PHP array to specified json structure - php

Question

I need to get an JSON structure as following:
{
"emails": [
{
"sender": "shihas#abc.com",
"unread_count": 2,
"items": [
{
"id": "89",
"email": "shihas#abc.com",
"read": "0",
},
{
"id": "32",
"email": "shihas#abc.com",
"read": "0",
}
]
},
{
"sender": "marias123#gmail.com",
"unread_count": 0,
"items": [
{
"id": "2",
"email": "marias123#gmail.com",
"read": "1",
}
]
},
{
"sender": "gutar4320#hotmail.com",
"unread_count": 1,
"items": [
{
"id": "1",
"email": "gutar4320#hotmail.com",
"read": "0",
}
]
}
]
}
Array($hire_email):
In the below array I need to group all the details based on the email. And also count the no. of unread messages(i.e read = 0).
Array
(
[0] => Array
(
[id] => 89
[email] => shihas#abc.com
[read] => 0
)
[1] => Array
(
[id] => 32
[email] => shihas#abc.com
[read] => 0
)
[2] => Array
(
[id] => 2
[email] => marias123#gmail.com
[read] => 1
)
[3] => Array
(
[id] => 1
[email] => gutar4320#hotmail.com
[read] => 0
)
)
The following is the code snippet used for maintaining the JSON structure.
foreach($hire_email as $val) {
if($val['read']==0){ $count++; }else{ $count = 0;}
$hire_group_email[$val['email']]['sender'] = $val['email'];
$hire_group_email[$val['email']]['unread_count'] = $count;
$hire_group_email[$val['email']]['items'][] = $val;
}
$output["emails"][] = $hire_group_email;
echo json_encode($output);

Answer 1

This should do the trick.
$hire_email =array(
array(
"id" => "89",
"email" => "shihas#abc.com",
"read" => "0"
),
array
(
"id" => "32",
"email" => "shihas#abc.com",
"read" => "0"
),
array
(
"id" => "2",
"email" => "marias123#gmail.com",
"read" => "1"
),
array
(
"id" => "1",
"email" => "gutar4320#hotmail.com",
"read" => "0"
)
);
$tmp = array();
foreach($hire_email as $arg)
{
$tmp[$arg['email']][] = $arg;
}
$output = array();
foreach($tmp as $type => $labels)
{
$count = 0;
foreach ($labels as $value) {
if($value['read']==0){ $count++; }else{ $count = 0;}
}
$output[] = array(
'sender' => $type,
'unread_count' => $count,
'items' => $labels
);
}
echo json_encode($output);

Answer 2

Try doing it like this, using: array_sum and array_column, the rest is just picking out the first items values.
$array = json_decode($json, true)['emails'];
$result = [];
foreach($array as $val) {
$result[] = [
'id' => $val['items'][0]['id'],
'email' => $val['items'][0]['email'],
'read' => array_sum(array_column($val['items'], 'read'))
];
}
$output["emails"] = $result;
echo json_encode($output, JSON_PRETTY_PRINT);
Result:
{
"emails": [
{
"id": "89",
"email": "shihas#abc.com",
"read": 0
},
{
"id": "2",
"email": "marias123#gmail.com",
"read": 1
},
{
"id": "1",
"email": "gutar4320#hotmail.com",
"read": 0
}
]
}
https://3v4l.org/hi7qm
And if you want it as shown ;p (my mistake, misread it):
Loop over each item, then loop over the items and use that to build the output.
$array = json_decode($json, true)['emails'];
$result = [];
foreach($array as $val) {
foreach ($val['items'] as $item) {
$result[] = [
'id' => $item['id'],
'email' => $item['email'],
'read' => array_sum(array_column($val['items'], 'read'))
];
}
}
$output["emails"] = $result;
echo json_encode($output, JSON_PRETTY_PRINT);
Result:
{
"emails": [
{
"id": "89",
"email": "shihas#abc.com",
"read": 0
},
{
"id": "32",
"email": "shihas#abc.com",
"read": 0
},
{
"id": "2",
"email": "marias123#gmail.com",
"read": 1
},
{
"id": "1",
"email": "gutar4320#hotmail.com",
"read": 0
}
]
}
https://3v4l.org/eU95A