I'm working on a simple quiz. One question is displayed at a time with 3 possible answers on radio buttons. The answer for each question is stored in a table from a database called
SOLUTION:
What I’m trying to do in the program is to show a message of 'Try again!' every time the user answers the question badly after clicking on SUBMIT. I have implemented it in the following code but I do not know why I always get the message of 'Try again!' when I click submit. Maybe it is because I put an 'else' after an 'empty'? Or because I'm not comparing it well with the correct variable? Can you help me find out the mistake?
This is my code:
<?php
$Err = "";
$Try = "";
if ($_SERVER["REQUEST_METHOD"] == "POST") {
if (empty($_POST["choice"])) {
$Err = "Please select option";
}
else{
if($_POST["choice"] != "solution_number FROM solution WHERE exercise_id_fk=$id"){
$Try = "Try again!";
}
}
}
?>
<form action='' method='post'>
<input type="radio" name="choice" value= "1" /><img src="<?php echo $row["image_path_A"] ?>"/><br>
<input type="radio" name="choice" value= "2" /><img src="<?php echo $row["image_path_B"] ?>"><br>
<input type="radio" name="choice" value= "3" /><img src="<?php echo $row["image_path_C"] ?>"><br>
<br><br>
<span class="error"><?php echo $Err;?></span>
<span class="try"><?php echo $Try;?></span>
<br><br><br><!--- Select difficulty --->
<p2>Select difficulty level:</p2>
<form action='' method='post'>
<select name="choose" id="choose">>
<option value="1" <?php if($row["difficulty"]=="1") { echo "selected"; } ?> >1</option>
<option value="2" <?php if($row["difficulty"]=="2") { echo "selected"; } ?> >2</option>
<option value="3" <?php if($row["difficulty"]=="3") { echo "selected"; } ?> >3</option>
<option value="4" <?php if($row["difficulty"]=="4") { echo "selected"; } ?> >4</option>
<option value="5" <?php if($row["difficulty"]=="5") { echo "selected"; } ?> >5</option>
</select>
<input class="buttonSubmit" type="submit" name="submit" value="Submit">
<?php
if ($next_question_id >= 0) {
?>
<a href="?id=<?php echo $next_question_id; ?>&order=<?php echo $next_question_order; ?>" class="buttonNext" >Next Question</a>
<?php
}
?>
</form>
And my PHP:
<?php
if (isset($_POST['submit'])) {
$user_id = $_SESSION['user_id'];
$user_check_query = "SELECT * FROM users WHERE id='$user_id'";
if(isset($_POST['choice'], $_POST['choose'])){
$choice_answer=$_POST['choice'];
$difficulty=$_POST['choose'];
$query = "INSERT INTO answers (exercise_id_fk, student_id, difficulty_change, difficulty_student, choice_answer, correct_answer) VALUES ('$id','$user_id', (SELECT IF(difficulty='$difficulty','NO','YES') FROM exercises WHERE exercise_id=$id), '$difficulty', '$choice_answer', (SELECT IF(solution_number='$choice_answer','1','0') FROM solution WHERE exercise_id_fk=$id))";
$sql=mysqli_query($conn,$query);
}
}
?>
Related
I'm doing a program where I try to save data every time the user press 'submit'. I have managed to save in my table 'answers' the data of the columns: exercise_id_fk, student_id and difficulty_student, but I can not save the data from the column: choice_answer. Every time I try to save it, it stops me from saving the other columns. I'm trying to store in the database multiple choice answers. Can you help me see what is wrong?
