select multiple options at a time - php

<select class="form-control default-select2 " id="group" data-size="10" data-live-search="true" data-style="btn-white" multiple="multiple">
<option value="" disabled="disabled" selected="selected">Select Group</option>
<!-- <option value="1">Admin</option>
<option value="4">User</option> -->
<?php $groups = $objUser->GetGroups(); ?>
<?php foreach($groups as $group){ ?>
<option value="<?php echo $group['id'] ?>"<?php echo ($data[0]['group_id'] == $group['id'] ? "selected='selected'" : "") ?>><?php echo $group['primary_name'] ?></option> <? } ?>
</select>
Now I want user to select multiple option at a time. i searched the whole internet but i couldn't find the answer to fix this issue. i dont know what i am missing.

Your code can actually manage multiple selections. Just hold Ctrl key and click on different options.
Exemple of multiple select : here
When you submit the form, you will be able to get all the selected options into an array.

Related

PHP: How to display select options if no value from database

I am trying to display my dropdown with a value from the database, but if the value is null I want it to show my options.
Currently it keeps showing me the blank select option.
<select class="form-control col-sm-5" id="freqlevels" name="freqlevels" value="<?php if ($customerinfo['freqlevel']) { echo h($customerinfo['freqlevel']);} else { echo "" ; } ?>"">
<option value=""></option>
<option value="Twice Weekly">Twice Weekly</option>
<option value="Weekly">Weekly</option>
<option value="Fortnightly">Fortnightly</option>
<option value="Monthly">Monthly</option>
</select>
Please can you suggest what I should do?
put your condition outside the value
<?php if ($customerinfo['freqlevel']) { echo value="$customerinfo['freqlevel']";}
hope this will resolve your problem
You need to make use of conditional statements.
<select name="something" id="my-select">
<option value="0">Everyone can see me</option>
<?php if (empty($array['some_key'])) : ?>
<option value="1">I'm only if some_key is empty</option>
..etc..
<?php endif; ?>
</select>
Then you can check values against the option value:
<option value="<?php echo $key; ?>"
<?php echo ($key === $_POST['some_key'] ? 'selected' : ''); ?>>
Hello, world
</option>

How to set the value for dropdown box?

i want to display the value for all the textbox with the help of this code
value="<?php `if(!empty($result) && !empty($result['part'])){ echo $result['part']; } ?>">
Where part is the name of the database field...same thing i have to display for dropdown box how can i do this..In dropdown box the options are displayed with the help of another table
<select class="bootstrap-select show-tick" data-size="5" data-live-search="true" data-width="100%" name="TName1" required>
<option value="" disabled selected>Select Sub Account Name</option>
<?php foreach ($accName as $row ): ?>
<option value="<?=$row['id']?>" <?php echo set_select('accName', $row['id']); ?>>
<?=$row['accName']?>
</option>
<?php endforeach ?>
</select>
where accName is the name stored in another table..i want to display the name here..but it had to be stored as code(predefined integer value) in my database field...How can i did this..??
Value for drop down is set different way than that of text box or text area.
Drop down has options and one of its options (multiple in case it is a multiple dropdown) is set to be selected one.
So, <option> syntax:
<option value="value">Text</option>
If we want to make an option selected, use selected' attribute of`
<option value="value" selected="selected">Text</option>
So, in your case, solution would be:
1) Take value from database.
2) In the options loop, compare database value with current iteration <option> value.
3) If any of options' values are matching, use selected attribute of <option>
<select class="bootstrap-select show-tick" data-size="5" data-live-search="true" data-width="100%" name="TName1" required>
<option value="" disabled selected>Select Sub Account Name</option>
<?php foreach ($accName as $row ):
$selected = ($dbValueForDropDown == $row['id']) ? 'selected="selected"' : '';
?>
<option value="<?=$row['id']?>" <?php echo set_select('accName', $row['id']); ?> <?php echo $selected;?>><?=$row['accName']?></option>
<?php endforeach ?>
</select>
you should bring id and name of the accounts in the same results set by join in the query you send to the database and then run on the results and put the id in the value and the name in the display
<select class="bootstrap-select show-tick" data-size="5" data-live-search="true" data-width="100%" name="TName" required placeholder="select account name">
<option value="" disabled selected>Select Account Name</option>
<?php foreach ($accName as $row ):
$selected = '';
if($row['id'] == $result['code']){
$selected = 'selected = selected';
}
?>
<option <?php echo $selected; ?> value="<?=$row['id']?>" <?php echo set_select('accName', $row['id']); ?>>
<?=$row['accName']?></option>
<?php endforeach ?>
</select>

About Using Multi Select?

