When I encode the json data fetching from the mysql database, I get this:
[{"userid":"11","postid":"12"},{"userid":"13","postid":"12"},{"userid":"16","postid":"12"}]
And I am trying to get only the userid's like this: 11, 13, 16.
Decoding the json data gives me an output of: Array. And nothing else. When I var_dump this is my results:
array(3) {
[0]=> array(2) {
["userid"]=> string(2) "11"
["postid"]=> string(2) "12"
}
[1]=> array(2) {
["userid"]=> string(2) "13"
["postid"]=> string(2) "12"
}
[2]=> array(2) {
["userid"]=> string(2) "16"
["postid"]=> string(2) "12"
}
So I know there is data present, it's just not showing for some reason.
Here is what my query looks like:
if(isset($_POST['postuserid'])){
$uid = $_POST['postuserid'];
$ssql = "SELECT * FROM foodid WHERE postid=$uid";
$rresult = mysqli_query($db,$ssql);
while ($lrow = mysqli_fetch_assoc($rresult)){
$ret[] = $lrow;
$postjson = json_encode($ret);
$decode_postid = json_decode($postjson, true);
$new_postid = $decode_postid;
}
var_dump($new_postid);
die($new_postid);
// die($new_postid['userid']); is what I need along with all data userid fetched.
}
Is there a reason why this works when I encode json data, but not when I decode the json data?
Are you trying to get that array out of the die function? It can only take a string or int.
http://php.net/manual/en/function.exit.php
Your array is there... just do something like:
$ids = '';
foreach ($new_postid as $post) {
$ids .= $post['userid'] . ',';
}
$ids = rtrim($ids,',');
die($ids);
Try mapping those results:
$new_postid = $decode_postid;
$new_postid = array_map(function($item){
return $item['userid'];
}, $new_postid);
var_dump($new_postid);
Output
array(3) {
[0]=>
string(2) "11"
1=>
string(2) "13"
[2]=>
string(2) "16"
}
If you need to output as string, just use implode function
die(implode(',',$new_postid));
http://php.net/manual/en/function.array-map.php
Related
I have a php page which returns a php array as the following
array(6) {
[0]=>
array(2) {
["cityName"]=>
string(10) "Ananindeua"
[0]=>
string(10) "Ananindeua"
}
[1]=>
array(2) {
["cityName"]=>
string(8) "An�polis"
[0]=>
string(8) "An�polis"
}
[2]=>
array(2) {
["cityName"]=>
string(8) "Anderson"
[0]=>
string(8) "Anderson"
}
[3]=>
array(2) {
["cityName"]=>
string(6) "Angers"
[0]=>
string(6) "Angers"
}
[4]=>
array(2) {
["cityName"]=>
string(9) "Angoul�me"
[0]=>
string(9) "Angoul�me"
}
[5]=>
array(2) {
["cityName"]=>
string(6) "Anshan"
[0]=>
string(6) "Anshan"
}
}
I want to use this array in another page to do some ajax, and I want to encode the resulat into a JSON as the following :
{
"cityName": "Anshan",
"cityName": "Angoul�me",
"cityName": "Anderson",
"cityName": "An�polis",
"cityName": "Ananindeua"
}
but Instead I get only one value, which is the last value :
{
"cityName": "Anshan"
}
This is the code I tried :
<?php
$connexion = new PDO("mysql:host=localhost;dbname=world", 'root', 'toor');
$statement = $connexion->prepare("SELECT cityName FROM cities WHERE cityName LIKE '" . $_POST['cityName'] . "%'");
$statement->execute();
$resultats = $statement->fetchAll();
foreach($resultats as $city) {
$output[key($city)] = current($city);
}
echo json_encode($output, 128);
?>
So how can I solve this problem ?
Edit :
I tried to get only cities names, and push them into an array, when I do a var_dump() for this array this is what I get :
array(6) {
[0]=>
string(10) "Ananindeua"
[1]=>
string(8) "An�polis"
[2]=>
string(8) "Anderson"
[3]=>
string(6) "Angers"
[4]=>
string(9) "Angoul�me"
[5]=>
string(6) "Anshan"
}
But when I did a json_encode() I don't get anything, so I tried to do a var_dump(json_encode($output)); and I get this :
bool(false)
In the second time I tried to create a table manually :
$a = array("Ananindeua","Anápolis","Anderson","Angers","Angoulême","Anshan" );
and it worked.
But why the first array won't encode !
Your desired output is not valid/conceivable either as a PHP associative array or JSON because in both cases, you have duplicate keys.
