How to assign variables taken from url to table (HTML, PHP) - php

Trying to assign variables set by user in URL to a table in HTML using php but it doesn't seem to work.
At start of body:
<?php
$border = $_GET['border'];
$cellpadding = $_GET['cellpadding'];
$bgcolor = $_GET['bgcolor'];
?>
Below, in table:
<table <?php echo" style='border: $border; padding: $cellpadding; background-color: $bgcolor;' "; ?> >
Thank You.

This code is the same and I don't think that there's a problem with your code
But I prefer displaying PHP in HTML like that. If it does not work open inspect element and check the HTML code there and post it here
<table style="border:<?=$border?>; padding:<?=$cellpadding?>; background-color:<?=$bgcolor?>;">

Related

Div stuck in Div when inserted using appendChild PHP

I'm trying to insert a div into a HTML page using a for loop and the appendChild method in PHP. The issue I'm running into is that the first div always ends up stuck inside the second div, which always ends up stuck in the third div and so on and so forth. So how do I end the div at the end of the for loop?
///The PHP Side
// Create an insertion point for the Projects element
$projectInsert = $doc->getElementById("projects");
// Create a project Box
for ($x = $row_cnt; $x > 0; $x--) {
$sql2 = "SELECT * FROM `$prjct` WHERE id=$x";
$result2 = mysqli_query($db,$sql2);
$row2 = mysqli_fetch_array($result2,MYSQLI_ASSOC);
//Insert a project Box
$projectBox = $doc->createElement('div');
$projectBox->setAttribute("class","projectBox");
$project_element_title = $doc->createElement('p', $row2["title"]);
$project_element_description = $doc->createElement('p', $row2["description"]);
$projectInsert->appendChild($projectBox);
$projectInsert->appendChild($project_element_title);
$projectInsert->appendChild($project_element_description);
}
//Here's where it's inserting in the HTML
<div class="projectBar" id="projectsBar">
<h4 style="height: 30%; width: 100%; margin: auto;">Projects</h4>
<p id="projects"></p>
</div>
Here's photos of what's happening vs what I want to happen
https://docs.google.com/presentation/d/1OgthPueXHzGXyUi6L3DmgWTtOr6gHpfj8LgGh5OG85Y/edit?usp=sharing
Since I'm new I can't embed images.
Thanks for any and all help!
Instead of appending childs($project_element_title and $project_element_description) to parent($projectBox) you are appending it to super-parent($projectInsert), that's the problem.
So change:
$projectInsert->appendChild($project_element_title);
$projectInsert->appendChild($project_element_description);
To
$projectBox->appendChild($project_element_title);
$projectBox->appendChild($project_element_description);

How to get a PHP loop to run via a variable?

(This has now been resolved - thanks #ChelseaStats)
I have built a web page in PHP. users log in and upload photos and stories, and the page displays the stories and photos immediately.
The problem is that the photos that the MySQL query and PHP return from the database are being displayed all over the place. I have printed them out in an id’d div but the CSS is having no control over their positioning.
Currently the query is like this:
$q1 = "SELECT * from images ORDER BY date ASC";
and they are displayed like this...
row1 = #mysqli_query($dbc, $q1);
echo '<div id = "pictures">';
while ( $fix1 = mysqli_fetch_array($row1) ) {
echo '
<img style = "border: 1px solid black; padding: 10px;" height = "80" width = "80" src = "data:image;base64,'.$fix1['image'].'"><br>'.$fix1['image_id'].'
';}
echo '</div id = "pictures">';
What I would like to do is store all the 'while loop' programming in a variable, then print that variable out elsewhere on the HTML page away from php script so that when the database query is run, I can use the results to fill/initialize the variable (e.g. $displayPics) which will then be printed out on the html page where I want it to appear.
I realise this may be impossible and I am open to suggestions...
...or I might be willing to run a query with a limit of 20 giving results in descending date order and then assigning ‘loop-free’ PHP code to a variable which I can then print out on the page elsewhere.
Code could look something like this:
row1 = #mysqli_query($dbc, $q1);
$fix1 = mysqli_fetch_array($row1);
$displayPics = '
<img style = "border: 1px solid black; padding: 10px;" height = "40" width = "40" src = "data:image;base64,\'.$row1[$fix1[\'image\']].\'"><br>\'.$row1[$fix1[\'image\']].\'
';
(Above code is a shot at how I imagine it will look). (I think the img src code and html has been filtered out by the forum possibly).
But maybe this code will be repeated 20x in the variable with row number changing for each subsequent repetition perhaps?
(I basically want better control over the positioning of the pics coming back from the database).
in a foreach you can assign to a variable like this
$bob = ''; // set it
foreach($row as $image) {
// append to it
$bob .= '<div id=""><img src="" /></div>'.PHP_EOL;
}
print $bob;
similar would work for you.
if you use Bootstrap- you can assign a display class as it is rendered. The following will display each image as follows (4 across on a medium to large viewport, 3 across on a small viewport, and two across on a mobile sized viewport). Also note the use of figcaption to provide the caption on each image.
row1 = #mysqli_query($dbc, $q1);
while ( $fix1 = mysqli_fetch_array($row1) ) {
echo "<div class='col-md-3 col-sm-4 col-xs-6'>
<figure>
<img style = 'border: 1px solid black; padding: 10px;' height = '80' width = '80' src = 'data:image;base64,".$fix1['image']."'/>
<figcaption>".$fix1['image_id']."</figcaption>
</figure>
</div>
";}
Simply write a function that returns all of the rows into an array of assoc arrays and loop through them when you need them elsewhere in the code and use conditional tests on the rows to have better control over where they go!
function getImages(){
$imgs = array();
while(($next = mysqli_fetch_assoc(...)){
array_push($imgs, $next);
}
return $imgs; //array of assoc arrays
}

