What i am trying to do is:
post a form when user is logged in.
but if he is not logged in then pop up login is shown to user.
and in that popup redirection URL is added to hidden field.
when popup opens and i login it redirect me to that form.
But when i try to submit form it not being submitted.
// submit button in form
$('#submitcompanyEnquiry').on('click',function(e){
e.preventDefault();
//get data attr to check if user is login
if($('#companyEnquiry').data('login')){
//companyEnquiry =>form id
//here i try to submit form
console.log('testing'); --->it is working
jQuery('#companyEnquiry').submit(); ---> //the problem is here this piece of code is executing
}else{
if($('#companyEnquiry').attr('action')!=''){
//here i added the current url to hidden field latter to used for redirection
$('#loginForm #redirectUrl').val($('#companyEnquiry').data('seotitle'));
}
//here the login popup is trigger.
jQuery("#login").trigger('click');
}
});
Things that I confirmed:
ensure that there is unique id with the
name provided.
console some value in the if block which was
running but the line of code i have mention.
PHP part is working fine i have removed the e.preventDefault();
it is works fine but doesn't achieve the require functionality.
HTML Code
<form action="<?=Route::url('default',array('controller'=>'contact','action'=>'user_contact'))?>" data-login="<?php echo $data; ?>" data-seotitle="<?=Route::url('company', array('controller'=>'listing','seotitle'=>$company_seotitle))?>" id="companyEnquiry" method="post">
<input type="hidden" name="company_to" value="<?php echo $id; ?>">
<?php if (!$auth->logged_in()) { ?>
<div class="input-group searchbox">
<input type="text" class="form-control search" placeholder="Name" name="name" required aria-describedby="basic-addon1">
</div>
<?php }else { ?>
<div class="input-group searchbox">
<input type="text" class="form-control search" placeholder="Name" required value="<?php echo $auth->get_user()->company_name; ?>" name="name" aria-describedby="basic-addon1">
</div>
<?php } ?>
<?php if (!$auth->logged_in()) { ?>
<div class="input-group searchbox">
<input type="email" class="form-control search" placeholder="email" required name="company_from" aria-describedby="basic-addon1">
</div>
<?php }else { ?>
<div class="input-group searchbox">
<input type="email" class="form-control search" placeholder="email" required value="<?php echo $auth->get_user()->companyemail; ?>" name="company_from" aria-describedby="basic-addon1">
</div>
<?php } ?>
<?php if ($auth->logged_in()) { ?>
<div class="input-group searchbox">
<input type="text" class="form-control search" placeholder="phone number" required name="phone" value="<?php echo $auth->get_user()->company_phone_1; ?>" aria-describedby="basic-addon1">
</div>
<?php } else { ?>
<div class="input-group searchbox">
<input type="text" class="form-control search" placeholder="phone number" required name="phone" aria-describedby="basic-addon1">
</div>
<?php } ?>
<div class="input-group searchbox">
<input type="text" class="form-control search" placeholder="subject" required name="subject" aria-describedby="basic-addon1">
</div>
<div class="input-group searchbox">
<input type="text" class="form-control search" placeholder="message" required name="message" aria-describedby="basic-addon1">
</div>
<input data-login="<?php echo $data; ?>" id="submitcompanyEnquiry" type="submit" name="submit" value="SEND" class="form-control blue-btn send-btn">
</form>
The problem can only exist in the way you are adding the login variable to the form with the id : companyEnquiry
Check if you have add it as correct parameter because jquerys data function will only read values which have a "data-" tag infront of it.
So your php code should look like this :
echo '<form id="companyEnquiry" ' . ($login ? 'data-login="1"' : '' . '>
Related
I am getting this error,
A PHP Error was encountered
Severity: Notice
Message: Trying to get property 'post_title' of non-object.
I cannot get the form inputs to print on the page and cannot update. Please help!
So, I have tried to update each record and only artist users are able to do that. But I cannot figure out how to show the individual post on the form page. The records saves correctly and deletes but cannot update them.
