Group 2 HTML table rows in a loop - php

I have a table query from DB. This table has few info from the DB. The rest of the info I want is to be shown when I click the collapsible. So for that I want the collapsible row just after each of the queried row. Below is my code.
It is creating as many collapsible as queried rows but all rows are together and all collapsible are together. Also The collapsible are coming before the queried rows though it should be under the queried rows.
<table class="blueTable">
<thead>
<tr>
<th>Broadband ID</th>
<th>Name</th>
<th>Email</th>
<th>Phone</th>
<th>Circle</th>
<th>SSA</th>
<th>SDCA</th>
<th>Action</th>
</tr>
</thead>
<tbody>
<?php while($row = mysqli_fetch_array($searchqry)):?>
<tr>
<td><?php echo $row['bb_id'];?></td>
<td><?php echo $row['name'];?></td>
<td><?php echo $row['email'];?></td>
<td><?php echo $row['phone'];?></td>
<td><?php echo $row['circle'];?></td>
<td><?php echo $row['ssa'];?></td>
<td><?php echo $row['sdca'];?></td>
</tr>
<tr><button class="collapsible">Open Section 3</button>
<div class="content">
<p>Lorem ipsum</p>
</div>
</tr>
<?php endwhile;?>
</tbody>
</table>
<script>
var coll = document.getElementsByClassName("collapsible");
var i;
for (i = 0; i < coll.length; i++)
{
coll[i].addEventListener("click", function()
{
this.classList.toggle("active");
var content = this.nextElementSibling;
if (content.style.maxHeight)
{
content.style.maxHeight = null;
}
else
{
content.style.maxHeight = content.scrollHeight + "px";
}
});
}
</script>

<tr>
<td colspan="8">
<button class="collapsible">Open Section 3</button>
<div class="content">
<p>Lorem ipsum</p>
</div>
</td>
</tr>
Needed to put a cell inside the row.

You are missing a <td> inside of the second <tr>.

Related

How do i hide my table in first time and show after user search something?

i'm trying to build a website where users can find location of my company, but i need to hide the information at the first time and only show the location that users needed.
Here's my code:
<?php
$condition = '';
if(isset($_REQUEST['Kota']) and $_REQUEST['Kota']!=""){
$condition .= ' AND Kota LIKE "%'.$_REQUEST['Kota'].'%" ';
}
if(isset($_REQUEST['Outlet']) and $_REQUEST['Outlet']!=""){
$condition .= ' AND Outlet LIKE "%'.$_REQUEST['Outlet'].'%" ';
}
if(isset($_REQUEST['Alamat']) and $_REQUEST['Alamat']!=""){
$condition .= ' AND Alamat LIKE "%'.$_REQUEST['Alamat'].'%" ';
}
$userData = $db->getAllRecords('lokasi','*',$condition,'ORDER BY id DESC');
?>
<div>
<table class="table table-striped table-bordered">
<thead>
<tr class="bg-primary text-white">
<th>No</th>
<th>Cabang GO</th>
<th>Nama Kota</th>
<th>Alamat Outlet</th>
<th>No Telepon</th>
</tr>
</thead>
<tbody>
<?php
$s = '';
foreach($userData as $val){
$s++;
?>
<tr>
<td><?php echo $s;?></td>
<td><?php echo $val['Kota'];?></td>
<td><?php echo $val['Outlet'];?></td>
<td><?php echo $val['Alamat'];?></td>
<td><?php echo $val['Nomor'];?></td>
</tr>
<?php } ?>
</tbody>
</table>
</div>
Start out with <div style=visibility:hidden>. Later change it to 'visible' using JavaScript code.
All the Code you have added is fine, you need few more things to add and it will be all working.
Add HTML Form with an input field for entering searching location and a submit button.
<form action="" method="post">
Search Location: <input type="text" name="location"> <input type="submit" name="submit">`enter code here`
</form>
Add "if" Condition to check the user submitted the form and the result from the db is not empty before the table, where you are displaying all the locations.
<?php if(isset($_POST['submit']) && count($userData) > 0){ ?>
<table class="table table-striped table-bordered">
<thead>
<tr class="bg-primary text-white">
<th>No</th>
<th>Cabang GO</th>
<th>Nama Kota</th>
<th>Alamat Outlet</th>
<th>No Telepon</th>
</tr>
</thead>
<tbody>
<?php
$s = '';
foreach($userData as $val){
$s++;
?>
<tr>
<td><?php echo $s;?></td>
<td><?php echo $val['Kota'];?></td>
<td><?php echo $val['Outlet'];?></td>
<td><?php echo $val['Alamat'];?></td>
<td><?php echo $val['Nomor'];?></td>
</tr>
<?php } ?>
</tbody>
</table>
<?php } ?>

Generate multiple table (For viewing)

