Laravel Routes not working for specific cases - php

any expert here ? This is a very strange problem I am facing.
I have my website hosted on an aws machine. The code was working absolutely fine there. Then it was shifted to another server and this strange problem staeted to appear.
I have a route to update a car
Route::put('vehicles/{vehicle}', 'VehicleController#update');
Edit form
{!! Form::model($vehicle, ['url' => ['backend/vehicles', $vehicle->id], 'method' => 'put','files' => true , 'class' => 'form-horizontal form-label-left', 'role' => 'form']) !!}
#include( 'backend.vehicles.form' )
{!! Form::close() !!}
Now here is where the strange behaviour start, whenever I try to update a car which was created prior to the server move, It shows me MethodNotAllowedHttpException in RouteCollection.php
But when I create a car and then updates this new car, Operation succeeds. Please help.
One more thing, In routeCollection.php where it matches a route for a request, It shows GET method for old car but put method for new car
public function match(Request $request){
// die($request->getMethod()); $routes = $this->get($request->getMethod());
$route = $this->check($routes, $request);
if (! is_null($route)) {
return $route->bind($request);
}
// If no route was found we will now check if a matching route is specified by
// another HTTP verb. If it is we will need to throw a MethodNotAllowed and
// inform the user agent of which HTTP verb it should use for this route.
$others = $this->checkForAlternateVerbs($request);
if (count($others) > 0) {
return $this->getRouteForMethods($request, $others);
}
throw new NotFoundHttpException;
}
Please anyone.

Add this inside the form
{{ method_field('PUT') }}
or in HTML
<input type="hidden" name="_method" value="PUT">

Please try the following solution:
Route::put('vehicles/{vehicle}', 'VehicleController#update');
Change to
Route::match(['put', 'patch'], 'vehicles/{vehicle}', 'VehicleController#update');
And the form to
{!! Form::model($vehicle, ['action' => ['VehicleController#update', $vehicle->id], 'method' => 'put','files' => true , 'class' => 'form-horizontal form-label-left', 'role' => 'form']) !!}
#include( 'backend.vehicles.form' )
{!! Form::close() !!}
Does it work for you?

Related

php change certain rows value with a button

I have abstracts table in my database with the Abstract_Status_ID column, I am trying to create a button that changes every Status from '2' to '3'
I have tried to do this:-
My controller
public function publish($A_ID)
{
$abstracts = Project::find($A_ID);
$abstracts->Abstract_Status_ID= 3;
$abstracts->save();
return redirect('/AdvertisedProjects')->with ('success', 'Abstracts Published' );
}
my route
Route::put( '/projects', 'AbstractsController#publish');
Route::post( '/projects', 'AbstractsController#publish');
my view (projects)
Tried with the csrf token and without as eloquent docs says any post/put will be restricted without it.
#if (count ($abstracts)> 0)
#foreach ($abstracts as $abstract)
#if($abstract->Abstract_Status_ID == 2)
{!! Form::open(['action' => ['AbstractsController#publish' , $abstract->A_ID], 'method' => 'post' ]) !!}
{{ csrf_field() }}
{{Form::hidden('_method', 'PUT') }}
{{Form::Submit('Submit Changes',['class' => 'btn btn-primary'])}}
{!! Form::close() !!}
#endif
#endforeach
The error I am getting when clicking the button
(1/1) ErrorException
Missing argument 1 for App\Http\Controllers\AbstractsController::publish()
Also, the code above will show more than one button, any suggestions to make one button change all of them ?
A: If you want to have a button for each ABSTRACTS just change your route to :
Route::put( '/projects/{A_ID}', 'AbstractsController#publish');
B: If you want to have only one button that change all , you can echo their ID in hidden input then send form
so your view would be:
#if (count ($abstracts)> 0)
{!! Form::open(['action' => ['AbstractsController#publish'], 'method' => 'post' ]) !!}
{{ csrf_field() }}
{{Form::hidden('_method', 'PUT') }}
#foreach ($abstracts as $abstract)
#if($abstract->Abstract_Status_ID == 2)
{{Form::hidden('abstract_ids[]', $abstract->A_ID) }}
#endif
#endforeach
{{Form::Submit('Submit Changes',['class' => 'btn btn-primary'])}}
{!! Form::close() !!}
And Your Controller :
public function publish()
{
foreach(request('abstract_ids') as $A_ID){
$abstracts = Project::find($A_ID);
$abstracts->Abstract_Status_ID= 3;
$abstracts->save();
}
return redirect('/AdvertisedProjects')->with ('success', 'Abstracts Published' );
}
You are using form method="POST". I think it should be method="PUT".
The main problem in your code is the definition of your routes, You are passing an argument ($A_ID) to the controllers publish method,
But in your routes, you did never mention that you are passing any argument through your route. So for passing the argument, you can use {$A_ID} in your route URL.
One thing you should always remember is that you should always give your route a name and call it by using its name and route() Laravel helper method.
The benefit of using route name is that if you decide to change the URL-Structure of your route later in the development process, you'll never have to change it everywhere in your application because you did not call it by its URL.
And route name is less error prone
In total, You should define your routes like this
Route::put('projects/{A_ID}/update', 'AbstractsController#publish')->name('projects.update');
Route::post('projects/{A_ID}/post', 'AbstractsController#publish')->name('projects.store');
Then in you blade files now you can call it like
{!! Form::open(['action' => route('projects.store', $abstract->A_ID), 'method' => 'post' ]) !!}
Hope this will clarify and resolve your problem.

