I have a smarty project, and in the .tpl file, there is a form:
<form method="get" action="{$smarty.server.PHP_SELF}?action=func1">
<input type="text" name="username"/>
<input type="submit">
</form>
there is a question, if the php file have many function for different action requests, so in the template if have many forms, I want to through the action for distinguish.
but in my practice, see upper code, I write like this, this can not delivery the action to my php file.
I want to write the action in the form action, because this can be more standard. so I don't want to write it in a hidden input. why write in the action can not pass into the php file?
You could use submit button with specified name and value:
<form method="get" action="{$smarty.server.PHP_SELF}">
<input type="text" name="username" />
<input type="submit" name="action" value="func1" />
</form>
and then you'll get a global variable $_POST['action'] with value func1. But the value will be showing on your button title, so I offer you to find forms only by submit name, for example name='submit_form1'.
Related
I have a php page with a form which I want to search the user database from for a username match. This is my code:
<form id="searchuser" name="searchuser" method="post" action="">
Enter a username to search for:
<label>
<input type="text" name="uname" id="uname" />
</label>
<label>
<input type="submit" name="submit" id="submit" value="Search" />
</label>
<p> </p>
</form>
Do I need to put setcookie() in the action?
The action field of a form should contain URL (relative or absolute) of the php script which the browser will navigate into while passing the form fields as a POST request.
For example, you can create a php script named search.php, set action="search.php" in the form and then access the fields of the form in that script using $_POST['uname'] for example.
Not sure what you need to set the cookies for in this form but to set a cookie you need to put the setcookie() call somewhere in your php script, NOT in the HTML code. Also you need to call the setcookie() before any HTML output in your php script.
I need little help i am making an upload page, so i have two different forms and two different action
form is ajax picture upload (profile picture of user) its working fine action is action='ajaximage.php'
form is simple user info details like Name,Bio, etc etc. its also working fine.. and its action is action="add.php"
Doubt/Problem
In my website input boxes are not arranged orderly because of the design.
<form id="form" method="post" enctype="multipart/form-data" action='add.php'>
<b>Tittle</b>
<input type="text" name="name">
</form>
<form id="imageform" method="post" enctype="multipart/form-data" action='ajaximage.php'>
<input type="file" title="Choose Image" name="photoimg" id="photoimg">
</form>
<form id="form" method="post" enctype="multipart/form-data" action='add.php'>
<b>Description</b>
<textarea name="description" rows="1" cols="1"></textarea>
<button input="submit">Save Changes</button>
</form>
Ajax image uploader is working but in case of add.php it is working only for Description.
I cannot change the design so how can it be solved ?? Please Help
You need one submit button for each form. A submit button will just submit the form it is in.
#bwoebi is right about the submits but I'd be very surprised if your arrangement would work anyway. By my reckoning you have 3 forms. Just using the same name again wouldn't work. A single form needs to be distinct - unless you want to do a whole lot of javascript processing on submit. Have another look at fixing your layout to keep forms together.
Just saw your comments above. Why have separate forms with separate actions anyway? Why not have one form with one action that simply does both the file upload and adds the details (presumably to a database)?
You could also simply have different submit buttons on your form and add an onclick attribute to each setting the action for the form to be different:
<input type="submit" name="sub1" value="Upload Image" onclick="document.myform.action='ajaximage.php';">
<input type="submit" name="sub2" value="Add User" onclick="document.myform.action='add.php';">
This means the form action will be changed depending on which submit button is used .
To upload images via ajax you do not need to submt a form, that is the whole point of doing it via ajax. You can upload the image, and then submit the form for the text inputs.
pseudocode:
<form id="form" method="post" enctype="multipart/form-data" action='add.php'>
<input name="name"/>
<input name="profilePic" id="profilePic"/>
<input name="descrption"/>
</form>
You can then use javascript(I prefer jQuery) to upload your image via ajax, specifying #profilePic.