This is my program where im trying to store in the column 'choice_anser' from the multiple choice answers:
<?php
// Start the session
session_start();
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "project";
$conn = new mysqli($servername, $username, $password, $dbname);
/*echo*/ $id=$_GET['id'];
$sql = "SELECT * FROM exercises where exercise_id='$id'";
$result = $conn->query($sql); /*Check connection*/
?>
<div id="centered_B" class="header">
<?php
$row = $result->fetch_assoc();
echo '<h1>' . $row["exercise_id"]. ". " . $row["title"] . '</h1>' . "<br>" . '<p>' . $row["text"] . '</p> <img width="603" height="auto" src="' . $row["image_path"] . '"><br><br>
<form method="post" >
<input type="radio" name="choice" value= "1" /><img src="' . $row["image_path_A"] . '"/><br>
<input type="radio" name="choice" value= "2" /><img src="' . $row["image_path_B"] . '"><br>
<input type="radio" name="choice" value= "3" /><img src="' . $row["image_path_C"] . '"><br>';
echo '</form>';
/*var_dump($id)*/
?>
<br><br><br><!--- Select difficulty --->
<p2>Select difficulty level:</p2>
<form action='' method='post'>
<select name="choose" id="choose">>
<option value="1" <?php if($row["difficulty"]=="1") { echo "selected"; } ?> >1</option>
<option value="2" <?php if($row["difficulty"]=="2") { echo "selected"; } ?> >2</option>
<option value="3" <?php if($row["difficulty"]=="3") { echo "selected"; } ?> >3</option>
<option value="4" <?php if($row["difficulty"]=="4") { echo "selected"; } ?> >4</option>
<option value="5" <?php if($row["difficulty"]=="5") { echo "selected"; } ?> >5</option>
</select>
<br><br><br><!--- Button --->
<!-- <button class="buttonSubmit" >Submit</button>-->
<input type="submit" name="submit" value="Submit">
<button class="buttonNext" >Next Question</button>
</form>
</div><!--- end of centered_B div --->
<?php
if (isset($_POST['submit'])) {
$user_id = $_SESSION['user_id'];
$user_check_query = "SELECT * FROM users WHERE id='$user_id'";
if(isset($_POST['choice'])){
if(isset($_POST['choose'])){
$choice_answer=$_POST['choice'];
$difficulty=$_POST['choose'];
// */$user_id = $_SESSION['user_id'];*/
$query = "INSERT INTO answers (exercise_id_fk, student_id, difficulty_student, choice_answer) VALUES ('$id','$user_id', '$difficulty', '$choice_answer')";
$sql=mysqli_query($conn,$query);
}
}
}
?>
<?php
// Start the session
session_start();
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "project";
$conn = new mysqli($servername, $username, $password, $dbname);
/*echo*/ $id=$_GET['id'];
$sql = "SELECT * FROM exercises where exercise_id='$id'";
$result = $conn->query($sql); /*Check connection*/
?>
<div id="centered_B" class="header">
<?php
$row = $result->fetch_assoc();
?>
<h1><?php echo $row["exercise_id"] ?></h1><br/>
<p><?php echo $row["text"] ?></p>
<img width="603" height="auto" src="<?php $row["image_path"]?>"><br/><br/>
<form action='' method='post'>
<input type="radio" name="choice" value= "1" /><img src="<?php echo $row["image_path_A"]; ?>"/><br>
<input type="radio" name="choice" value= "2" /><img src="<?php echo $row["image_path_B"] ; ?>"><br>
<input type="radio" name="choice" value= "3" /><img src="<?php echo $row["image_path_C"]; ?>"><br>
<!-- var_dump($id) -->
<br><br><br>
<p2>Select difficulty level:</p2>
<form action='' method='post'>
<select name="choose" id="choose">>
<option value="1" <?php if($row["difficulty"]=="1") { echo "selected"; } ?> >1</option>
<option value="2" <?php if($row["difficulty"]=="2") { echo "selected"; } ?> >2</option>
<option value="3" <?php if($row["difficulty"]=="3") { echo "selected"; } ?> >3</option>
<option value="4" <?php if($row["difficulty"]=="4") { echo "selected"; } ?> >4</option>
<option value="5" <?php if($row["difficulty"]=="5") { echo "selected"; } ?> >5</option>
</select>
<br><br><br><!--- Button --->
<button class="buttonSubmit" >Submit</button>
<input type="submit" name="submit" value="Submit">
<button class="buttonNext" >Next Question</button>
</form>
</div><!--- end of centered_B div --->
<?php
if (isset($_POST['submit'])) {
$user_id = $_SESSION['user_id'];
$user_check_query = "SELECT * FROM users WHERE id='$user_id'";
if(isset($_POST['choice'])){
if(isset($_POST['choose'])){
$choice_answer=$_POST['choice'];
$difficulty=$_POST['choose'];
// */$user_id = $_SESSION['user_id'];*/
$query = "INSERT INTO answers (exercise_id_fk, student_id, difficulty_student, choice_answer) VALUES ('$id','$user_id', '$difficulty', '$choice_answer')";
$sql=mysqli_query($conn,$query);
}
}
}
?>
You have to use the single form if you want to save everything when you click on submit.