Hi I'm working on the code now and the ticket system sending a notification to a user that selects him about.
I want a notification to select more than one user and more than one user.
I tried to use this for Multi Select more than one user selection, again when I say save too, a single user is registering on this can you help me ?
<div class="form-group select-placeholder">
<label for="assigned" class="control-label">
<?php echo _l('ticket_settings_assign_to'); ?>
</label>
<select name="assigned" id="assigned" class="form-control selectpicker" data-live-search="true" data-none-selected-text="<?php echo _l('dropdown_non_selected_tex'); ?>" data-width="100%">
<option value=""><?php echo _l('ticket_settings_none_assigned'); ?></option>
<?php foreach($staff as $member){ ?>
<option value="<?php echo $member['staffid']; ?>" <?php if($member['staffid'] == get_staff_user_id()){echo '';} ?>>
<?php echo $member['firstname'] . ' ' . $member['lastname'] ; ?>
</option>
<?php } ?>
</select>
</div>
If you want to be able to select multiple you have to add the multiple attribute to the box.
<select multiple>
To receive the values in your code as an array you should change the name from name="assigned" to name="assigned[]"
This will send the multi selected data back as an array to PHP or whichever language you are using
<select multiple name="assigned[]" id="assigned" class="form-control selectpicker" data-live-search="true" data-none-selected-text="<?php echo _l('dropdown_non_selected_tex'); ?>" data-width="100%">
You have to put the multiple attribute in your <select> tag.
Note: The javascript there is used to avoid holding the ctrl-key while selecting multiple options.
window.onmousedown = function (e) {
var el = e.target;
if (el.tagName.toLowerCase() == 'option' && el.parentNode.hasAttribute('multiple')) {
e.preventDefault();
// toggle selection
if (el.hasAttribute('selected')) el.removeAttribute('selected');
else el.setAttribute('selected', '');
// hack to correct buggy behavior
var select = el.parentNode.cloneNode(true);
el.parentNode.parentNode.replaceChild(select, el.parentNode);
}
}
<select name="option-list" size="5" multiple>
<option value="option-1">Option</option>
<option value="option-2">Option</option>
<option value="option-3">Option</option>
<option value="option-4">Option</option>
<option value="option-5">Option</option>
<option value="option-6">Option</option>
<option value="option-7">Option</option>
<option value="option-8">Option</option>
<option value="option-9">Option</option>
</select>
I organized the code this way. But I couldn't get a successful result.
<div class="form-group select-placeholder">
<label for="assigned" class="control-label">
<?php echo _l('ticket_settings_assign_to'); ?>
</label>
<select multiple name="assigned[]" id="assigned" class="form-control selectpicker" data-live-search="true" data-none-selected-text="<?php echo _l('dropdown_non_selected_tex'); ?>" data-width="100%">
<option value=""><?php echo _l('ticket_settings_none_assigned'); ?></option>
<?php foreach($staff as $member){ ?>
<option value="<?php echo $member['staffid']; ?>" <?php if($member['staffid'] == get_staff_user_id()){echo '';} ?>>
<?php echo $member['firstname'] . ' ' . $member['lastname'] ; ?>
</option>
<?php } ?>
</select>
</div>

Whats the possibility of one updating a database field with a form having a drop down without changing the value of the drop down field