User Submitted Posts Store function using Laravel

So in addition to my prior topic (thank you guys for helping) routes with compact
I am now facing troubles with my store function, I am getting the error : "Trying to get property of non-object.
This is my store function in my Controller
public function store(Request $request)
{
// validate the data
$this->validate($request, array(
'title' => 'required|max:255',
'body' => 'required'
));
// store in the database
$userpost = new Usp;
$userpost->title = $request->title;
$userpost->body = $request->body;
$userpost->save();
Session::flash('success', 'The blog post was successfully saved!');
return redirect()->route('admin.userposts.show', $userpost->id);
}
This is the view to create userpost(to make it more clear, p.s. the same form with different route ofcourse, works for my simple posts but not for my user submitted posts)
#extends('index')
#section('index-stylesheets')
{!! Html::style('css/parsley.css') !!}
#endsection
#section('content')
<h1>Create New User Post</h1>
<hr>
{!! Form::open(array('route' => 'admin.userposts.store', 'data-parsley-validate' => '')) !!}
{{ Form::label('title', 'Title:') }}
{{ Form::text('title', null, array('class' => 'form-control', 'required' => '', 'maxlength' => '255')) }}
{{ Form::label('body', "Post Body:") }}
{{ Form::textarea('body', null, array('class' => 'form-control', 'required' => '')) }}
{{ Form::submit('Create Post', array('class' => 'btn btn-success btn-lg btn-block', 'style' => 'margin-top: 20px;')) }}
{!! Form::close() !!}
#endsection
#section('index-scripts')
{!! Html::script('js/parsley.min.js') !!}
#endsection
Method of showing the post:
public function show($id)
{
$userpost = Usp::find($id);
return view('admin.userposts.show', compact('userpost'));
}
So the fact is that the problem was not the store method but the routes.
Route::get('/userposts/{id}', 'UserPostsController#show')->name('admin.userposts.show');
Route::get('/userposts/create', 'UserPostsController#create')->name('admin.userposts.create');
Route::post('/userposts/store', 'UserPostsController#store')->name('admin.userposts.store');
When registering the routes in that order, when laravel will iterate over your routes, it will first encounter the show one, and it will therefore take "create" as the id. Therefore, it will go into the show method and it won't find any post that matches, the post being null, you get the error.
So, there are two ways of fixing this.
The first one (the easiest, works in all cases, maybe not the best) is to put the create route before the show route.
The second one, the best in my opinion, is to add a condition to the id (doesn't work in the case of a slug). As the ids are only integers, you get :
Route::get('/userposts/{id}', 'UserPostsController#show')->name('admin.userposts.show')->where('id', '[0-9]+');
Therefore, create won't match the regular expression and it won't go in the show method.
For "resource creations" (storing in database), I wouldn't use a "field-by-field" method.
Instead, I'd do something like this :
$userpost = Usp::create($request->only('title', 'body'));
I feel this is more talkative.
But, it won't work, laravel protects* us against such things. To make it work, you have two options.
(The best option in my opinion)
In your model, add a protected variable called $fillable with all your columns that you allow to mass assign*. In this case you would put :
protected $fillable = ['name'];
(The option if you are sure of what are you doing)
In your model, you can say, hey, I know what I'm doing here, just let me do my stuff without guarding me. In this case you would put :
protected $guarded = [];
Notes :
$request->only('field1', ...) gives you an array of the fields that you want with the fields name as keys, in this case it gives you ['field1' => $request->field1]. In your case it will give you ['title' => $request->title, 'body' => $request->body].
Mass assignment is when you give an array to the model and it puts all attributes to the fields of the array. More informations here https://laravel.com/docs/5.4/eloquent#mass-assignment
When I mean laravel protects us against those things, it does't really protect us because it isn't a bad practice (instead, I find it more readable), but because it does allow you to make mistakes (for exemple, setting fields that don't exist).

