I'm trying to make a search feature that will search multiple columns to find a keyword based match. This query:
SELECT title FROM pages LIKE %$query%;
works only for searching one column, I noticed separating column names with commas results in an error. So is it possible to search multiple columns in mysql?
If it is just for searching then you may be able to use CONCATENATE_WS.
This would allow wild card searching.
There may be performance issues depending on the size of the table.
SELECT *
FROM pages
WHERE CONCAT_WS('', column1, column2, column3) LIKE '%keyword%'
You can use the AND or OR operators, depending on what you want the search to return.
SELECT title FROM pages WHERE my_col LIKE %$param1% AND another_col LIKE %$param2%;
Both clauses have to match for a record to be returned. Alternatively:
SELECT title FROM pages WHERE my_col LIKE %$param1% OR another_col LIKE %$param2%;
If either clause matches then the record will be returned.
For more about what you can do with MySQL SELECT queries, try the documentation.
If your table is MyISAM:
SELECT *
FROM pages
WHERE MATCH(title, content) AGAINST ('keyword' IN BOOLEAN MODE)
This will be much faster if you create a FULLTEXT index on your columns:
CREATE FULLTEXT INDEX fx_pages_title_content ON pages (title, content)
, but will work even without the index.
1)
select *
from employee em
where CONCAT(em.firstname, ' ', em.lastname) like '%parth pa%';
2)
select *
from employee em
where CONCAT_ws('-', em.firstname, em.lastname) like '%parth-pa%';
First is usefull when we have data like : 'firstname lastname'.
e.g
parth patel
parth p
patel parth
Second is usefull when we have data like : 'firstname-lastname'. In it you can also use special characters.
e.g
parth-patel
parth_p
patel#parth
Here is a query which you can use to search for anything in from your database as a search result ,
SELECT * FROM tbl_customer
WHERE CustomerName LIKE '%".$search."%'
OR Address LIKE '%".$search."%'
OR City LIKE '%".$search."%'
OR PostalCode LIKE '%".$search."%'
OR Country LIKE '%".$search."%'
Using this code will help you search in for multiple columns easily
SELECT * FROM persons WHERE (`LastName` LIKE 'r%') OR (`FirstName` LIKE 'a%');
Please try with above query.
I have a MySQL problem. This is just an example just to solve my real problem. Let's say I have a table like this:
Columns: id, name, classes.
Classes field is comma separated value like 1,4,5,4
I know database design is wrong and very bad.
What I want to do is select name where class is equal to 4 whereas the classes field has value 3,4,6,3,8 in MySQL. How can I do that?
You could use the FIND_IN_SET function in MySQL
SELECT name
FROM table_name
WHERE FIND_IN_SET('4',classes) > 0
use of find_in_set function like below-
select * from table_name where find_in_set('4',classes);
Hello everyone as the topic says I am looking for alternative or advanced using of "LIKE".
I have column which contains a row of words p.e. "keyword1,keyword2,another_keyword" and when I use
$sql = mysql_query("SELECT * FROM table WHERE `column` LIKE '%keyword1%' ");
It hardly find it p.e. this example works but when i try to find shorter strings it has problems and sometimes it does not find anything.
I tried put a whitespace after comas and it helped but if there is a way where I can search for match with this specification of column I would be happy.
You may move keywords into individual table.
Or you can use SET field type, if the list of your keywords don't change.
Storing comma separated list of your words is a bad idea example using like in your scenario is hard to find the exact work in comma separated list instead you can add new table which relates to your current table and store each the word in a new row with the associated identity like
table1
id title
1 test1
2 test2
kewords_table
table1_id word
1 word1
1 word2
1 word3
and query will be
select t.*
from table1 t
join kewords_table k
on(t.id = k.table1_id)
where k.word = 'your_keyword'
If you can't alter your structure you can use find_in_set()
SELECT * FROM table WHERE find_in_set('your_keyword',`column`) > 0
try something like this:
SELECT * FROM tablename
WHERE column LIKE '%keyword1%'
OR column LIKE '%keyword2%';
for more info see here:Using SQL LIKE and IN together
MySQL allows you to perform a full-text search based on very complex queries in the Boolean mode along with Boolean operators. This is why the full-text search in Boolean mode is suitable for experienced users.
