I was wondering if there is an easy way to work with multiple select boxes in Laravel. I am trying to make a city box, if the city is selected, if want to load the next controller that shows the areas in the city. Would this even be possible for a form?
Thank you
Thank you, guys.
It was quite easy to make.
Never expected it to be this easy.
I did it by setting a route to a new controller and working with javascript.
To the people that would like to make this in the near future.
Below you can find an idea of code that I have used for Laravel;
Javascript
$(document).ready(function () {
$('#city').change(function () {
var city = $("#city option:selected").val();
$.ajax({
url: "https://anma-maching-dev.aska-ltd.jp/destinations",
data: {
"city" : city
},
success: function(result){
jQuery('.area').html('');
$( ".area" ).fadeIn("fast", function() {
$(".area").append(result);
});
}
});
});
});
I attached the output of the controller to a div class called area!
route
Route::get('/destinations', 'destinationsController#get_area');
strong text
public static function get_area()
{
// your query to select the next information for your textBox
}
Related
Hello I have issue with my jquery code, because when I want to press any key to get query from database that is not working (it is not showing any alert). I think my ajax isn't working very well because I tried to copy other code and didn't work. I want to get data from database with my skills to choose in options
jQuery code
$(document).ready(function () {
$("#skills").click(function () {
alert("test")
});
});
<select class="select2bs4" multiple="multiple" name="ums[]" data-placeholder="Skills"
style="width: 100%;" id="skills">
</select>
And I want to do when I press any key then should show any result in multiple select but at beginning didn't show any alert yet.
I tried to do like "Select2 and Laravel: Ajax Autocomplete" from Laraget website and that wasn't working too
EDIT____
If it's only input with type 'text' it's working fine to show alert
Thank you in advance
Try this
$(document).ready(function () {
$("#skills").change(function () {
alert("test")
});
});
Select will not work with click but with change , but if you want change when you write in select like search bar , replace this :
$("#skills").click(function () {
alert("test")
});
to this if you want to get the change option :
$("#skills").on('change',function () {
alert("test")
});
or this if you want to handle user input :
$("#skills").on('keyup',function () {
alert("test")
});
I thought the easiest way would be to explain it with an image of what I have.
Summary -
I have a form to submit posts (pretty much like what you would find in twitter). Within each post there is an <ol> where comments to that post will reside.
Problem -
When I submit the first comment (button submit 2 in the picture), it doesn't call the ajax and just goes to a page where it presents me the php output of the comment. It seems it is not reloading or aplying DOM events to that portion of code. If I go back, the comment is presented (because it refreshs the page) and when adding the 2nd comment, everything goes normal, as expected. The problem is just the first comment.
Flow -
1) insert new post
2) click the textarea, put some text and press submit
3) Jumps to a page where php output for comment is presented
3a) no ajax call is done. It never enters the code
Could you please help me out understand what is going on? Thanks in advance.
In case you need more of the code just tell me.
JS (post_comment.js - associated with submit 2 in picture. I use ajaxForm - jquery form plugin - though I also tried with the standard .ajax call and the result is the same)
$(function () {
var options = {
success: function (html) {
var arrHTML = html.split(',');
var postId = $.trim(arrHTML[0]);
var html_code = arrHTML[1];
$('ol#post_comment_list' + postId).load(html_code);
//$('ol#post_comment_list'+postId 'li:first').slideDown('slow');
$('.footer-post').hide();
$('.comments-feed').delay(2000).slideUp({
duration: 1000,
queue: true
});
$('.small-textarea-main-feed').removeClass('set-large');
resetForm($('.footer-comment'));
},
error: function () {
alert('ERROR: unable to upload files');
},
complete: function () {
},
};
$(".footer-comment").ajaxForm(options);
function ShowRequest(formData, jqForm, options) {
var queryString = $.param(formData);
alert('BeforeSend method: \n\nAbout to submit: \n\n' + queryString);
return true;
}
function resetForm($form) {
$form.find('input:text, input:password, input:file, select, textarea').val('');
$form.find('input:radio, input:checkbox')
.removeAttr('checked').removeAttr('selected');
}
});
I'm using jQuery ui's sortable. A list of objects is retrieved from the db an dynamically put into a list, the user drag and drops the list objects and the new order of the list should get saved.
Below is the jQuery code for sortable, which include creating an array of the new list order. However, next step is to do something so that I'm able to use this array in my php code.
The thing is that the user, apart from sorting the list objects also should be able to add some comments and do some other stuff and then submit it all. That is, I'm using a form for this. By that reason I must be able to put in the array with the list order into the form in some way, and here's where I need some help.
What method should I use? Ajax? Local storage? How could this be accomplished?
$('#listElements').sortable({
update: function(event, ui) {
var order = [];
$('.listObject li').each( function(e) {
order.push($(this).attr('id'));
});
}
});
You'll want to use AJAX to send the order array to PHP like so:
$('#listElements').sortable({
update: function (event, ui) {
var order = [];
$('.listObject li').each(function (e) {
order.push($(this).attr('id'));
});
$.ajax({
url: "/save_order_to_db",
type: "post",
data: {
order_data: order
}
}).success(function (data) {
console.log(data);
});
}
});
I've built star button to use it like "starred items". I have the code running. but i have a problem.
