php remove duplicate values and show one - php

Question

<?php
include ("../pos/db_config/db_config.php");
include ("../pos/functions/select.php");
$i = 0;
$sql = topsalep($idCompany);
$result = $conn->query($sql);
while($row = $result->fetch_assoc()) {
$end_sale_date = $row["end_sale_date"];
$name = $row["name"];
$tot_s = $row["tot_price"];
$qc = $row["sales_item_qty"];
$proResult[$i][0] = $name;
$proResult[$i][1] = $end_sale_date;
$proResult[$i][2] = $tot_s;
$proResult[$i][3] = $qc;
$i++;
}
//$name = $proResult[0][0];
//echo "$name";
for ($i = 0; $i < $result->num_rows; $i++) {
$count = 0;
$name = $proResult[$i][0];
$date = $proResult[$i][1];
$price = $proResult[$i][2];
$qct = $proResult[$i][3];
$totalPrice = 0;
for ($j = 0; $j < $result->num_rows; $j++) {
if ($proResult[$j][1] == $date && $proResult[$j][0] == $name) {
$x = $proResult[$j][2];
$count++;
$totalPrice+=$x;
}
}
$name = $proResult[$i][0];
$date = $proResult[$i][1];
$price = $proResult[$i][2];
for ($k = 0; $k < $count; $k++){
if($proResult[$k][1] == $date && $proResult[$k][0] == $name)
{
}
}
echo "Name : $name <br>";
echo "End Date : $date : Count $count : total = $totalPrice <br><br>";
?>
In this code I showed Last 5 days product vise total value. A one day can happen same sale id there different quantity of products. Then finally I calculated the one product wise total sale value. But problem is duplicate it.
In my join query I used distinct But I want show my PHP code when duplicated values only show one value.
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