Controller
function editpost($post_id)//Edit post page
{
if (!$this->session->Role =='member,artist')
{
redirect(base_url() . 'login');
}
$data['success'] = 0;
if( !empty($this->input->post('post_title')) ) {
$data['post_title'] = $this->input->post('post_title');
$data['post'] = $this->input->post('post');
$data['active'] = 1;
/* >> file attach */
View
<form action="<?= base_url()?>starter/editpost/" method="post" class="justify-
content-center" enctype='multipart/form-data'>
<div class="form-group">
<label class="sr-only">Title</label>
<input type="text" class="form-control" placeholder="Title"
name="post_title" value="<?php echo $post->post_title; ?>">
</div>
<div class="form-group">
<label class="sr-only">Description</label>
<textarea class="form-control" placeholder="Describe it" name="post" ><?
php echo $post->post; ?></textarea>
</div>
<div class="row py-4">
<div class="col-lg-6 mx-auto">
<!-- Upload image input-->
<!-- File Button -->
<div class="col-md-5">
<input name="main_img[]" type="file" accept="image/x-png,image/gif,image/jpeg">
</div>
<br>
<br>
<p style="padding-top: 15px"><span> </span><input class="submit" type="submit" name="update"
value="Publish" /></p>
</form>
use direct the variable because you are passing just values which you are posting from form.
//like :
//for post_title
<input type="text" class="form-control" placeholder="Title"
name="post_title" value="<?php echo $post_title; ?>">
// for description
textarea class="form-control" placeholder="Describe it" name="post" ><?
php echo $post; ?></textarea>
You don't need to pass the post data in controller you can get post data anywhere
<input type="text" class="form-control" placeholder="Title" name="post_title" value="<?php echo ($this->input->post('post_title')!='')?$this->input->post('post_title'):''; ?>">
How do I get this cookies code to display properly? Both in Google Chrome and Firefox I get a dropdown suggestion from the browser. I would like to only have my own php "setcookie" to display.
PHP:
index.php:
<form action="index.php" method="POST">
<div class="row">
<div class="form-group">
<input type="email" class="form-control fill-bar" name="email" aria-describedby="emailHelp" placeholder="Email"
value="<?php
if(isset($_COOKIE["username"])) {
if(isset($_POST["email"])) {
echo($_POST["email"]);
}
} ?>" required>
</div>
<div class="form-group">
<input type="password" class="form-control fill-bar" id="passwd" name="password" placeholder="Password" value="<?php if(isset($_COOKIE["password"])) { echo $_COOKIE["password"]; } ?>" required>
</div>
<p><input type="checkbox" name="remember" class="mr-1">Remember Me</p>
Forgot your password?
<br><br><br>
<input type="submit" class="btn d-inline btn-primary register_button mr-3 w-100" id="login" name="login" value="Login">
<p class="text-center mt-3">No account yet? Register Here</p>
<br>
</div>
</div> <!-- end row -->
</form>
page-2.php: (inside if isset login button clicked)
if(!empty($_POST["remember"])) {
setcookie ("email",$_POST["email"],time()+ 3600);
setcookie ("password",$_POST["password"],time()+ 3600);
echo "Cookies Set Successfuly";
} else {
setcookie("email","");
setcookie("password","");
echo "Cookies Not Set";
}
Instead of my "setcookie", both Google and Firefox displayes these, I would like to have them not appear.
In your form, add the autocomplete attribute to your inputs and set it to off, like the following:
<form action="index.php" method="POST">
...
<div class="form-group">
<input type="password" class="form-control fill-bar" id="passwd" name="password" placeholder="Password" value="<?php if(isset($_COOKIE["password"])) { echo $_COOKIE["password"]; } ?>" autocomplete="off" required>
</div>
...