<?php
// Start the session
session_start();
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "project";
$conn = new mysqli($servername, $username, $password, $dbname);
/*echo*/ $id=$_GET['id'];
$sql = "SELECT * FROM exercises where exercise_id='$id'";
$result = $conn->query($sql); /*Check connection*/
?>
<div id="centered_B" class="header">
<?php
$row = $result->fetch_assoc();
echo '<h1>' . $row["exercise_id"]. ". " . $row["title"] . '</h1>' . "<br>" . '<p>' . $row["text"] . '</p> <img width="603" height="auto" src="' . $row["image_path"] . '"><br><br>
/*var_dump($id)*/
?>
<br><br><br><!--- Select difficulty --->
<p2>Select difficulty level:</p2>
<form action='' method='post'>
<input type="radio" name="choice" value= "1" /><img src="<?php $row["image_path_A"];?>"/><br>
<input type="radio" name="choice" value= "2" /><img src="<?php $row["image_path_B"];?>"><br>
<input type="radio" name="choice" value= "3" /><img src="<?php $row["image_path_C"];?>"><br>
<select name="choose" id="choose">
<option value="1" <?php if($row["difficulty"]=="1") { echo "selected"; } ?> >1</option>
<option value="2" <?php if($row["difficulty"]=="2") { echo "selected"; } ?> >2</option>
<option value="3" <?php if($row["difficulty"]=="3") { echo "selected"; } ?> >3</option>
<option value="4" <?php if($row["difficulty"]=="4") { echo "selected"; } ?> >4</option>
<option value="5" <?php if($row["difficulty"]=="5") { echo "selected"; } ?> >5</option>
</select>
<br><br><br><!--- Button --->
<!-- <button class="buttonSubmit" >Submit</button>-->
<input type="submit" name="submit" value="Submit">
<button class="buttonNext" >Next Question</button>
</form>
</div><!--- end of centered_B div --->
<?php
if (isset($_POST['submit'])) {
$user_id = $_SESSION['user_id'];
$user_check_query = "SELECT * FROM users WHERE id='$user_id'";
if(isset($_POST['choice'])){
if(isset($_POST['choose'])){
$choice_answer=$_POST['choice'];
$difficulty=$_POST['choose'];
// */$user_id = $_SESSION['user_id'];*/
$query = "INSERT INTO answers (exercise_id_fk, student_id, difficulty_student, choice_answer) VALUES ('$id','$user_id', '$difficulty', '$choice_answer')";
$sql=mysqli_query($conn,$query);
}
}
}
?>
I want a first radio button to be checked by default. When I click get schedule I want to fetch the schedule of that radio selected train number using a WHERE clause.