Laravel 4 - NotFoundHttpException only on one custom route

I must be missing something really simple but I can't seem to find it. So I have my Resource defined in my routes.php but I need an additional route for an advanced search page with filters and stuff, my show/update/edit/create... pages are working perfectly but my search page isn't.
So in routes I have:
Route::resource('hostesses', 'HostessesController');
Route::get('/hostesses/search', 'HostessesController#search');
And I have a search form on my main page like this:
{{ Form::open(array('route' => 'hostesses.search', 'class' => 'navbar-form navbar-right')) }}
<div class="form-group">
{{ Form::text('search_term', '', array('class' => 'form-control')) }}
</div>
{{ Form::submit('Submit', array("class"=>'btn btn-default')) }}
{{ Form::close() }}
And when I use the search form I get the NotFoundHttpException
In my controller I have:
public function search()
{
return View::make('hostesses.search');
}
And I have created the template on views/hostesses/search.blade.php with a simple hello world message to check that it works, but I keep getting the exception!
Change the order of your routes and 'define' the named route of hostesses.search which is in your form
Route::any('/hostesses/search', array(['as' => 'hostesses.search', 'uses' => 'HostessesController#search');
Route::resource('hostesses', 'HostessesController');
Because what is happening is the resource for /hostesses/$id is capturing the search id, and returning an error that id of search does not exist
Also - change your route to Route::any(). This means it will respond to "get" and "post" requests.
However I would recommend splitting your route to be getSearch() and postSearch() functions and do this:
Route::get('/hostesses/search', array(['as' => 'hostesses.getsearch', 'uses' => 'HostessesController#getSearch');
Route::post('/hostesses/search', array(['as' => 'hostesses.postsearch', 'uses' => 'HostessesController#postSearch');
Route::resource('hostesses', 'HostessesController');
public function getSearch()
{
return View::make('hostesses.search');
}
public function postSearch()
{
// Do validation on form
// Get search results and display
}
And update your form
{{ Form::open(array('route' => 'hostesses.postsearch', 'class' => 'navbar-form navbar-right')) }}
You need to define a POST route:
Route::post('/hostesses/postSearch',array('as'=>'hostesses.search','uses' => 'HostessesController#postSearch'));
Then in your controller
public function postSearch()
{
var_dump(Input::get('search_term'));
}

