PHP dynamic JSON invalid - php

Question

I am trying to get a dataTable on a page called "locations.php" but i am still get a JSON invalid error.
I generate the JSON dynamically using this php code on "get_SR_Locations.php":
$myjson = array();
foreach ($locationList as $list) :
$json= array(
"id" => addslashes($list['id']),
"name" => addslashes($list['name']),
"address" => addslashes($list['address']),
"telephone" => addslashes($list['telephone']),
"emailaddress" => addslashes($list['email'])
);
array_push($myjson, $json);
endforeach;
$mj=array("data"=>$myjson);
echo json_encode($mj);
The generated JSON looks something like this:
{"data":[{"id":"108","name":"Sportpark","address":"Karspstreet 501","telephone":"0123456789","emailaddress":"sport#mail.com"},{"id":"2","name":"Blaashal","address":"Gustavstreet 2920","telephone":"","emailaddress":"sporting#mailing.com"}]}
So when I put this in a JSON validator it says: VALID JSON
But I still get an invalid JSON warning by ajax.
On locations.php I have this code:
HTML
<table id="displayTable" class="table table-striped table-bordered display compact" style="width:100%">
<thead>
<tr>
<th> </th>
<th>Name</th>
<th>Address</th>
<th>Telephone</th>
</tr>
</thead>
<tfoot>
<tr>
<th> </th>
<th>Name</th>
<th>Address</th>
<th>Telephone</th>
</tr>
</tfoot>
</table>
And this JQUERY
function format ( d ) {
// `d` is the original data object for the row
return 'So Far .... NOT so Good';
}
$('#SR_sendForm').click(function(){
$('#displayTable').DataTable(
{
"order": [[ 1, "asc" ]],
"scrollY": $(window).height()-($(window).height()/10),
"scrollX": true,
"ajax": 'pages/get_SR_Locations.php?fdr='+$('#FDR').val()+'&s_term='+$('#searchterm').val()+'&city='+$('#city').val()+'&searchgroup='+$('#searchgroup').val(),
"columns": [
{
"className": 'details-control',
"orderable": false,
"data": null,
"defaultContent": ''
},
{ "data": "name" },
{ "data": "address" },
{ "data": "telephone" }
]
}
);
$('#responseTable').show();
}
});
// Add event listener for opening and closing details
$('#responseTable tbody').on('click', 'td.details-control', function () {
var tr = $(this).closest('tr');
var row = table.row( tr );
if ( row.child.isShown() ) {
// This row is already open - close it
row.child.hide();
tr.removeClass('shown');
}
else {
// Open this row
row.child( format(row.data()) ).show();
tr.addClass('shown');
}
} );
And this is the error I get:
DataTables warning: table id=displayTable - Invalid JSON response. For more information about this error, please see http://datatables.net/tn/1
What is wrong?

Answer 1

Thank you Jeff.... I did what you said ... Add json to the data instead of going via ajax.
So the solution is:
I made an tempDIV to load the data from get_SR_Locations.php
<div class="row" id="tempDIV" style="display: none"></div>
then I load the data and I use the callback for errors etc.
$('#tempDIV').load('pages/get_SR_Locations.php?fdr='+$('#FDR').val()+'&s_term='+$('#searchterm').val()+'&city='+$('#city').val()+'&searchgroup='+$('#searchgroup').val(), function(responseTxt, statusTxt, xhr) {
if(statusTxt == "success"){
$('#displayTable').DataTable(
{
"order": [[ 1, "asc" ]],
"scrollY": $(window).height()-($(window).height()/10),
"scrollX": true,
"data": JSON.parse($.trim($('#tempDIV').text())),
"columns": [
{
"className": 'details-control',
"orderable": false,
"data": null,
"defaultContent": ''
},
{ "data": "name" },
{ "data": "address" },
{ "data": "telephone" }
]
}
);
$('#responseTable').show();
}
if(statusTxt == "error"){
$('#responseTable').html("<b>Oops</b><br>Houston we have a problem");
alert("Error: " + xhr.status + ": " + xhr.statusText);
$('#responseTable').show();
}
});
And a last modification in get_SR_Locations.php:
I removed this line:
$mj=array("data"=>$myjson);
$myjson = array();
foreach ($locationList as $list) :
$json= array(
"id" => addslashes($list['id']),
"name" => addslashes($list['name']),
"address" => addslashes($list['address']),
"telephone" => addslashes($list['telephone']),
"emailaddress" => addslashes($list['email'])
);
array_push($myjson, $json);
endforeach;
echo json_encode($myjson);