Lets say i input data into a mysql database using a drop down like:
<div>
<input name="name" type="text" id="name" placeholder="Enter Name"></div>
<div>
<select name="position" id="position" type="text">
<option selected="selected">Select</option>
<option value="A">A</option>
<option value="B">B</option>
<option value="C">C</option>
</select>
</div>
With a normal text field, i can simply include the value field to show on the form the initially entered data in the table. And change that so when i submit form, it updates the related field.
<div>
<select name="position" id="position" type="text" value="<?php echo $row_position['Position']; ?>>
<option selected="selected">Select</option>
<option value="A">A</option>
<option value="B">B</option>
<option value="C">C</option>
</select>
</div>
So assuming i do not want to update the field relating to the drop down, how do i it? Because what happens is, once i submit the form without selecting any option from the drop down, it picks the first option from the list which is the "Select" option and uses that to update the related field in the database.
I'd suggest at least two steps to make it user-friendly and achieve your goals:
First, make the initially entered selection selected if available:
<?php
$positions = Array("A", "B", "C");
?>
<div>
<select name="position" id="position">
<option value="-1">Select</option>
<?php
foreach($positions as $v) {
$selected = ($row_position['Position']===$v) ? "selected" : "";
echo "<option value='$v' $selected>$v</option>";
}
?>
</select>
</div>
And on the receiving php-script check if you've received a valid option, otherwise send error-message:
<?php
//other stuff...
if($_POST['position']>0) {
// save that value
} else {
// send error to user
}
// even more stuff..
?>
Notes: in select tag there is no type=text nor a value=anything available.
Assuming you are fetching dropdown options from database.
Note: Array keys, variables are only for demonstration purposes. This may differ from your actual records.
<div>
<select name="position" id="position">
<?php foreach($options as $option): ?>
<option value="<?= $option['position'] ?>" <?php if($option['position'] == $current_record['position']) { echo "selected"; } ?>> <!-- e.g. $option['id'] -->
<?= $option['name'] ?>
</option>
<? endforeach; ?>
</select>
</div>
What i have done that has solved the issue was to simply add the value from the database to the selectedoption or the first option field. So by default without changing the drop down, the first option with the value from the database is selected. And so there would be no change.
<div>
<div><?php echo $row_position['Position']; ?></div>
<select name="position" id="position">
<option value="<?php echo $row_position['Position']; ?>Select to Change</option>
<option value="A">A</option>
<option value="B">B</option>
<option value="C">C</option>
</select>
</div>
This gives a simple or straight forward solution to the problem.
Will still try the other suggestions to see how it all plays out. Thanks guys.

trying to display previously selected value in dropdown list php

I have made some code to create a dropdown in a webpage and you can select among 2 currency values namely USD and SGD. I have been able to get the value for the currency field while entering the data in the database. But while trying to edit the entry in the database, I am able to use $_POST to get all entries to display except the value of currency. I would ideally want to display the previously selected value on the dropdown. As of now the drop down on the edit page just displays the default "Please Choose" and doesn't show the previously selected value. any help would be greatly appreciated.
Code :
<select id="currency" name="currency" placehoder="Currency">
<option value='' disabled selected style='display:none;'>Please Choose</option>
<option value="SGD">SGD</option>
<option value="USD">USD</option>
</select>
And I am trying to somehow display the previously read value that exists in the database and display that instead of the "Please Choose" so that while editing I don't have to re-select the currency value.
Supposing you stored in $currency the value from DB:
<select id="currency" name="currency" placehoder="Currency">
<option value='' disabled style='display:none;'>Please Choose</option>
<option value="SGD"<?php echo $currency == "SGD" ? " selected" : ""; ?>>SGD</option>
<option value="USD"<?php echo $currency == "USD" ? " selected" : ""; ?>>USD</option>
</select>
Use PHP to Solve it..
<select name="select_limitby" onChange="frm_sub()">
<?php if($_SESSION[select_limitby]!='') { ?>
<option value="<?php echo $_SESSION[select_limitby]; ?>" <?php if($_POST[select_limitby]=='$_SESSION[select_limitby]') {?> selected="selected" <?php }?>><?php echo $_SESSION[select_limitby]; ?></option>
<?php } ?>
<option value="">Default</option>
<option value="9" <?php if($_POST[select_limitby]=='9') {?> selected="selected" <?php }?>>9</option>
<option value="12" <?php if($_POST[select_limitby]=='12') {?> selected="selected" <?php }?>>12</option>
<option value="15" <?php if($_POST[select_limitby]=='15') {?> selected="selected" <?php }?> >15</option>
</select>
USE session if it does not work...
otherwise you can leave session...

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