i want to retrieve data from MySQL db by displaying it using table, arrange it the same way it appear in the image

<?php
$con = mysqli_connect("localhost","root","","shady");
$query = "SELECT * fROM hall1 ";
$result = mysqli_query($con,$query) or die(mysqli_error());
echo "<form action='food.php' method='post'>";
echo "<table >";
$size = 0;
while($row = mysqli_fetch_array($result))
{
$imagewidth=200;
if($size > 900)
{
echo"<tr>";
}
echo'<td width='.$td3=100 .'px > </td>' ;
echo'<td width='.$td1=200 .'px> <label><input type="radio" name="radii" value='.$row[1].' checked> <img src="'.$row['image'].'" width="200" height="200" style="margin-top:10px;"> </label></td>' ;
echo"<td width=".$td2=200 ."px> Name &nbsp: " .$row[1] ."<br> Size &nbsp &nbsp : ".$row[2] ."Person <br> Price &nbsp &nbsp: ".$row[3] ." SDG <br> See More </td>";
$size+= $imagewidth+$td1+$td2+$td3;
if($size > 900)
{
echo"<tr>";
}
}
echo"</table>";
echo "<BR><BR><BR><CENTER><input type='submit' name='radiii' value='next' width='200PX' height='200PX' ></a> </CENTER></b>";
echo "</form>";
}
?>
There are many problems with your code:
It's unclear what the variable size does. I'm willing to bet it's unnecessary
You are using deprecated code. The width attribute on HTML elements is no longer supported, and if you insist on using it, you should only enter the width in pixels without the px like so: <td width="200">. The <center> tag is also deprecated.
Your <label> tag is pretty much useless. What are you trying to achieve with it?
It's a bad practice to set the widths on all rows, just set the widths on the first row's cells. Even better, do not use any style directly on the HTML tags and using CSS rules instead.
Lastly, i believe it would be much more readable code to NOT echo HTML and instead use the following approach to "plug in" your variables from PHP into HTML code :
<? $a = "Some variable"; $b = 123; $c = "http://example.com/img/1.png"; ?>
<p><strong>My variable a: <?=$a?></p>
<p><strong>My variable b: <?=$b?></p>
<p><strong>My img: <img src="<?=$c?>"></p>
In short, wrap your PHP logic in <? and ?> (be sure to have short_open_tag = On in your PHP settings or you'll need to use the alternative opening tag <?php like you did.
The write plain old HTML without all the echo. Whenever you want to echo something you simply write a new PHP opening tag like so :
<? echo $a ?>
OR, the shorthand version
<?=$a?>
Now your real problem is about designing the page. And i think you are starting in the wrong order. I would suggest you
1- Build a design that works using some IDE like Adobe Dreamweaver or a freeware alternative. With that tool, make the design for 1 item (1 iteration of your while loop).
The next step is to see how you're gonna repeat it. You seem to want a Horizontal list that wraps around lines at a certain width. One way you would do that is that you would wrap all the list items with a div element for which you will set a fixed width. And inside you will have the code you have for each item repeated for all items. If your outer div has a width of 900px and each element consumes 300px in width and you have 9 items, you would have a 3x3 grid.
Here is a summary code of what i explained. In your PHP file you would have:
<div class="grid">
<? while($row = .... ){ ?>
<div class="item">
<!-- The code for the image, label and whatever information you want to have for each item -->
</div>
<? } ?>
</div>
And a CSS file which you would link in your PHP file, containing:
.grid {
width: 900px;
}
.item {
width: 300px;
}
If the information your are displaying come from user input you should sanitize it and have some sort of logic that breaks long text, either with CSS or PHP.
In short, you seem to be doing all the math in PHP so that you jump into a new line once the total width exceeds your desired grid width. This is a design issue and not a logic / programming issue. Therefore you should tackle this with CSS and not PHP.
I strongly suggest you either follow a video tutorial (there are plenty online) or read some documentations on HTML, CSS, JavaScript, PHP and MySQL in that order.
Here is a link to get you started: Mozilla Developer Network

