Laravel sort and save position in database - php

Question

I have a table in my database called 'users', it has these columns:
id, points, rank.
Everytime I update points, I want to sort all users by points desc and save rank position in that column.
I was wondering about getting all rows from database, sort them by using collection method and using update to update rank column. But i was wondering about how intense it would be to update 100k users one by one.
Maybe some experienced Laravel developers can suggest me a best possible solution in this situation?

Answer 1

If you want data orderred by points you can use
$user = User::orderBy('point', 'desc')
->get();

Answer 2

Alright the things you need here is an Eloquent Observer so each time you update the points on update it will sort all the users by points desc and save the rank position.
However with that amout of data I would never use collections or anything simillar as it will be slow, I suggest you using raw methods to do that.
Now there are two possible options if latency matters on this case then you can place all the logic in the observer itself like below:
First of seperate the observer logic to a different class like:
namespace App\Observers;
class UserRankObserver
{
public function updated($model)
{
//check if points column its updated
//if yes then run the query to sort all user by points and save rank
}
}
Then on your User model you need to register the observer like :
public static function boot()
{
parent::boot();
User::observe(new \App\Observers\UserRankObserver);
}
Case two when the latency does not matter then I suggest on the method updated I would just pass the data to a background job to complete the action like :
namespace App\Observers;
class UserRankObserver
{
public function updated($model)
{
//check if points column its updated
//if yes then pass the data to a background job to complete the task.
(new UpdateUserRankJob($data))->dispatch();
}
}