First You have to add FULLTEXT index to that perticuler column :
ALTER TABLE table_name ADD search_column TEXT CHARACTER SET utf8mb4 COLLATE utf8mb4_general_ci NULL DEFAULT NULL, ADD FULLTEXT search_column (search_column);
Run following query for searching :
SELECT * FROM table WHERE MATCH(search_column) AGAINST("keyword1")
for more info see here : https://dev.mysql.com/doc/refman/8.0/en/fulltext-boolean.html
So I think I completely misunderstood how FIND_IN_SET work
SELECT
u.*, p.*
FROM
users u
INNER JOIN profiles p ON p.user_id = u.id
WHERE
FIND_IN_SET('1,4,7', p.fruits)
This is not working as I thought it would.
1,4,7 represent the fruits selected by the user to search
p.fruits can look something like this 1,2,3,4,5,6,7 or 5,6,7 or 1,6,7 etc
Basically I want to find the records if any of the values in the first argument match any of the values in the second argument.
Is this possible?
if your p.fruits column is a varchar (which is not ideal for this situation, but if it is so) your query will be like
where … ( concat(',', p.fruits , ‘,’) like ‘%,1,%’
or concat(',', p.fruits , ‘,’) like ‘%,4,%’ or concat(',',p.fruits , ‘,’) like ‘%,7,%’ ) ...
this won't be good for indexes since concatenation will disable usage of indexes ..
better solution would be turn the column into a set and do the query like Michael's above ..
or you can create a new table called user_fruits(fk_user_id int, fruit_id int) and create unique index on both fields and do the search in user_fruits table
Use FIELD instead of that.
FIELD(p.fruits, 1,4,7)
You should refer to this article:
10 things in MySQL (that won’t work as expected)
I have a column in one of my table where I store multiple ids seperated by comma's.
Is there a way in which I can use this column's value in the "IN" clause of a query.
The column(city) has values like 6,7,8,16,21,2
I need to use as
select * from table where e_ID in (Select city from locations where e_Id=?)
I am satisfied with Crozin's answer, but I am open to suggestions, views and options.
Feel free to share your views.
Building on the FIND_IN_SET() example from #Jeremy Smith, you can do it with a join so you don't have to run a subquery.
SELECT * FROM table t
JOIN locations l ON FIND_IN_SET(t.e_ID, l.city) > 0
WHERE l.e_ID = ?
This is known to perform very poorly, since it has to do table-scans, evaluating the FIND_IN_SET() function for every combination of rows in table and locations. It cannot make use of an index, and there's no way to improve it.
I know you said you are trying to make the best of a bad database design, but you must understand just how drastically bad this is.
Explanation: Suppose I were to ask you to look up everyone in a telephone book whose first, middle, or last initial is "J." There's no way the sorted order of the book helps in this case, since you have to scan every single page anyway.
The LIKE solution given by #fthiella has a similar problem with regards to performance. It cannot be indexed.
Also see my answer to Is storing a delimited list in a database column really that bad? for other pitfalls of this way of storing denormalized data.
If you can create a supplementary table to store an index, you can map the locations to each entry in the city list:
CREATE TABLE location2city (
location INT,
city INT,
PRIMARY KEY (location, city)
);
Assuming you have a lookup table for all possible cities (not just those mentioned in the table) you can bear the inefficiency one time to produce the mapping:
INSERT INTO location2city (location, city)
SELECT l.e_ID, c.e_ID FROM cities c JOIN locations l
ON FIND_IN_SET(c.e_ID, l.city) > 0;
Now you can run a much more efficient query to find entries in your table:
SELECT * FROM location2city l
JOIN table t ON t.e_ID = l.city
WHERE l.e_ID = ?;
This can make use of an index. Now you just need to take care that any INSERT/UPDATE/DELETE of rows in locations also inserts the corresponding mapping rows in location2city.
