how to sort mysql data and find position? [closed] - php

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I have mysql data of 3 rows (user_id, exam_id, marks).
I want to find each user ranking position based on marks and exam_id .
How will be the SQL query with php code for this. Please help me. Thanks in advance.
Here is partial code
$p = "SELECT * FROM IDTABLE WHERE EID = '$info[EID]'";
$rowp = mysqli_query($conn, $p);
while (($ret = mysqli_fetch_assoc($rowp)) > 0) {
$q = "SELECT * FROM INFOTABLE WHERE EID = '$ret[EID]'";
$rowq = mysqli_query($conn, $q);
while (($retq = mysqli_fetch_assoc($rowq)) > 0) {
$user[$ret['EID'] . $retq['UID']] = $retq['Marks'];
}
}
arsort($user);
var_dump($user);

Answer 1

First of all you should consider a few things:
You should always better search for an already answered question before posting a new one (it's part of stack overflow's code)
Bring more information of what you want, being as clear as possible
Giving more details (for example: you sql structure)
However, I will try to give you a hint - Hope it helps!
For example you want to order your user_id based on their marks:
select user_id from my_table order by "marks" asc;
For example you want to order your user_id based on their marks and exam_id :
select user_id from my_table order by "marks", "exam_id" asc;
For example you want to create a kind of ranking based on users's marks:
SET #rank := 0;
SELECT
*,
#rank := #rank + 1 AS rank
FROM my_table
order by marks ASC;
For example you want to get the ranking number from a specific
SET #rank := 0;
SELECT * from ( select
*,
#rank := #rank + 1
FROM my_table
order by marks ASC ) AS rank where user_id = 2;
Hope this helps! You could get more information about mysql's ranking here
Regards,