<?php
while ($res = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td><input type = radio />" . $res['Train_no'] . "</td>";
?>
<form action="schedule.php" method="POST" class="form-inline">
<input type="submit" value="Get Schedule"/>
</form>
<?php
}
<?php
$con = mysql_connect("localhost", "root", "");
if ($con) {
$db = mysql_select_db('traindb', $con);
} else {
die('Could not connect: ' . mysql_error());
}
$selected_val = $_POST['Train_no']; // Storing Selected Value In Variable
echo "You have selected :" . $selected_val; // Displaying Selected Value
$result = mysql_query("SELECT * FROM train_detail WHERE Train_No='$selected_val'");
mysql_close($con);
?>
You can try this:
if(isset($_POST['Submit'])){
$selected_val = $_POST['Train_no']; // Storing Selected Value In
echo "You have selected :" .$selected_val; // Displaying Selected Value
$result = mysql_query("SELECT * FROM train_detail WHERE
Train_No='$selected_val'");
}
Here is one example of "select":
<form action="" method="post">
<select type="age" class="form-control" id="age" name="age">
<!-- <option value="disable" selected="">Please Select</option> -->
<option value="">Please select</option>
<option value="Under 35">Under 35</option>
<option value=">35 - 44">35 - 44</option>
<option value=">45 - 54">45 - 54</option>
<option value=">55 - 59">55 - 59</option>
<option value=">60 - 64">60 - 64</option>
<option value=">65 - 69">65 - 69</option>
<option value=">70 - 74">70 - 74</option>
<option value=">75 - 79">75 - 79</option>
<option value="80 +">80 +</option>
</select>
<input type="submit" value="Submit">
</form>
<?php
$age = $_POST['age'];
if (isset($_POST['age']) && $_POST['age'] == "")
echo "You did not choose any options. Pls try again.";
else {
echo $age;
}
?>
If you want embed PHP in select options, do it like this:
<option value="<?php echo $res['Train_no'] ?>"><?php echo $res['some_other'] ?></option>
For radio button it is like this:
<!DOCTYPE html>
<html>
<body>
<form action="/action_page.php">
<input type="radio" name="gender" value="<?php echo $res['Train_no'] ?>" checked><?php echo $res['some_other'] ?><br>
<input type="radio" name="gender" value="female"> Female<br>
<input type="radio" name="gender" value="other"> Other<br><br>
<input type="submit">
</form>
</body>
</html>
I am trying to submit a form value in a database with php. In form a select box value comes from database.
<?php include_once 'header.php';
$sql="SELECT uid,name FROM emitra_basic where block='$user'";
$result = $conn->query($sql);
//form validion
if(isset($_POST['submit']))
{
$eid =$_POST["eid"];
if($eid=="blank")
{
$flag=1;
$idErr="please Select E-MITRA";
}
$miatm =trim($_POST["miatm"]);
if(empty($miatm) || !preg_match("/^[a-zA-Z0-9 ]*$/",$miatm)) {
$flag=1;
$miErr="Please Enter Valid Id";
}
.............like this
if($flag==0)
{
$sqll="insert into **********";
}
//my form is
<form id="basic" method="post" name="basic">
<select class="select-style gender" name="eid">
<option value="blank">Please Select E-MITRA ID</option>
<?php
while($row=mysqli_fetch_array($result))
{
?>
<option value="<?php echo $row['uid']; ?>"><?php echo $row['uid']." (" . $row['name'] .")"; ?></option>
<?php
}
?>
</select>
<p class="contact"><label for="bid">Micro-ATM Serial No</label></p>
<input type="text" name="miatm" value ="<?php if (isset($miatm)) echo $miatm; ?>" /> <?php echo $miErr; ?>
<p class="contact"><label for="bid">Micro-ATM TID No</label></p>
<input type="text" name="tid" value ="<?php if (isset($tid)) echo $tid; ?>" /> <?php echo $tiErr; ?>
<input class="buttom" name="submit" id="submit" value="Add Me" type="submit">
Its seems Ok.but when i tried to submit the form if some of one field remain empty then its show blank value in select box.
how can i remain the same selected value in select box even if textbox remain empty.
You need to retain the value of drop down after form submit.
User selected attribute of select option.