From MySQL's point of view you're not storing multiple ids separated by comma - you're storing a text value, which has the exact same meaing as "Hello World" or "I like cakes!" - i.e. it doesn't have any meaing.
What you have to do is to create a separated table that will link two objects from the database together. Read more about many-to-many or one-to-many (depending on your requirements) relationships in SQL-based databases.
Rather than use IN on your query, use FIND_IN_SET (docs):
SELECT * FROM table
WHERE 0 < FIND_IN_SET(e_ID, (
SELECT city FROM locations WHERE e_ID=?))
The usual caveats about first form normalization apply (the database shouldn't store multiple values in a single column), but if you're stuck with it, then the above statement should help.
This does not use IN clause, but it should do what you need:
Select *
from table
where
CONCAT(',', (Select city from locations where e_Id=?), ',')
LIKE
CONCAT('%,', e_ID, ',%')
but you have to make sure that e_ID does not contain any commas or any jolly character.
e.g.
CONCAT(',', '6,7,8,16,21,2', ',') returns ',6,7,8,16,21,2,'
e_ID=1 --> ',6,7,8,16,21,2,' LIKE '%,1,%' ? FALSE
e_ID=6 --> ',6,7,8,16,21,2,' LIKE '%,6,%' ? TRUE
e_ID=21 --> ',6,7,8,16,21,2,' LIKE '%,21,%' ? TRUE
e_ID=2 --> ',6,7,8,16,21,2,' LIKE '%,2,%' ? TRUE
e_ID=3 --> ',6,7,8,16,21,2,' LIKE '%,3,%' ? FALSE
etc.
Don't know if this is what you want to accomplish. With MySQL there is feature to concatenate values from a group GROUP_CONCAT
You can try something like this:
select * from table where e_ID in (Select GROUP_CONCAT(city SEPARATOR ',') from locations where e_Id=?)
this one in for oracle ..here string concatenation is done by wm_concat
select * from table where e_ID in (Select wm_concat(city) from locations where e_Id=?)
yes i agree with raheel shan .. in order put this "in" clause we need to make that column into row below code one do that job.
select * from table where to_char(e_ID)
in (
select substr(city,instr(city,',',1,rownum)+1,instr(city,',',1,rownum+1)-instr(city,',',1,rownum)-1) from
(
select ','||WM_CONCAT(city)||',' city,length(WM_CONCAT(city))-length(replace(WM_CONCAT(city),','))+1 CNT from locations where e_Id=? ) TST
,ALL_OBJECTS OBJ where TST.CNT>=rownum
) ;
you should use
FIND_IN_SET Returns position of value in string of comma-separated values
mysql> SELECT FIND_IN_SET('b','a,b,c,d');
-> 2
You need to "SPLIT" the city column values. It will be like:
SELECT *
FROM table
WHERE e_ID IN (SELECT TO_NUMBER(
SPLIT_STR(city /*string*/
, ',' /*delimiter*/
, 1 /*start_position*/
)
)
FROM locations);
You can read more about the MySQL split_str function here: http://blog.fedecarg.com/2009/02/22/mysql-split-string-function/
Also, I have used the TO_NUMBER function of Oracle here. Please replace it with a proper MySQL function.
IN takes rows so taking comma seperated column for search will not do what you want but if you provide data like this ('1','2','3') this will work but you can not save data like this in your field whatever you insert in the column it will take the whole thing as a string.
You can create a prepared statement dynamically like this
set #sql = concat('select * from city where city_id in (',
(select cities from location where location_id = 3),
')');
prepare in_stmt from #sql;
execute in_stmt;
deallocate prepare in_stmt;
Ref: Use a comma-separated string in an IN () in MySQL
Recently I faced the same problem and this is how I resolved it.
It worked for me, hope this is what you were looking for.
select * from table_name t where (select (CONCAT(',',(Select city from locations l where l.e_Id=?),',')) as city_string) LIKE CONCAT('%,',t.e_ID,',%');
Example: It will look like this
select * from table_name t where ',6,7,8,16,21,2,' LIKE '%,2,%';