How to trim my home url on the localhost - php

Question

This is how I get my url on my localhost:
$url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];
echo $url;
it returns : http://localhost/CodeSensei/menu because I am on the menu page.
How can I trim this? I only want "http://localhost/CodeSensei"
I know I can trim it like this
echo trim($url,"menu");
But the problem is, that "menu" is dynamic, it keep changing dependes on the page. Is there any way to trim my url so it will always and only print "http://localhost/CodeSensei" in any page?

Answer 1

There are many ways to achieve this. You can play around with different string manipulators like explode() etc.
Here is a solution using explode()
$variable = "http://localhost/CodeSensei/menu";
$variable = (explode("/",$variable));
$url='';
for($i=2;$i<count($variable)-1;$i++)
{
$url .= "/".$variable[$i];
}
$final_url = "http:/".$url;
echo $final_url;
Your output
http://localhost/CodeSensei

Answer 2

This function may help you. It get a url and return the url without after the last /.
<?php
function getSubUrl($originUrl) {
$url = parse_url($originUrl);
$url['scheme'] .= '://';
$url['path'] = dirname($url['path']);
return implode($url);
}
echo getSubUrl('http://localhost/CodeSensei/menu/123') . PHP_EOL;
// http://localhost/CodeSensei/menu
echo getSubUrl('http://localhost/CodeSensei/menu') . PHP_EOL;
// http://localhost/CodeSensei
echo getSubUrl('http://localhost/CodeSensei') . PHP_EOL;
// http://localhost/
echo getSubUrl('http://localhost/') . PHP_EOL;
// http://localhost/
echo getSubUrl('http://localhost') . PHP_EOL;
// http://localhost