Also, you should look at: http://blueimp.github.io/jQuery-File-Upload/
I am using a button to function in the same way as a hyperlink:
<form action="intro.html"><input type="submit" value="CLICK HERE TO ENTER" ></form>
This works for static links, but does not work with PHP $_GET arguments.
<form action="wrong_choice.php?stage=0"><input type="submit" value="Wrong Choice!" ></form>
Clicking that will proceed to "wrong_choice.php" but not "wrong_choice.php?stage=0"
How can I fix that?
Thank you
Better to use:
<input type="button" value="Wrong Choice!" onClick="document.location.href('wrong_choice.php?stage=0');" />
If you do not want javascript, add method to form, delete parameter from action and add input with type hidden, which stands for parameter.
Action does not accept query string!
If you want to append data into the form which isn't part of the inputs filled by the user, add inside the <form>
<input type="hidden" name="stage" value="0" />
Action is what you want to do with the information in the form: you want to send the form in a email or send the information to another script to manage or comeback to same script.
If you want pass arguments in the form you should put them in form's fields like that:
<form action="wrong_choice.php>
<input type='hidden' value='0' name="stage">
<input type="submit" value="Wrong Choice!" >
</form>
Thanks
For my php file, I need to grab the unique form name.
The php file is executed when a user clicks the submit button. However, there are multiple submit button each with the same id, but they all have unique names. I need the name when they click on the submit button.
you dont want elements in html with the same id - bad practice in general. Your page will likely load normally but an html validator will notice it as an error.
html validator: http://validator.w3.org/
without seeing your code, its difficult to give you a definitive answer. if you have miltuple forms you can use hidden inputs. e.g.
<input type="hidden" name="form_name" />
Otherwise you can use javascript to put data in the form when the button is clicked. example javascript using jquery
html:
<form id="formid" >
<button type="button" id="someid" onclick="submitForm('btn1')" />
<button type="button" id="someid" onclick="submitForm('btn2')" />
<input type="hidden" id="btnsubmitid" value="" />
</form>
js:
function submitForm(btnID){
$("#btnsubmitid").val(btnID);
$("#formid").submit();
}
1 way is to put a hidden input inside of your form.
<input type="hidden" name="formName" value="[name of form]" />
then in your php, you can get it using
$form-name = $_POST['formName'];
pretty sure there are other ways, but this came to mind first.
In a php-script i have a form, method is post, action-attribute is empty, which is working so far. but when i add a value into the action-atribute, like so:
action="index.php?id=9&get-id=5"
the whole post-array is empty after submitting.
Someone has any idea what this could be about?
Thanx in advance, Jayden
edit: here is an Example:
$form = '<form name="form1" method="post" enctype="multipart/form-data" action="index.php?id=9&get-id=5">
<input type="text" name="name1" value="">
<input name="submit" type="submit" value="submit">
</form>';
The form is displayed in a tab in a js-tabmenu, which opens also by get-parameters, in each tab is a form and after submitting the get-param is needed to display the right tab with the right form.
try to use $_REQUEST
which is collection of $_GET and $_POST
You should not use both GET and POST in a request.
You must only use post, therefore the two variables 'id' and 'get-id' should be in the form (use hidden fields)
edit:
try changing your code to:
<form name="form1" method="post" enctype="multipart/form-data"
action="index.php?id=9&get-id=5">
<input type="hidden" name="id" value="9">
<input type="hidden" name="get-id" value="5">
<input type="text" name="name1" value="">
<input name="submit" type="submit" value="submit">
</form>
then if you :
print_r($_POST);
at the top of the index.php page you should be able to see what is going on.
Also - just to check are there any redirects in your code, ie does index.php then redirect somewhere else as that would cause the $_POST to get lost
If you're trying to access id or get-id from your script: Those were appended to the url, even if you submit that form via post. Therefore you will find their values in $_GET, as usual. Only the values of <input> fields (and textarea etc., simply: all form elements) are in $_POST.