<?php
if (isset($_POST['submit'])) {
$eid =$_POST["eid"];
if ($eid=="blank") {
$flag=1;
$idErr="please Select E-MITRA";
}
}
$sql="SELECT uid,name FROM emitra_basic where block='$user'";
$result = $conn->query($sql);
?>
<select class="select-style gender" name="eid">
<option value="blank">Please Select E-MITRA ID</option>
<?php
while($row=mysqli_fetch_array($result)) {
$selected = (isset($_POST["eid"]) && $_POST["eid"] == $row['uid']) ? 'selected="selected"' : '';
?>
<option value="<?php echo $row['uid']; ?>" <?php echo $selected;?>><?php echo $row['uid']." (" . $row['name'] .")"; ?></option>
<?php
}
?>
</select>
You need to use selected="" or selected="selected" after submission in your select tag as a attribute as:
<?
$sql="SELECT uid,name FROM emitra_basic where block='$user'";
$result = $conn->query($sql);
?>
<select class="select-style gender" name="eid">
<option value="blank">Please Select E-MITRA ID</option>
<?php
while($row=mysqli_fetch_array($result))
{
$selected = ((isset($_POST["eid"]) && $_POST["eid"] == $row['uid']) ? 'selected=""' : '');
?>
<option <?=$selected?> value="<?php echo $row['uid']; ?>"><?php echo $row['uid']." (" . $row['name'] .")"; ?></option>
<?php
}
if(isset($_POST['submit']))
{
$eid = $_POST["eid"];
if($eid=="blank")
{
$flag=1;
$idErr="please Select E-MITRA";
}
?>
</select>
Side Note:
In your question ist two lines are not inside the php, i hope this is type error.
I'm drawing data from a MySQL database that dynamically places a question with 4-5 radio button choices for the answer. These radio buttons all belong to the same group, $quest_name. The first pass of the while statement will create 4 radio buttons belonging to radio group "question_1".
It creates 30-40 of these questions on a page, each with 4 radio buttons. I want the user to fill in all there answers and the page to post back to itself with the users answers still selected and then display if they were correct or not (functionality I still have to add).
I'm trying to follow http://www.w3schools.com/php/php_form_complete.asp as an example, but use a dynamically created radio button name instead.
This is what I have thus far:
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
<?php
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$quest_num = $row["id"];
$question = $row["question"];
$option_1 = $row["option_1"];
$option_2 = $row["option_2"];
$option_3 = $row["option_3"];
$option_4 = $row["option_4"];
$option_5 = $row["option_5"];
$answer = $row["answer"];
$quest_name = "question_" . $row["id"];
echo "(" . $quest_num . ") " . $question . "<br>";
?>
<label>
<input type="radio" name=<?php echo $quest_name ?>
<?php if (isset(echo $quest_name) && echo $quest_name == echo $option_1) echo "checked"; ?>
value=<?php echo $option_1 ?>><?php echo $option_1 ?>
</label>
<br>
<label>
<input type="radio" name=<?php echo $quest_name ?>
value=<?php echo $option_2 ?>><?php echo $option_2 ?>
</label>
<br>
<label>
<input type="radio" name=<?php echo $quest_name ?>
value=<?php echo $option_3 ?>><?php echo $option_3 ?>
</label>
<br>
<label>
<input type="radio" name=<?php echo $quest_name ?>
value=<?php echo $option_4 ?>><?php echo $option_4 ?>
</label>
<br>
<br>
<?php
}
} else {
echo "0 results";
}
$conn->close();
?>
<input type="submit">
</form>
The part causing me grief so far is:
<?php if (isset(echo $quest_name) && echo $quest_name == echo $option_1) echo "checked"; ?>
I have also tried:
<?php if (isset($quest_name) && $quest_name == $option_1) echo "checked"; ?>
and:
<?php echo (isset($quest_name) && $quest_name == $option_1) ? "checked" : ""; ?>
How do you post back to the same page what they've selected? Like in this case I'm trying to say if "question_1" is set and "question_1" is equal to "converter" (the first radio button option) then have it checked when submit button is clicked.
I'm not that good at web development, but I'm trying to create a website to help my fellow electrical technician classmates.
Thanks for any help.