Laravel 4: Use URI placeholders and query strings in form

I'm working on a website that searches a database of organizations. On the search page, there are two search fields: one for searching by record name, and one searching the organization's subjects.
Now, normally, I would have no problem setting up placeholders in my URIs.
Route::get('/search/{name}', function($name)
{
//code...
});
And I use the post route to attach the parameters
Route::post('/search', array( 'as' => 'results', function()
{
$string = Input::get('search');
return Redirect::to("/search/$string");
}));
And the Laravel form would have no problem...
<h4>Search by Name</h4>
{{ Form::open(array('url' => "search") )}}
<p>
<div class="input-group input-group-lg">
<span class="input-group-btn">
{{ Form::button('Search', array('class' => 'btn btn-default', 'type' => 'submit'))}}
</span>
{{ Form::text('search', '', array('class' => 'form-control', 'placeholder' => 'Search by name')) }}
</div>
</p>
{{ Form::close() }}
But how do I attach a query string to this part?
{{ Form::open(array('url' => "search") )}}
How I would like my code to behave is when a query string is present, it searches by subject, not name. Doing this:
{{ Form::open(array('url' => "search/?subject=true") )}}
Doesn't actually attach it to my url.
The one thing I could do is just have a hidden input that tells the code to search by subject and not name, but that would mean any users who go to the url again will get different results. I don't want that behavior.
Any help? Laravel documentation doesn't help and I can't seem to find anyone online with the same problem.
[edit]
I found the trick to putting it into the url is by attaching the query string on the Route::post() like so:
$string = Input::get('search');
$subject = Input::get('subject');
return Redirect::to("/search/$string?subject=$subject");
But then Laravel gives me a NotFoundHttpException even after I change the final route to
Route::get('/search/{name}?subject={subject}', function($name, $subject)
Try
Route::get('/search',function($name)
{
//code...
if(Input::has('subject'))
$subject = Input::get('subject');
...
});
Laravel Router system already adds all of your non-route parameters as queries, so if you have a router:
Route::get('/search/{name?}', ['as' => 'search', function($name)
{
//code...
}]);
And you do
return Redirect::route('search', ['name' => 'laracon', 'subject' => 'true']);
It will redirect to:
http://server/search/laracon?subject=true
And
return Redirect::route('search', ['subject' => 'true']);
To
http://server/search?subject=true
And, of course, inside your router you have access to both of them:
Route::get('/search/{name?}', ['as' => 'search', function($name)
{
var_dump(Input::get('name'));
var_dump(Input::get('search'));
}]);

MethodNotAllowedHttpException laravel-4

Form :
{{ Form::open(array('url' => 'user/create', 'files' => true)) }}
Route :
Route::resource('user', 'UserController');
UserController.php
class UserController extends BaseController {
public function index()
{
return 'hi11';
//return View::make('home.index');
}
public function create()
{
return 'hi22';
//return View::make('home.index');
}
}
This code gives
Symfony \ Component \ HttpKernel \ Exception \ MethodNotAllowedHttpException
I'd just like to add my own discovery along these lines... Maybe this will save someone else the head-scratching I just performed.
I too implemented the Route::resource mechanism. I couldn't figure out why my create was working but my update was not. It turns out you can't reuse the same form code exactly, the form that does an update must use the method PUT or PATCH. Why update couldn't be a POST is beyond me.
That is to say, the opening form tag for an update must look like this:
Form::model($thing, array(
'method' => 'PUT',
'route' => array('things.update', $thing->id)
)
Without specifying method => PUT, you get this not-helpful error.
Because in your roures you use resourse controller, you can use only specific paths and actions, described in documentation http://laravel.com/docs/controllers#resource-controllers.
user/create ( UserController::create ) is where you need to show the form for adding a new user.
The actual storage of the user should be done in user/store i.e. your form must be send data to UserController::store() method.
In your case if you POST your form only to 'url' => 'user', this should automatically send data to the correct method.
Laravel 4 resources have named routes - just use those:
{{ Form::open(array('route' => 'user.create', 'files' => true)) }}
this is how I'm doing it, it might help someone, can be improved, but this would be main idea.
#if(isset($data))
{{ Form::open(['route'=>['blog.update', isset($data) ? $data->slug : null],'method' => 'patch','role' => 'form', 'class' => 'blog-form form-horizontal']) }}
#else
{{ Form::open(['route'=>'blog.store','role' => 'form', 'class' => 'blog-form form-horizontal']) }}
#endif

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