I have a sms tracker database with a date column in the format 02/25/2018 04:12:52 pm. I want to count the no of sms sent each day to display it in bar chart.
I could only count sms sent by a user using this query "SELECT count(*) as user_count from table where username = 'CTC01'". How can i get an array of count for each day in a particular month
Since OP's date_column is VARCHAR type. We use STR_TO_DATE function:
SELECT DATE(STR_TO_DATE(date_column, "%m/%d/%Y %r")), COUNT(*)
FROM table
GROUP BY DATE(STR_TO_DATE(date_column, "%m/%d/%Y %r"));
Use DATE function, to convert a datetime expression to a date. Then use GROUP BY to get COUNT datewise.
In case, you want to get data for a specific user (eg: CTC01) and datewise. You can do the following:
SELECT DATE(STR_TO_DATE(date_column, "%m/%d/%Y %r")), COUNT(*)
FROM table
WHERE username = 'CTC01'
GROUP BY DATE(STR_TO_DATE(date_column, "%m/%d/%Y %r"));
I see your date format is 'm/d/Y H:i:s'. So, to get the total for each day in a month, you have to do a comparison against the least time in that month and the highest time in that month. So, the query for February 2018 would be:
SELECT DATE(date_column), COUNT(*)
FROM jobs
where created_on >= '02/01/2018 00:00:00' and created_on < '03/01/2018 00:00:00'
GROUP BY DATE(date_column);
To get for a particular user, simply append a where clause to the query above like so:
SELECT DATE(date_column), COUNT(*)
FROM jobs
where created_on >= '02/01/2018 00:00:00' and created_on < '03/01/2018 00:00:00' and username = 'CTC01'
GROUP BY DATE(date_column);
EDIT
Since your date column is varchar, you first have to convert it to datetime. So run this query instead:
SELECT DATE(DATE_FORMAT(STR_TO_DATE(date_column, '%c/%e/%Y %H:%i'), '%Y-%m-%d %H:%m:%s')) as Date, COUNT(*)
FROM jobs
where created_on >= '02/01/2018 00:00:00' and created_on < '03/01/2018 00:00:00'
GROUP BY DATE(DATE_FORMAT(STR_TO_DATE(date_column, '%c/%e/%Y %H:%i'), '%Y-%m-%d %H:%m:%s'));
Related
I have a table (Hire Rates) which contains multiple records. I'm trying to find records based on a date query but cannot get it to work correctly.
Essentially I am looking for records that contain a date between two dates. If my query date is "2021-08-15", it should return the third row (3000) as the query date falls between the two dates.
It is mostly working for me, except if the query date is equal to the start date or end date - in that case it doesn't return any result.
Table
startDate
endDate
hireRate
2021-01-01
2021-03-05
2350
2021-03-06
2021-04-08
2890
2021-04-09
2021-09-15
3000
Query
$sql = "SELECT rate, currencyID FROM hire_rates WHERE status = '1' AND NOT (startDate >= '$queryDate' OR endDate <= '$queryDate')
Try adding 'between' condition.
Like
select rate, currencyId from hire_rates where states =1 and not (cast($queryDate as DATE) between cast(startDate As DATE) and cast(endDate AS DATE) )
You would pass in the date you care about as a parameter. Then you can use between (based on your description of the logic):
SELECT rate, currencyID
FROM hire_rates
WHERE status = 1 AND
? BETWEEN startDate AND endDate;
Where ? is a parameter for the date you are passing in.
For 2021-08-15, you can write:
WHERE status = 1 AND
'2021-08-15' BETWEEN startDate AND endDate;
If you want the current date, you can actually get that from the database:
SELECT rate, currencyID
FROM hire_rates
WHERE status = 1 AND
curdate() BETWEEN startDate AND endDate;
Just try this then, `$sql = SELECT hireRate FROM hire_rate WHERE startDate<= '$queryDate' and endDate >= '$queryDate'
I have saved the dates of a user's registration as a datetime, so that's for instance 2011-12-06 10:45:36. I have run this query and I expected this item - 2011-12-06 10:45:36 - will be selected:
SELECT `users`.* FROM `users` WHERE created_at >= '2011-12-01' AND
created_at <= '2011-12-06'
But is not. Exist any elegant way, how to select this item? As a first idea that I got was like 2011-12-06 + 1, but this doesn't looks very nice.