I would like to ask on how to make my table to appear as following:
But I only manage to get my table to appear like this:
As you can see, the table is separated according to the different year or semester of when they stored their stuff. It is basically a history storage of that particular person. Unfortunately, I don't know how to make the generated table to attach together for the one with same year and semester instead of separating it. Even the numbering is affected. Below is the code that I have so far:
<?php
include("connect.php");
include("header.php");
if(isset($_GET['invstuview_bag'], $_GET['invstuview_name']))
{
$get_id = $_GET['invstuview_bag'];
$get_name = $_GET['invstuview_name'];
?>
<br/>
<ul class="breadcrumb">
<li class="breadcrumb-item">View History</li>
<li class="breadcrumb-item-active">Baggage Detail History</a></li>
</ul>
<div id="cssword">Baggage Detail History For <?php echo $get_name; ?>(<?php echo $get_id; ?>)</div>
<div class="container" style="width:70%;">
<div class="table-responsive">
<?php
$sql_join = "SELECT student.*,location.*, inventory.*, baggage.*
FROM
student,location, inventory, baggage
WHERE
student.student_id = inventory.invstu_id AND
baggage.baggage_id = inventory.invbag_id AND
location.location_id = inventory.invloc_id AND
invstu_id = '$get_id'
ORDER BY inventory_id";
$result_join= mysqli_query($connect,$sql_join);
$prev_year = "";
$prev_sem = 0;
$get_year = "";
$get_sem = 0;
while($row_join=mysqli_fetch_assoc($result_join))
{
$counter = 1;
$prev_year = $row_join["invstu_year"];
$prev_sem = $row_join["invstu_sem"];
//if the data is of same year and semester
if(($prev_year!="") && ($prev_sem!=0) && ($prev_year == $get_year) && ($prev_sem == $get_sem))
{
$get_year = $row_join["invstu_year"];
$get_sem = $row_join["invstu_sem"];
?>
<table class="table table-bordered">
<tr>
<th>No.</th>
<th>Baggage Types</th>
<th>Quantity</th>
<th>Location</th>
</tr>
<tr>
<td><?php echo $counter; ?></td>
<td><?php echo $row_join["baggage_type"]; ?></td>
<td><?php echo $row_join["invbag_quantity"]; ?></td>
<td><?php echo $row_join["location_house"]; ?></td>
</tr>
<?php
$counter++;
echo'</table>';
}
//if data is not of same year or semester
else
{
$get_year = $row_join["invstu_year"];
$get_sem = $row_join["invstu_sem"];
?>
</br></br>
Room: <?php echo $row_join["invstu_room"]; ?><br/>
Year: <?php echo $row_join["invstu_year"]; ?><br/>
Semester: <?php echo $row_join["invstu_sem"]; ?><br/>
<table class="table table-bordered">
<tr>
<th>No.</th>
<th>Baggage Types</th>
<th>Quantity</th>
<th>Location</th>
</tr>
<tr>
<td><?php echo $counter; ?></td>
<td><?php echo $row_join["baggage_type"]; ?></td>
<td><?php echo $row_join["invbag_quantity"]; ?></td>
<td><?php echo $row_join["location_house"]; ?></td>
</tr>
<?php
$counter++;
echo'</table>';
}
}
?>
</div>
<div align="right">
<button type="button" name="back" class="btn btn-success" id="back" style="width:200px; display:inline-block; margin-top:2%; margin-bottom:1%; background-color: #4CAF50" onclick="window.location.href='view.php'">Back</button>
</div>
</div>
<?php
}
?>
Any ideas is highly appreciated.
Move these out of the while loop:
<table class="table table-bordered">
<tr>
<th>No.</th>
<th>Baggage Types</th>
<th>Quantity</th>
<th>Location</th>
</tr>
echo'</table>';

