php sql code not inserting into db - php

Question

I'm new to php and a complete noob. I used following code to insert some files to my db.
<?php
include_once 'dbconfig.php';
if(isset($_POST['btn-upload']))
{
$file = rand(1000,100000)."-".$_FILES['file']['name'];
$file_loc = $_FILES['file']['tmp_name'];
$file_size = $_FILES['file']['size'];
$file_type = $_FILES['file']['type'];
$folder="uploads/";
$new_size = $file_size/1024;
$new_file_name = strtolower($file);
$final_file=str_replace(' ','-',$new_file_name);
if(move_uploaded_file($file_loc,$folder.$final_file))
{
$sql = "INSERT INTO tbl_uploads(file,type,size) VALUES('$final_file','$file_type','$new_size')";
//mysql_query($sql, $conn);
?>
<script>
alert('successfully uploaded');
window.location.href='index.php?success';
</script>
<?php
}
else
{
?>
<script>
alert('error while uploading file');
window.location.href='index.php?fail';
</script>
<?php
}
}
?>
Though this save the file in upload folder, it does not insert anything into the data base. No matter how many times its uploaded database remain empty. It doesn't show any error either.
My config.php file is
<?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$dbname = "dbtuts";
$conn = new mysqli($dbhost, $dbuser, $dbpass);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
?>
HTML part
<form action="upload.php" method="post" enctype="multipart/form-data">
<input type="file" name="file" />
<button type="submit" name="btn-upload">upload</button>
</form>

Answer 1

No DB is selected
<?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$dbname = "dbtuts";
$conn = new mysqli($dbhost, $dbuser, $dbpass, $dbname); // <--- here select db first
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
?>
Then use
<?php
include_once 'dbconfig.php';
if(isset($_POST['btn-upload']))
{
$file = rand(1000,100000)."-".$_FILES['file']['name'];
$file_loc = $_FILES['file']['tmp_name'];
$file_size = $_FILES['file']['size'];
$file_type = $_FILES['file']['type'];
$folder="uploads/";
$new_size = $file_size/1024;
$new_file_name = strtolower($file);
$final_file=str_replace(' ','-',$new_file_name);
if(move_uploaded_file($file_loc,$folder.$final_file))
{
$sql = "INSERT INTO tbl_uploads(file,type,size) VALUES('$final_file','$file_type','$new_size')";
if($conn->query($sql)) {
echo "Success";
} else {
echo "Failed. Error: ".$conn->error;
}
?>
<script>
alert('successfully uploaded');
window.location.href='index.php?success';
</script>
<?php
}
else
{
?>
<script>
alert('error while uploading file');
window.location.href='index.php?fail';
</script>
<?php
}
}
?>

Answer 2

I think, your sql can not get variable
You try to write like that:
$sql = "INSERT INTO tbl_uploads(file,type,size) VALUES('$final_file','$file_type','$new_size')";

Answer 3

Try this
$sql = "INSERT INTO tbl_uploads(file,type,size) VALUES('$final_file','$file_type','$new_size')";
mysqli_query($conn,$sql);