Send image to other page using $.post() method - php

Question

I have two pages first page has a form which accepts information like name,mobile-no etc and an image from user.
I want to access the image using jquery and send it other page using $.post() method there i want to access the image and insert it into database
First File
<script>
$(function(){
$("#add_staff").click(function(){
event.preventDefault();
var regex_mobile=/^\d{10}$/;
var regex_email = /^([a-zA-Z0-9_\.\-\+])+\#(([a-zA-Z0-9\-])+\.)+([a-zA-Z0-9]{2,4})+$/;
var insti=$("#inst_id").val();
var name=$("#Staff_name").val();
var pwd=$("#Staff_pwd").val();
var add=$("#staff_address").val();
var dob=$("#Staff_dob").val();
var mail=$("#Staff_mail").val();
var role=$("#Staff_role").val();
var mobile=$("#Staff_mobile").val();
var img = $('#image').prop('files')[0];
if(name=="" || pwd=="" || add=="" || dob=="" || mail=="" || role=="" || mobile=="")
{
alert("All fields are compulsory");
}
else{
if(!regex_mobile.test(mobile)) {
alert("Mobile Number invalid");
}
else if(!regex_email.test(mail)){
alert("Email Invalid");
}
else{
$.post("add_faculty2.php",
{
insti: insti,
name:name,
pwd:pwd,
add:add,
dob:dob,
mail:mail,
role:role,
mobile:mobile,
img:img
},
function(data,status){
$("#msg").text(data);
alert(data);
alert(status);
});
}
});
});
</script>
In the above file all the information is accepted from the user and in the jquery i have tried to access all the information and image then i am trying to send the data to other page using $.post() method.
Second File
<?php
$insti =$_POST['insti'];
$name =$_POST['name'];
$pwd =$_POST['pwd'];
$add =$_POST['add'];
$dob =$_POST['dob'];
$mail =$_POST['mail'];
$role =$_POST['role'];
$mobile =$_POST['mobile'];
$img =$_POST['img'];
$today = date("Y-m-d H:i:s");
include_once 'conf.php';
$q="insert into tbl_staff_details(inst_id,name,pwd,email,phone,photo,address,dob,role,created_date) values('".$insti."','".$name."','".$pwd."','".$mail."','".$mobile."','".$img."','".$add."','".$dob."','".$role."','".$today."')";
echo $q;
$r=mysqli_query($con,$q);
if($r)
{
echo "Success";
}
else
{
echo "Fail";
}
?>
In the above file i am accessing all the information using $_POST[] sent by the $.post() method in the first file then i am trying to insert all the data in the database
Problem is that the data is not inserted in the database
But when i omit the image all the other data is inserted in the database

Answer 1

Ok first you need to use FormData() in your javascript
example
// formdata
var formdata = FormData();
var insti=$("#inst_id").val();
var name=$("#Staff_name").val();
var pwd=$("#Staff_pwd").val();
var add=$("#staff_address").val();
var dob=$("#Staff_dob").val();
var mail=$("#Staff_mail").val();
var role=$("#Staff_role").val();
var mobile=$("#Staff_mobile").val();
var img = $('#image').prop('files')[0];
formdata.append('upload[insti]', insti);
formdata.append('upload[name]', name);
formdata.append('upload[pwd]', pwd);
formdata.append('upload[add]', add);
formdata.append('upload[dob]', dob);
formdata.append('upload[mail]', mail);
formdata.append('upload[role]', role);
formdata.append('upload[mobile]', mobile);
formdata.append('upload[img]', img);
// now send
$.post("add_faculty2.php", formdata,
function(data,status){
$("#msg").text(data);
alert(data);
alert(status);
}
);
And in your php script you can access the image by calling
$img = $_FILES['upload']['img']['name'];
$img_tmp = $_FILES['upload']['img']['tmp_name'];
others
$insti = $_POST['upload']['insti'];
$name = $_POST['upload']['name'];
$pwd = $_POST['upload']['pwd'];
$add = $_POST['upload']['add'];
$dob = $_POST['upload']['dob'];
$mail = $_POST['upload']['mail'];
$role = $_POST['upload']['role'];
$mobile = $_POST['upload']['mobile'];
$today = date("Y-m-d H:i:s");
// you can see the image printed here..
var_export($img);
Hope this helps.