MySQL not fetching all results

Trying to fetch all results in PHP from MySQL database, but it is leaving the first query.
My MySQL table is in the below image: .
My Code:
<?php
$irn = "33857";
$stmt = $user_home->runQuery('SELECT * FROM invoice WHERE Inv = :inv ORDER BY Sr ASC ');
$stmt->bindParam(':inv',$irn);
$stmt->execute();
$rowc = $stmt->fetch(PDO::FETCH_ASSOC);
if($stmt->rowCount() > 0)
{
?>
<table id="chiru_inv" class="table table-striped table-hover table-bordered table-responsive">
<tr>
<td colspan="4" align="center">
<h1>Company</br><span style="font-size: 75%;">Number</span></h1>
</td>
</tr>
<tr>
<td colspan="2">
<h3><span style="float: left;"><?php echo $rowc['Customer']; ?> (<?php echo $rowc['Inv']; ?>)</span></h3>
</td>
<td colspan="2">
<h3><span style="float: right;"><?php echo $rowc['Date']; ?></span></h3>
</td>
</tr>
<tr>
<th>Sr.</th>
<th>Item</th>
<th>Qty</th>
<th>Amount</th>
</tr>
<?php
$i = 0;
while($row=$stmt->fetch(PDO::FETCH_ASSOC))
{
extract($row);
$i++;
?>
<tr>
<td><?php echo $i; ?></td>
<td><?php echo $Item; ?></td>
<td>5</td>
<td>200</td>
</tr>
<?php
}
?>
<tr>
<td></td>
<td></td>
<td></td>
<td></td>
</tr>
<tr>
<td colspan="2"><strong><?php echo getIndianCurrency(225); ?>Only</strong></td>
<td><strong>Total:</strong></td>
<td><strong>225</strong></td>
</tr>
</table>
<?php
}
?>
The result when I execute the above code is in the below image:
There are three queries with invoice number 33857, but only two are displayed (leaving the first one)!
I need all to be displayed as per invoice number.
Please help me from sorting out the error/code I made or I left.
The problem in your code is with the line:
$rowc = $stmt->fetch(PDO::FETCH_ASSOC);
in the beginning of your code you're fetching the first row.
You have to update your while loop, like this
<?php
$i = 0;
while($rowc)
{
extract($rowc);
$i++;
?>
<!-- Your HTML/PHP code for the table -->
<?php
$rowc=$stmt->fetch(PDO::FETCH_ASSOC);
}
?>
So, the idea is to fetch the row at the end of the while loop, in order to not lose your first row.

how to create link for one user id from datatable and view only that user id detail in next page?

I have a function manage_child which it is in a datatables that show all children details. My problem is I want to view only one child details at another pages. I have tried to implement this example of code in my function but it didnt work since I call it like this:
`<td><a href="?pages=child_view"</a><?php_e($child_id); ?></td>`
I have link the page where the details should go but it didn't work. I am still in my basic using php and I use mysqli for the database.
This is the example that I tried to implement in my code but still doesn't work.
echo "<td>".$row[id]."</td>";
echo "<td>".$row[l_name]."</td>";
echo "<td>".$row[f_name]."</td>";
echo "<td>".$row[ssn]."</td>";
this is my code
function manage_child(){
$query = query("SELECT * FROM register_child");
confirm($query);
?>
<div class='container-fluid'>
<div class='row'>
<h1 class="page-header">Children
<small>Information</small>
</h1>
<div class="panel-body">
<div class="dataTable_wrapper">
<table width="50%" class="table table-striped table-bordered table-hover" id="dataTables-example">
<thead>
<tr>
<th>No</th>
<th>CHild ID</th>
<th>Child IC</th>
<th>Name</th>
<th>Address</th>
<th>Mother name</th>
</tr>
</thead>
<tbody>
<?php
$bil = 0;
while($row = fetch_array($query)) {
$password = $row['ic_no'];
$child_id = $row['child_id'];
$child_name = $row['child_name'];
$address = $row['address'];
$mother_name = $row['mother_name'];
$bil++;
?>
<tr class="odd gradeX">
<td><?php echo $bil; ?></td>
<td><?php _e($password);?></td>
<td><a href="?pages=child_view"</a><?php _e($child_id); ?></td>
<td><?php _e($child_name); ?></td>
<td><?php _e($address); ?></td>
<td><?php _e($mother_name); ?></td>
<?php
}// End of while
?>
</tbody>
</table>
</div>
</div>
</div>
</div>
<?php
}

how to pass values between tabs in a html page using php

how can I pass values/ variables between tabs in html using php
I have 3 tabs those are fetched from database. each tab has separate id.
<div class="tab-nav">
<?php while ($row1 = mysql_fetch_array($result1)) : ?>
<?php $row1['name']; ?>
<?php endwhile ?>
</div>
tabs
<div class="tab-holder">
<div class="tab">
<table class="table table-striped">
<thead>
<tr>
<th width="34%">Job Title</th>
<th width="15%">Experience</th>
<th width="29%">Location</th>
<th width="8%">Salary</th>
<th width="7%"></th>
</tr>
</thead>
<tbody>
<?php
while($row = mysql_fetch_array($result)) {
$cat = $row['cat'];
if ($cat =='6') {
$jobtitle = $row['vVacjobtitle'];
?>
<tr>
<td>
<span class="pill medium green"><?php echo $row['vVacjobtitle'] ?></span>
</td>
<td><?php echo $row['experience'] ?></td>
<td><?php echo $row['vVacLocation'] ?></td>
<td><?php echo $row['salary'] ?></td>
<td>
Apply
</td>
</tr>
<?php
}
} ?>
</tbody>
</table>
</div>
how can i get id when clicking the tab
if ($cat == 6)
i want to place id in the place of 6
Thanks in advance .. :)
Since you're passing the value of id as a GET parameter, so you can access it by $_GET['id'] in your PHP code

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