Your problem is that the short version of dates uses midnight as the default. So your query is actually:
SELECT users.* FROM users
WHERE created_at >= '2011-12-01 00:00:00'
AND created_at <= '2011-12-06 00:00:00'
This is why you aren't seeing the record for 10:45.
Change it to:
SELECT users.* FROM users
WHERE created_at >= '2011-12-01'
AND created_at <= '2011-12-07'
You can also use:
SELECT users.* from users
WHERE created_at >= '2011-12-01'
AND created_at <= date_add('2011-12-01', INTERVAL 7 DAY)
Which will select all users in the same interval you are looking for.
You might also find the BETWEEN operator more readable:
SELECT users.* from users
WHERE created_at BETWEEN('2011-12-01', date_add('2011-12-01', INTERVAL 7 DAY));
SELECT users.* FROM users WHERE created_at BETWEEN '2011-12-01' AND '2011-12-07';
You need to use '2011-12-07' as the end point as a date without a time default to time 00:00:00.
So what you have actually written is interpreted as:
SELECT users.*
FROM users
WHERE created_at >= '2011-12-01 00:00:00'
AND created_at <= '2011-12-06 00:00:00'
And your time stamp is: 2011-12-06 10:45:36 which is not between those points.
Change this too:
SELECT users.*
FROM users
WHERE created_at >= '2011-12-01' -- Implied 00:00:00
AND created_at < '2011-12-07' -- Implied 00:00:00 and smaller than
-- thus any time on 06
Another alternative is to use DATE() function on the left hand operand as shown below
SELECT users.* FROM users WHERE DATE(created_at) BETWEEN '2011-12-01' AND '2011-12-06'
Have you tried before and after rather than >= and <=? Also, is this a date or a timestamp?
Searching for created_at <= '2011-12-06' will search for any records that where created at or before midnight on 2011-12-06
. You want to search for created_at < '2011-12-07'.
Maybe use in between better. It worked for me to get range then filter it
You can use MySQL DATE function like below
For instance, if you want results between 2017-09-05 till 2017-09-09
SELECT DATE(timestamp_field) as date FROM stocks_annc WHERE DATE(timestamp_field) >= '2017-09-05' AND DATE(timestamp_field) <= '2017-09-09'
Make sure to wrap the dates within single quotation ''
Edit:
A better solution would be this. It would make sure that it uses the index if any exists.
select date(timestamp_field) as date from stocks_annc where time_stamp_field >= '2022-01-01 00:00:00' and time_stamp_field <= '2022-01-10 00:00:00'
Hope this helps.
i got a table that stores start_date and end_date with the field type DATE
I want to retrieve all records between the start_date and end_date but my below SQL statement do not give any results.
$sql = "SELECT * FROM expo Where date >= DATE(NOW()) AND end_date <= DATE(NOW())";
You can use the between function to perform this action.
SELECT *
FROM expo
WHERE NOW() BETWEEN date AND end_date
Oh, since your column is date, not datetime use date(now()). That will select records that start and end on the current date as well.
Demo: http://sqlfiddle.com/#!9/0aaad/6
SELECT *
FROM expo
WHERE date(NOW()) BETWEEN date AND end_date
Use curdate
SELECT *
FROM expo
WHERE date >= curdate() AND end_date <= curdate()
I have a scenario where I need to pull up delivery dates based on a table below (Example)
job_id | delivery_date
1 | 2013-01-12
2 | 2013-01-25
3 | 2013-02-15
What I'm trying to do is show the user all the delivery dates that start with the earliest (in this case it would be 2013-01-12) and add an another 21 days to that. Basically, the output I would expect it to show of course, the earliest date being the starting date 2013-01-12 and 2013-01-25. The dates past the February date are of no importance since they're not in my 21 date range. If it were a 5 day range, for example, then of course 2013-01-25 would not be included and only the earliest date would appear.