EDIT :
Using this line of code fixed the issue:
<?php if(isset($_POST[$quest_name]) && $_POST[$quest_name]==$option_1) { echo 'checked="checked"'; } ?>
What you need is called Radio Group. In HTML layer it is created with same name for all and different values for each like this:
<p>
<label>
<input type="radio" name="RadioGroup1" value="Value1" id="RadioGroup1_0">
Radio</label>
<br>
<label>
<input type="radio" name="RadioGroup1" value="Value2" id="RadioGroup1_1">
Radio</label>
<br>
</p>
And when you want to get the user input in php layer you go like this:
<?php
//check if Radio Group 1 is set
if(isset($_POST['RadioGroup1'])) {
// print the value of Radio Group 1 choice
echo $_POST['RadioGroup1'];
}
?>
When you want to create a Selected Radio in HTML layer you go like this:
<input name="RadioGroup1" type="radio" id="RadioGroup1_1" value="radio" checked="checked">
So you have to check if user inputs the value of which radio like this:
<label>
<input type="radio" name="RadioGroup1" value="value1" id="RadioGroup1_0" <?php if(isset($_POST['RadioGroup1']) && $_POST['RadioGroup1']=='value1') { echo ' checked="checked"'; } ?>>
Radio</label>
<br>
<label>
<input type="radio" name="RadioGroup1" value="value2" id="RadioGroup1_1" <?php if(isset($_POST['RadioGroup1']) && $_POST['RadioGroup1']=='value2') { echo ' checked="checked"'; } ?> >
Radio</label>
You could use the following:
<input type="radio" name="<?php echo $quest_name ?>" value="<?php echo $option_1 ?>"
<?php if (isset($quest_name) && ($quest_name == $option_1)) echo "checked"; ?> />
I'm developing a webpage with a select list that contains images.
I already have this:
When I select an image name in the list the image will be displayed in the div below.
<?php
// Create connection
$con=mysqli_connect("******","***","***","charts");
// Check connection
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
?>
<form method="post" action="index.php" id="nano" name="nano">
<p>
<select name="SelectBox" id="SelectBox" onchange="this.form.submit()">
<?php if($_POST['submitted'] == true){ ?>
<?php
$result = mysqli_query($con,"SELECT * FROM Nano WHERE IMAGE_NAME ='". $_POST['SelectBox']."'");
while($row = mysqli_fetch_array($result))
{ ?>
<option selected="selected" value="<?php echo $row['IMAGE_NAME'] ?>">
<?php echo $row['IMAGE_PARAMETER'] ?>
</option>
<?php } ?>
<?php echo $_POST['SelectBox']; ?></option>
<?php } else{ ?>
<?php
$result = mysqli_query($con,"SELECT TOP * FROM Nano");
while($row = mysqli_fetch_array($result))
{
?>
<option selected="selected" value="<?php echo $row['IMAGE_NAME'] ?>">
<?php echo $row['IMAGE_PARAMETER'] ?>
</option>
<?php
$var1 = $row['IMAGE_NAME']; ?>
<?php
}
?>
<?php } ?>
<option value="" disabled="disabled"> -------- </option>
<?php
$result = mysqli_query($con,"SELECT * FROM Nano");
while($row = mysqli_fetch_array($result))
{ $values[] = $row['IMAGE_NAME'];
?>
<option value="<?php echo $row['IMAGE_NAME'] ?>">
<?php echo $row['IMAGE_PARAMETER'] ?>
</option>
<?php }?>
</select>
<input type="hidden" name="submitted" id="submitted" value="true" />
</p>
<?php if($_POST['submitted'] == true){ ?>
<p><img src="Images\Nano\<?php echo $_POST['SelectBox']?>" width="953" height="600" /></p>
<?php }else { ?>
<p><img src="Images\Nano\<?php print_r($values[0]) ?>" width="953" height="600" /></p>
<?php } mysqli_close($con);?>
</form>
</div>
I want when I move down in the select list the picture will change and not when I click on it in the select list.
In your case, you have to bind hover event to option, but there is no way to do what you want using native select control. The native one only answers when you click a different option from previous.
However, you can simulate a select control using html&css&js, that way when your cursor move down the simulated option(which might be a div or something), you can bind event handlers to it and display the name.