i have bellow string in php and i want remove directory listing and get only the xml name
/usr/local/EDI/GTNexus/BookingConfirmation/test/PROCESSED/ELITESGGTN_30120180814_1410366355.XML_20180817135443
i want to return the string as ELITESGGTN_30120180814_1410366355.XML.
i use below way but im not getting the expected result
to remove front i used this but not getting the expected outcome
$newfname = strstr($fname, '/');
You can explode on "/" and then find the last undescore from the last item and substring it.
$str = "/usr/local/EDI/GTNexus/BookingConfirmation/test/PROCESSED/ELITESGGTN_30120180814_1410366355.XML_20180817135443";
$arr = explode("/", $str);
$name = substr(end($arr), 0, strrpos(end($arr), "_"));
echo $name; //ELITESGGTN_30120180814_1410366355.XML
Related
I have below URL in my code and i want to split it and get the number from it
For example from the below URL need to fetch 123456
https://review-test.com/#/c/123456/
I have tried this and it is not working
$completeURL = https://review-test.com/#/c/123456/ ;
list($url, $number) = explode('#c', preg_replace('/^.*\/+/', '', $completeURL));
Use parse_url
It's specifically made for this sort of thing.
You can do this without using regex also -
$completeURL = 'https://review-test.com/#/c/123456/' ;
list($url, $number) = explode('#c', str_replace('/', '', $completeURL));
echo $number;
If you wan to get the /c/123456/ params you will need to execute the following:
$url = 'https://review-test.com/#/c/123456/';
$url_fragment = parse_url($url, PHP_URL_FRAGMENT);
$fragments = explode('/', $url_fragment);
$fragments = array_filter(array_map('trim', $fragments));
$fragments = array_values($fragments);
The PHP_URL_FRAGMENT will return a component of the url after #
After parse_url you will end up with a string like this: '/c/123456/'
The explode('/', $url_fragment); function will return an array with empty indexes where '/' was extracted
In order to remove empty indexes array_filter($fragments); the
array_map with trim option will remove excess spaces. It does not
apply in this case but in real case scenario you better trim.
Now if you var_dump the result you can see that the array needs to
be reindexed array_values($fragments)
You should try this: basename
basename — Returns trailing name component of path
<?php
echo basename("https://review-test.com/#/c/123456/");
?>
Demo : http://codepad.org/9Ah83qaP
Subsequently you can directly take from pure regex to fetch numbers from string,
preg_match('!\d+!', "https://review-test.com/#/c/123456/", $matches);
print_r($matches);
Working demo
Simply:
$tmp = explode( '/', $completeUrl).end();
It will explode the string by '/' and take the last element
If you have no other option than regex, for your example data you could use preg_match to split your url instead of preg_replace.
An approach could be to
Capture the first part as a group (.+\/)
Then capture your number as a group (\d+)
Followed by a forward slash at the end of the line \/$/
This will take the last number from the url followed by a forward slash.
Then you could use list and skip the first item of the $matches array because that will contain the text that matched the full pattern.
$completeURL = "https://review-test.com/#/c/123456/";
preg_match('/(.+\/)(\d+)\/$/', $completeURL, $matches);
list(, $url, $number) = $matches;
i have a path like this:
/dude/stuff/lol/bruh.jpg
i want to echo it like this:
/stuff/lol/bruh.jpg
how to do this? and if you could please explain it. i found one good answer
Removing part of path in php but i cannot work my way around with explode and implode.
please give me the link to the duplicate answer if my question is a duplicate
You could use strpos with substr:
$string = '/dude/stuff/lol/bruh.jpg';
$string = substr($string, strpos($string, '/', 1));
The strpos to look for the position of the / after the first one, then use substr to get the string starting from that position till the end.
$path = '/dude/stuff/lol/bruh.jpg';
$path = explode('/', $path);
unset($path[1]);
$path = implode('/', $path);
Will separate the string into an array, then unset the first item (technically the second in the array, since the first element will be empty due to the string starting with /). Finally the path is imploded, and you get:
/stuff/lol/bruh.jpg
Try this :
$string = "/dude/stuff/lol/bruh.jpg";
$firstslash = strpos($string,"/",1);
$secondstring = substr($string, $firstslash+1);
echo "String : " . $string;
echo " <br> Result : " . $secondstring;
You can use a regular expression to extract resource name you need.
preg_match('/(?P<name>[^\/]+)$/', $path, $match);
Then you have to use $match as array, and you can see the name inside of it.
$match['name];
How can I remove all the content in a string after the LAST occurance of a slash character / ?
For example, the string is:
http://localhost/new-123-rugby/competition.php?croncode=12345678
I want to remove all the content after the last / so that it just shows:
http://localhost/new-123-rugby/
But the content after the / could be of a variable length.
