Convert the curl example to Requests util usage - php

Question

I use the Requests for http request:
I also package it to a util function:
function http_util($url, $params, $add_headers = null, $base_url = null ){
$headers = array('Accept'=>'application/json');
if($add_headers){
$headers = array_merge($headers, $add_headers);
}
if($base_url) {
$url = $base_url . $url;
}
$request = Requests::post($url, $headers, $params);
return $request;
}
but I found, such as the curl example:
curl -X POST -d "grant_type=password&username=<user_name>&password=<password>" -u"<client_id>:<client_secret>" http://localhost:8000/o/token/
if the curl example convert to use my http_util, how to use? I am not sure whether my http_util will have more optimize action. and how to use the http_util request the curl example?

Answer 1

You cant use it as-is you'll need to add the $options param as noted in the docs: http://requests.ryanmccue.info/docs/authentication.html
The "util" function is simply setting a content Accept header. Not worth writing a function for that.
$result = Requests::post('http://localhost:8000/o/token' [
// headers
'Accept' => 'application/json'
], [
// data
'grant_type' => 'password',
'username' => '<user_name>',
'password' => '<password>',
], [
// options
'auth' => new Requests_Auth_Basic(['<client_id>', '<client_secret>'])
]);