When i click on star it becomes a starred item and and the star image changes.
But when i click again to unstar, it just doesn't work. i need to refresh the page to unstar it.
Also even the first step doesn't work for chrome.
add star codes:
jquery
$(function() {
$(".yildiz").click(function() {
var id = $(this).attr("id");
var dataString = 'id='+id ;
var parent = $(this).parent();
$.ajax({
type: "POST",
url: "yildizekle.php",
data: dataString,
cache: false,
success: function toggle()
{
$('.yildizbutton'+id).animate({
src:"star-icon.png",
class:"yildizsizbutton"+id,
},0);
}
});
return false;
});
});
php:
<img class="yildizsizbutton'.$row['id'].'" border="0" src="star-icon.png" alt="Yildizi kaldir" width="16" height="16" />
remove star
$(function() {
$(".yildizf").click(function() {
var id = $(this).attr("id");
var dataString = 'id='+id ;
var parent = $(this).parent();
$.ajax({
type: "POST",
url: "yildizsil.php",
data: dataString,
cache: false,
success: function toggle()
{
$('.yildizsizbutton'+id).animate({
src:"star-icon-f.png",
class:"yildizbutton"+id,
},0);
}
});
return false;
});
});
php:
<img class="yildizbutton'.$row['id'].'" border="0" src="star-icon-f.png" alt="Yildiz ekle" width="16" height="16" />
To add the star, do something similar to this:
$("#"+id).find("img").attr("src", "star-icon.png");
To remove:
$("#"+id).find("img").attr("src", "sstar-icon-f.png");
You shouldn't use animate in the way you are using it at all. I also used the ID of the container, then found the image inside of it, instead of putting together that class like you were doing. That's just personal preference, though...the main takeaway is to use attr("src") to set the src of an image in jQuery.
EDIT: Here is a full solution that should work.
$(function() {
$(".star").click(function() {
var id = $(this).attr("id");
if($(this).hasClass("starred")) {
$.post("yildizekle.php", {id: id}, function(resp) {
$(this).removeClass("starred").find("img").attr("src", "star-icon-f.png");
});
}
else {
$.post("yildizsil.php", {id: id}, function(resp) {
$(this).addClass("starred").find("img").attr("src", "star-icon.png");
});
}
return false;
});
});
Notice that we are using a class to track whether or not the element is already starred. This means in your PHP you will need to add the starred class to any elements that are already starred when the page loads. Also, I used $.post instead of $.ajax since it is a simpler way of doing the same thing.
There are a few problems in your code, and both of the answers here are relevant and both are correct. Being as green as you are, I'd say you are on the road to learning well.
I'd use a separate class for ALL of the stars, one that doesn't relate to if its starred or unstarred. Maybe something like 'star'. :) You need to refresh the page to un-star it is because you never actually change it on the FRONT-end to be starred. If you use a tool like firebug of WebKit's Web inspector, you'll see that the class of the link is still "yildiz".
I'm not going to give you a complete answer because I'd be robbing you of an awesome learning experience here. Here are some pointers:
Remember which objects your click() events are connected to: $(".yildizf") and $(".yildiz")
When you click on an item, does it actually change class so that jQuery knows it's different? Essentially, you are 'starring' the same item over and over again because you never allow jQuery to see it as something it needs to un-star
If you use a 'star' class in addition to the other class (like <a class="star yildiz" ...>), then you can attach your click event to $('a.star'), and figure out in THERE if you should be starring or unstarring the item.
I hope this all makes sense.
You've defined the click event to both star and un-star the item. In the event you need to look at the current state of the item then decide if you want to star or un-star it. you need to branch inside your click event.
Hoping that using something like this demo it is possible to drag items within and between two columns, and update their order either live or with a "save" button to MySQL. Point being that you can make changes and return to the page later to view or update your ordering.
http://pilotmade.com/examples/draggable/
Doing it for just one column is fine, but when I try to pass the order of both columns, the issue seems to be passing multiple serialized arrays with jQuery to a PHP/MySQL update script.
Any insight would be much appreciated.
If you look below, I want to pass say...
sortable1entry_1 => 0entry_5 => 1
sortable2entry_3 => 0entry_2 => 1entry_4 => 2
EDIT: This ended up doing the trick
HTML
<ol id="sortable1"><li id="entry_####">blah</li></ol>
jQuery
<script type="text/javascript">
$(function()
{
$("#sortable1, #sortable2").sortable(
{
connectWith: '.connectedSortable',
update : function ()
{
$.ajax(
{
type: "POST",
url: "phpscript",
data:
{
sort1:$("#sortable1").sortable('serialize'),
sort2:$("#sortable2").sortable('serialize')
},
success: function(html)
{
$('.success').fadeIn(500);
$('.success').fadeOut(500);
}
});
}
}).disableSelection();
});
This is the PHP query
parse_str($_REQUEST['sort1'], $sort1);
foreach($sort1['entry'] as $key=>$value)
{
do stuff
}
what I would do is split them up
data :
{
sort1:$('#sortable1').sortable('serialize'),
sort2:$('#sortable2').sortable('serialize')
}
then when you post you can get the request and set them as needed, I hope that makes sense
so what I do is this
parse_str($_REQUEST['sort1'],$sort1);
foreach($sort1 as $key=>$value){
//do sutff;
}