Please note, there could be any number of slashes in the URL. It needs to be able to remove content after the last slash. There could be more than shown in the example above.
you can try this
$url = "http://localhost/new-123-rugby/competition.php?croncode=12345678";
preg_match("/[^\/]+$/", $url, $matches);
$newUrl = str_replace($matches[0],'',$url);
echo $newUrl;
Solution #1, using substr() + strrpos():
$string = 'http://localhost/new-123-rugby/competition.php?croncode=12345678';
$pos = strrpos($string, '/');
if ($pos !== FALSE) {
echo(substr($string, 0, $pos + 1));
}
Function strrpos() finds the position of the last occurrence of / in the string, substr() extracts the required substring.
Drawback: if $string does not contain '/', strrpos() returns FALSE and substr() does not return what we want. Need to check the value returned by strrpos() first.
Solution #2, using explode() + implode():
$string = 'http://localhost/new-123-rugby/competition.php?croncode=12345678';
$array = explode('/', $string);
if (count($array) > 1) {
array_pop($array); // ignore the returned value, we don't need it
echo(implode('/', $array).'/'); // join the pieces back, add the last '/'
}
Alternatively, instead of array_pop($array) we can make the last component empty and there is no need to add an extra '/' at the end:
$string = 'http://localhost/new-123-rugby/competition.php?croncode=12345678';
$array = explode('/', $string);
if (count($array) > 1) {
$array[count($array) - 1] = ''; // empty the last component
echo(implode('/', $array)); // join the pieces back
}
Drawback (for both versions): if $string does not contain '/', explode() produces an array containing a single value and the rest of the code produces either '/' (the first piece of code) or an empty string (the second). Need to check the number of items in the array produced by explode().
Solution #3, using preg_replace():
$string = 'http://localhost/new-123-rugby/competition.php?croncode=12345678';
echo(preg_replace('#/[^/]*$#', '/', $string));
Drawbacks: none. It works well when both when $string contains '/' and it does not contain '/' (it does not modify $string in this case).
NOTA:
The question was edited so that the original answer (below the edit), doesn't match the requirements from OP. It wasn't marked as an edit from OP.
EDIT:
Updated my answer so it now matches the requirements of OP:
(Now it works with as many slashes as you want)
Will also work using
http://localhost/new-123-rugby////////competition.php?croncode=12345678
<?php
$url = "http://localhost/new-123-rugby/competition.php?croncode=12345678";
echo dirname($url) . "/";
?>
Output:
http://localhost/new-123-rugby/
Original answer:
This should work for you:
<?php
$string = "http://localhost/new-123-rugby/competition.php?croncode=12345678";
echo $string = substr($string, 0, strpos(strrev($string), "/")-2);
?>
Output:
http://localhost/new-123-rugby/
Demo: http://ideone.com/0R9QUG
To create an array from a string and get an element you need to do this:
$string = "1/2";
$array = explode("/", $string);
$elem = $array[0];
A little trick lets you use the strstr() and provides the same result as both lines above.
$elem = strstr($string, "/", true);
The issue is..
What if you want to return after the "/" instead of before it, but without the "/" prepended
If the "/" does not exist in the array, false is returned
strstr() is not the answer. Is there another method or syntax to get the string before the "/" in one line either by doing an array operation or some string operation?
You can do it like this in php 5.4 +
$string = "1/2";
$first = explode("/", $string)[0];
Eval.in example
You can use substr():
$after = substr($string, strpos($string, '/')+1);
the +1 makes it skip past the /.
Hi i want to know how can i get substring from string after last slash?
In short i want to get the file name from path.
for example i got string like this:
test-e2e4/test-e2e4/test-e2e4/6.png
and i want to get 6.png how can i do that ?
I got dir only and the file name can be all format, it can be also something else then file
Or test-e2e4/test-e2e4/test-e2e4/aaaaa and want to get aaaaa
Regex maybe? Or maybe you know some nice functions which will do it for me ?
In addition to other replies, there's actually a function in PHP to do this: basename. Example:
$string = 'test-e2e4/test-e2e4/test-e2e4/6.png';
$base = basename($string); // $base == '6.png';
$string = 'test-e2e4/test-e2e4/test-e2e4/aaaaa';
$base = basename($string); // $base == 'aaaaa'
$string = '6.png';
$base = basename($string); // $base == '6.png'
Full details here: http://php.net/basename
Do like this..
$yourstring = 'test-e2e4/test-e2e4/test-e2e4/6.png';
$val = array_pop(explode('/',$yourstring)); // 6.png
You can try explode and array_pop functions to work this out:
$str = 'test-e2e4/test-e2e4/test-e2e4/aaaaa.png';
$str = explode('/', $str);
$filename = array_pop($str);
echo $filename; //Output will be aaaaa.png
...Or you can use the following regex:
[^\/]*$
You don't need to use regex for this, you can use substr() to get a portion of the string, and strrpos() to specify which portion:
$full_path = "test-e2e4/test-e2e4/test-e2e4/6.png"
$file = substr( $full_path, strrpos( $full_path, "/" ) + 1 );
substr() returns a portion of the string, strrpos() tells it to start from the position of the last slash in the string, and the +1 excludes the slash from the return value.