Generate an HTML table with dynamic row Height

I need to print an html table with row heights sets dynamically based on some values from the database using PHP. seems that html 5 doesn't support inline height and with tags and using css instead.
My requirement is to generate an html file and then convert it into pdf using DOM pdf.
Please guide me how to set these parameters dynamically inline or using css or whether a library already available for the same purpose.
I Googled a lot, but unable find any results matching my requirement.
Also am attaching final output format
(In answer column i printed some values which is the height required for each row)
Thanks in advance
You can use inline styles:
<tr style="height: 300px;"></tr>
I am not sure if you can effectively set the height of a <tr> tag, so you might have to set the height of each <td> in the row individually. Give it a try.
Furthermore, I am not sure how you have your array of rows and columns structured, but this might shed some light on how to do it.
<?php
$array=array(array(50,'r1c1','r1c2'),array(50,'r2c1','r2c2'));
echo '<table>';
foreach($array as $row)
{
echo '<tr style="height: '.$row[0].'px;">';
echo '</tr>';
for($i=1;$i<count($row);++$1)
{
echo '<td>'.$row[$i].'</td>';
}
}
echo '</table>';
?>
If you still need help, post the exact array you wish to turn into a <table> and I will do my best to assist.
If I understand this right, your table rows can be different sizes from each other, but for each row there is a rule in database, that sets row's height, no matter what height the content of the row, right? Then you can use something like this:
<html>
<head>
<style>
<?php foreach($yourRows as $key => $row) { ?>
#row<?=$key;?>{
height: <?=$row['height']; ?>px;
}
<?php } ?>
</style>
</head>
<body>
<table>
<?php foreach($yourRows as $key => $row) { ?>
<tr id="row<?=$key; ?>">
...
</tr>
<?php } ?>
</table>
</body>
In the style tag you can replace "#row<?=$key;?>" with "#row<?=$key;?> td"
Updated
Anyway, if you want to use the inline styling, you can make it happen like that:
<html>
<body>
<table>
<?php foreach($yourRows as $row) { ?>
<tr style="height:<?=$row['height']; ?>px">
Or you can apply height to td instead of the tr...
</tr>
<?php } ?>
</table>
</body>
If you think that jQuery might work here is a suggestion. I'm not sure it works with DOMPDF but as we're dynamically creating CSS it should be fine once the DOM has loaded.
If you know exactly the heights of each row - then select them using jQuery using eq.
$(document).ready(function() {
$('table tr').eq(1).css({'height':'250'});
$('table tr').eq(3).css({'height':'450'});
});
Here is the fiddle.
That way you don't have to modify the output but you have to make the assumption the content isn't going to be higher than your fixed height.
If you need this to be more dynamic then you'll need to either associate identifiers to your rows, like a class or something like that. Or alternatively, if you have a pattern in your content is to create a regular expression that scans your content and identifies it that way - then you can apply CSS rules to these rows once matched using jQuery.
EDIT
OK so I may have slightly misunderstood if you have the height value stored in the database. It also looks as though you've determined already that you're unable to use inline styles.
Here is my next suggestion.
You're building the table from a loop so it probably looks something like this.
foreach($rows as $row) {
echo '<tr data-height="'.$row['height'].'"><td>...</td></tr>;
}
if you add data-height="'.$row['height'].'" then you have a value that we can get using jQuery's data like so.
$(document).ready(function() {
$('table tr').each(function() {
var height = $(this).data('height');
$(this).css({ 'height': height });
});
});
Here is an example fiddle with static data-height values. Let me know how you get on.

Div not auto expanding due to dynamically loaded content

I have a bit of an issue...
Ive made a div, and normally, it expands to suit the height of its contents fine, however... Now i have a problem.
My content is being returned from a Sql statment, and its not expanding to suit its height, a working non dynamic version is
#commentblock {
min-height:50px;
width:90%;
margin:20px auto;
padding:10px;
border:1px solid #999;
}
My code is as follows (its in a for loop making a new div for each instance)
// Now lets query to grab the responses to this fault
$querytwo = "SELECT * FROM comments WHERE faultid=".$fid;
// execute query
$resulttwo = mysql_query($querytwo) or die ("Error in query: $querytwo. ".mysql_error());
// see if any rows were returned
if (mysql_num_rows($resulttwo) > 0) {
// print them one after another
while($row = mysql_fetch_row($resulttwo)) {
// lets make this render then
echo "<div id='commentblock'>";
echo "<div class='loggedby'>Logged By : <span>".$row[4]."</span><p class='contactno'>Entered : <span>".$row[3]."</span></p></div>";
echo "<div class='info'><span>".$row[2]."</span></div>";
echo "</div>";
}
}
// free result set memory
mysql_free_result($resulttwo);
// close connection
mysql_close($connection);
Thanks in advance :)
Got it, the content was in a span which was inheriting a floating attribute. Removed the float - now its all fine :)
It might not be to do with dynamic code, but invalid HTML.
You are using:
id='commentblock'
... in a loop, which create multiple, identical IDs on the same page, which is not valid.
You should change to:
class='commentblock'
and reference you CSS as:
.commentblock
... instead of:
#commentblock

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