strings/. I hope this proves useful to someone else. Thanks everyone for all the suggested solutions.
If i were you, i'll try to convert the strings in a json format with some regexp.
Then, simply use Json.