Here is main SQL clause I have which only shows jobs starting this year forward:
SELECT date, delivery_date
FROM `job_sheet`
WHERE print_status IS NULL
AND job_sheet.date>'2013-01-01'
Is it possible to accomplish this with 1 SQL query, or must I go with a mix of PHP as well?
You can use the following:
select *
from job_sheet
where print_status IS NULL
and delivery_date >= (select min(delivery_date)
from job_sheet)
and delivery_date <= (select date_add(min(delivery_date), interval 21 day)
from job_sheet)
See SQL Fiddle with Demo
If you are worried about the dates not being correct, if you use a query then it might be best to pass in the start date to your query, then add 21 days to get the end date. Similar to this:
set #a='2013-01-01';
select *
from job_sheet
where delivery_date >= #a
and delivery_date <= date_add(#a, interval 21 day)
See SQL Fiddle with Demo
SELECT date,
delivery_date
FROM job_sheet
WHERE print_status IS NULL
AND job_sheet.date BETWEEN (SELECT MIN(date) FROM job_sheet) AND
(SELECT MIN(date) FROM job_sheet) + INTERVAL 21 DAY
SELECT j.job_id
, j.delivery_date
FROM `job_sheet` j
JOIN ( SELECT MIN(d.delivery_date) AS earliest_date
FROM `job_sheet` d
WHERE d.delivery_date >= '2013-01-01'
) e
ON j.delivery_date >= e.earliest_date
AND j.delivery_date < DATE_ADD(e.earliest_date, INTERVAL 22 DAY)
AND j.print_status IS NULL
ORDER BY j.delivery_date
(The original query has a predicate on job_sheet.date; the query above references the d.delivery_date... change that if it is supposed to be referencing the date column instaed.)
If the intent is to only show delivery_date values from today forward, then change the literal '2013-01-01' to an expression that returns the current date, e.g. DATE(NOW())
Using PHP/MySQL
I'm trying to create a select statement that gets the data from the least day of the current week (I'm using it to show data on a certain player 'this week'). The week starts on Sunday. Sundays's data may not always exist therefore if the Sunday data isn't found then it would use the next earliest day found, Monday, Tuesday, etc.
My date column is named 'theDate' and the datatype is 'DATE'
The query would need to be something like:
SELECT *
FROM table_name
WHERE name = '$username'
AND [...theDate = earliest day of data found for the current week week]
LIMIT 1
It would return a single row of data.
This is a query I tried for getting the 'this week' data, It doesn't seem to work correctly on Sunday's it shows nothing:
SELECT *
FROM table_name
WHERE playerName = '$username'
AND YEARWEEK(theDate) = YEARWEEK(CURRENT_DATE)
ORDER BY theDate;
This is the query that I'm using to get 'this months' data and it works even if the first day of the months data is not found, it will use the earliest date of data found in the current month/year (this query works perfect for me):
SELECT *
FROM table_name
WHERE playerName = '$username'
AND theDate >= CAST( DATE_FORMAT( NOW(),'%Y-%m-01') AS DATE)
ORDER BY theDate
LIMIT 1
Without trying this, you probably need an inner query:
select *
from table_name tn
where tn.the_date =
(select min(the_date)
from table_name
where WEEKOFYEAR(the_date) = WEEKOFYEAR(CURDATE())
and YEAR(the_date) = YEAR(CURDATE()))
viz, give me the row(s) in the table with a date equal to the earliest date in the table in the current week and year.
Try this
SELECT * FROM table_name WHERE name = '$username'
AND your_data IS NOT NULL
AND WEEK(the_date,0 = WEEK(NOW(),0))
ORDER BY DATE_FORMAT(the_date,'%w') ASC
Try the following, replace YOUR_DATE with the date from the column you want (theDate):
SELECT ADDDATE(YOUR_DATE, INTERVAL 1-DAYOFWEEK(YOUR_DATE) DAY)
FirstDay from dual
Did you try:
SELECT ADDDATE(theDate , INTERVAL 1-DAYOFWEEK(theDate ) DAY) FirstDay
FROM table_name
WHERE playerName = '$username'
ORDER BY theDate DESC
LIMIT 1