How to count row by using GROUP mysql bind_param? - php

Question

How to count row by using GROUP mysql bind_param ?
Table : check
.
__________________________
| id | product_id | user |
| 1 | 123 | test |
| 2 | 456 | test |
| 3 | 456 | test |
| 4 | 123 | test |
| 5 | 789 | test |
and this is my code
<?PHP
$username = "test";
$sql = 'SELECT COUNT(*) FROM check WHERE user = ? GROUP BY product_id';
$statement = $db_mysqli->prepare($sql);
$statement->bind_param('s', $username);
$statement->execute();
$result = $statement->get_result();
$row = $result->fetch_row();
$all_product = $row[0];
echo $all_product;
?>
When I test code it's show 5 I want to know how can I do for show 3 group by product_id

Answer 1

You need to change your SQL query.
SELECT COUNT(DISTINCT PRODUCT_ID) FROM check WHERE user = ?
this will produce a result of 3
If you wanted one row for each product, then you would do this:
SELECT product_id, COUNT(*) AS c FROM check WHERE user = ? GROUP BY product_id
which would look like this:
| product_id | c |
| 123 | 2 |
| 456 | 2 |
| 789 | 1 |

Answer 2

Try this query.
$statement=$mysqli->prepare("SELECT user,COUNT(*) FROM check GROUP BY product_id");
I hope it will help you.

Answer 3

you can use one of these three queries as per your need. It will give you results as shown below.
To get the total of rows with distinct product_id present in table-:
SELECT COUNT(DISTINCT product_id) FROM check;
Result-:
COUNT(DISTINCT product_id)
3
To get the rows with distinct product_id row-:
SELECT COUNT(DISTINCT product_id) FROM check GROUP BY product_id;
Result-:
COUNT(DISTINCT product_id)
1
1
1
To get the row with distinct product_id with the count number of duplicate product_id present in the table -:
SELECT COUNT(product_id) FROM check GROUP BY product_id
Result-:
COUNT(product_id)
2
2
1