You're just overwriting the cityName key with each iteration. Push to an array instead:
foreach($resultats as $city) {
$output[] = current($city);
}
echo json_encode($output, 128);
Output:
[
"Anshan",
"Angoulme",
"Anpolis"
]
Or if you want an object for each city, which is useful if you want other properties:
foreach($resultats as $city) {
$output[] = array(
'cityName' => current($city)
);
}
echo json_encode($output, 128);
Output:
[
{
"cityName" : "Anshan",
},
{
"cityName" : "Angoulme",
},
{
"cityName" : "Anpolis"
}
]
Side note: if you don't need the numerical keys from the PDO fetch call, consider using the PDO::FETCH_ASSOC fetch style, to bring back only associative keys:
$resultats = $statement->fetchAll(PDO::FETCH_ASSOC);
The json you're expecting doesn't look right. It should be:
[
{"cityName": "Anshan"},
{"cityName": "Angoul�me"},
{"cityName": "Anderson"},
{"cityName": "An�polis"},
{"cityName": "Ananindeua"}
]
and to generate this you need code like this:
foreach($resultats as $city) {
$item = new stdClass();
$item.cityName = current($city);
$output[] = item;
}
Your array's key is same (cityName), so the value getting replaced on each assignment.
use a numeric array, or another method that differentiating the key
e.g.,
foreach($resultats as $city) {
$output['cityName'][] = current($city);
}
output will be
{"cityName":
[
"Anshan",
"Angoulme",
"Anpolis"
]
}
The problem was that the table which I populate from database contains some accented characters, so the json_encode() failing.
The solution was to add charset=UTF8 in the first parameter of the PDO instance.
$connexion = new PDO("mysql:host=localhost;dbname=world;charset=UTF8", 'root', 'toor');
$sql = "SELECT catgy.category_id, catgy.category_title
FROM categories catgy
INNER JOIN subj_category_relation scr
ON scr.scr_id = catgy.category_id
INNER JOIN subjects subj
ON subj.subject_id = '{$sId}'
WHERE subj.subject_id = '{$sId}'
AND subj.subject_id = scr.subject_id";
$res = $this->db->query( $sql );
if ($res) {
$results = $res->result_array();
echo "<pre>";
var_dump( $results );
echo "</pre>"
exit;
vardump
array(5) {
[0]=>
array(2) {
["category_id"]=>
string(1) "1"
["category_title"]=>
string(5) "terms"
}
[1]=>
array(2) {
["category_id"]=>
string(1) "2"
["category_title"]=>
string(6) "people"
}
[2]=>
array(2) {
["category_id"]=>
string(1) "3"
["category_title"]=>
string(8) "places
"
}
[3]=>
array(2) {
["category_id"]=>
string(1) "4"
["category_title"]=>
string(7) "works
"
}
[4]=>
array(2) {
["category_id"]=>
string(1) "5"
["category_title"]=>
string(8) "events
"
}
}
Getting Database int type in string. What is the proper solution? Instead converting each array may be not good solution.
Database object should return correct value type in object. there is issue in PHP/MySQL older versions.
https://dev.mysql.com/downloads/connector/php-mysqlnd/
Install php5-mysqlnd driver
apt-get install php5-mysqlnd
service apache2 restart
Reference:
MySQL integer field is returned as string in PHP
Check #advait answer
$new_int_array = array();
foreach($results as $value){
$new_int_array [] = array_map('intval', $value);
}
print_r($new_int_array); //this is new array with int type values.
Try array_walk to convert string to int:
array_walk($results, function(&$a) {
$a['category_id'] = (int)$a['category_id'];
});
var_dump($results);
DEMO
When retrieving even integers from DB it is converted to string so you have to manually convert them back to int
This is one of those that should be easy. I'm not even sure if "subset" is the right way to describe it.
My initial array looks like this:
array(3) { [0]=> array(5) { ["id"]=> string(1) "1" ["claim_id"]=> string(1) "1" ["price"]=> string(2) "50" ["date"]=> string(19) "2013-05-15 01:58:48" ["created"]=> string(19) "2013-05-15 01:58:48" } [1]=> array(5) { ["id"]=> string(2) "11" ["claim_id"]=> string(1) "1" ["price"]=> string(2) "45" ["date"]=> string(19) "2013-05-15 03:34:59" ["created"]=> string(19) "2013-05-15 03:37:01" } [2]=> array(5) { ["id"]=> string(2) "25" ["claim_id"]=> string(1) "1" ["price"]=> string(2) "50" ["date"]=> string(19) "2013-05-15 22:47:46" ["created"]=> string(19) "2013-05-15 22:52:02" } }
I'd ultimately like to end up with just the date and price values, swap them so that date is first in the array, reformat the date, and convert it to a json array that looks something like this:
[{"date":"Mar. 15","price":"50"},{"date":"Mar. 15","price":"45"},{"date":"Mar. 15","price":"50"}]
I ran a foreach statement to get at the data and reformat the date, then went out of my league with splice, unset, and other functions that took me in the wrong direction. Any ideas?
Try this
$array = array();
for($i = 0 ; $i<count($your_array);$i++) {
$a=array();
$a['date'] = $your_array[$i]['date'];
$a['price'] = date("F .j",strtotime($your_array[$i]["date"]));
array_push($array,$a);
}
json_encode($array);
Output
[{"date":"Mar. 15","price":"50"},{"date":"Mar. 15","price":"45"},{"date":"Mar. 15","price":"50"}]
Codepad
This should get you there
$ret = array();
foreach ($source as $rec){
$ret[] = array("date"=>$rec["date"], "price"=>$rec["price"]);
}
$json = json_encode($ret);
Create a quick function to create another array with only selected elements:
function datePriceToJson($array) {
$a = array();
foreach($array as $i => $a) {
$a[] = array("date" => $a['date'], "price" => $a['price']); //Creae a new array based on the one you want
}
return json_encode($a);
}
datePriceToJson($array);
You need to reconstruct array using correct foreach and the use json_encode to get the json
$req_array = array();
foreach($youArray as $value)
{
$temp = array();
$temp['date'] = $value['date'];
$temp['price'] = $value['price'];
$req_array[] = $temp;
}
$json = json_encode($req_array);
echo $json;
see demo
Hope it helps you
$infos =array(
array("id" =>"1","price"=>"50","date"=>"2013-05-15 01:58:48"),
array("id" =>"2","price"=>"55","date"=>"2013-06-15 01:58:48")
);
$i=0;
foreach ($infos as $info )
{
$infos[$i]["date"]= date("F .j",strtotime($info["date"]));
$i++;
}
echo json_encode($infos);
I'm receiving a JSON and trying to interpret some values using PHP.
Example snippet from a JSON dump:
["11811"]=>
object(stdClass)#15 (11) {
["parent_area"]=>
NULL
["generation_high"]=>
int(19)
["all_names"]=>
object(stdClass)#16 (0) {
}
["id"]=>
int(11811)
["codes"]=>
object(stdClass)#17 (3) {
["ons"]=>
string(2) "08"
["gss"]=>
string(9) "E15000008"
["unit_id"]=>
string(5) "41421"
}
["name"]=>
string(10) "South East"
["country"]=>
string(1) "E"
["type_name"]=>
string(15) "European region"
["generation_low"]=>
int(1)
["country_name"]=>
string(7) "England"
["type"]=>
string(3) "EUR"
}
As there is lots of (nested) data, I need to obtain the value of ["name"] where ["type_name"] == 'European region'.
Thanks.
You could use array_filter()
$data_array = array(...);
function is_european($data) {
return $data->type_name == 'European region';
}
$filtered = array_filter($data_array,'is_european');
And then use filtered array to obtain values.
Maybe a better way would be to use JsonPath, like this, assuming your array is a result of decoding JSON (object):
$names = jsonPath($data_object, "$.[?(#['type_name'] == 'European region')].name");
Haven't tried this myself, it may need a bit of correction.
Try this:
<?php
$json = JSON_decode(str,true);
$arr = Array();
foreach($json as $f) {
/* eg. $f = $json["11811"] */
if($f['type_name'] == 'European region') {
$arr[] = $f['name'];
}
}
?>
I want to create a JSON object from my MySQL results with PHP so I can pass it to JavaScript. I don't quite understand the difference between JSON array and JSON object.
This is how I do it. But is there a better way? This is the array way I believe?
$json = array();
while($r=mysql_fetch_array($res)){
$json['firstname'] = $r['firstname'];
$json['lastname'] = $r['lastname'];
}
echo json_encode($json);
I want to be able to get the info from JavaScript, by selecting all first names only If I wish etc..
you can try this, fetch data and push to array, then echo that array
$info=array();
while($row = mysql_fetch_array($res,MYSQL_ASSOC)){
array_push($info,$row);
}
echo json_encode($info);
would return
array(2) { [0]=> array(3) { ["id"]=> string(1) "1" ["firstname"]=> string(3) "foo" ["lastname"]=> string(3) "bar" } [1]=> array(3) { ["id"]=> string(1) "2" ["firstname"]=> string(3) "foo" ["lastname"]=> string(3) "bar" } }
json
[{"id":"1","firstname":"foo","lastname":"bar"},{"id":"2","firstname":"foo","lastname":"bar"}]
Well this would encode every row, with each row being the JSON Object:
$json = array();
while($r=mysql_fetch_array($res)){
$json[] = $r;
}
echo json_encode($json);