</form>
That should be enough to prevent autocomplete. However, browsers are not required to follow that attribute. You can check which browsers currently comply with the autocomplete attribute here. In the case of a browser not respecting the autocomplete attribute, you could try using methods to mangle the input names (such as jQuery plugins or by using PHP to generate random names and store those names in the user's session, and verify the form versus the session on submit).
I created an HTML form that passes variables to an exec_shell. Everything worked perfectly until I added CSS to my HTML page. The new HTML+CSS code doesn't pass the variables to the php shell_exec.
Before (working):
<body>
<form action="adduser.php" method="post">
Server: <input type="text" value="<?php echo $name; ?>" name="name"><br>
Password: <input type="text" value="<?php echo $password; ?>" name="password"><br>
<input type="submit">
</form>
</body>
After (not working):
<form action="adduser.php" method="post" class="contact3-form validate-form">
<span class="contact3-form-title">
Title
</span>
<div class="wrap-input3 validate-input" data-validate="Server Name is required">
<input class="input3" type="text" value="<?php echo $hosts; ?>" name="hosts" placeholder="Server Name or Server Group">
<span class="focus-input3"></span>
</div>
<div class="wrap-input3 validate-input" data-validate = "Valid Password is required">
<input class="input3" type="text" value="<?php echo $password; ?>" name="password" placeholder="Your Password">
<span class="focus-input3"></span>
</div>
<div class="container-contact3-form-btn">
<button class="contact3-form-btn">
Submit
</button>
</div>
</form>
I also tried:
value="<' . $hosts .'"
Is there a better way to do it than HTML ?
Thank you.
your button don't have type="submit"
I am trying to submit a form using Ajax, the problem is the validation file I made is not called at all (I checked it by putting a bit of js alert inside the PHP validation file). I searched the internet and tried a lot of solutions but none worked. Is there something wrong I am making in my code?
Here is my HTML:
<form method="post" id="signup">
<div class="form-group">
<input type="fname" name="fname" id="fname" value="" class="form-control" placeholder="Your First name" />
</div>
<div class="form-group">
<input type="lname" name="lname" id="lname" value="" class="form-control" placeholder="Your Last name" />
</div>
<div class="form-group">
<input type="email" name="email" id="email" value="" class="form-control" placeholder="Your Email" />
</div>
<div class="form-group">
<input type="password" name="password" id="password" value="" class="form-control" placeholder="Your Password" />
</div>
<div class="form-group submit-btn">
<input id="signupsumbit" type="submit" name="submit" value="Sign Up" class="btn btn-success btn-lg"/>
</div>
</form>
And here is the ajax call:
$(function (){
$('#signup').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'POST',
data: $('#signup').serialize(),
url: 'login.php',
success: function (data) {
alert("data is"+data);
}
});
});
});
Here is a bit of my PHP code:
include("connection.php");
echo "<script>alert(2)</script>";
if (isset($_GET['logout']) and $_GET['logout']==1 and isset($_COOKIE[id]))
{
setcookie("email", '', time()-60*60*24);
setcookie("password", '', time()-60*60*24);
setcookie("id", '', time()-60*60*24);
$message = "You have been logged out! Come back soon!";
}
if(mysqli_connect_error()) // if failed to connect to database
{
die("Could not connect to database"); //stop the whole script from runnning
}
if (isset($_POST['submit']) and $_POST['submit'] == 'Sign Up')
{
echo '<script>console.log(1)</script>'; //
$error = '';
$success = '';
// email validation
$email = $_POST['email'];
if (empty($_POST['email']))
{
$error .="<br />Please enter your email";
}
else
{
if (!filter_var($email, FILTER_VALIDATE_EMAIL))
{
$error .="<br />Please enter a valid email address";
}
}
.
.
.
.
?>
And of course, the PHP file I made validation at is called login.php.
As you may notice, I put two alerts in my PHP code, I alerted 2 to make sure that the file is called, and alerted 1 to make sure that the form was posted. Odds are, when I submit the form the normal way (with no AJAX), both of alerts work, but when I submit it with AJAX, none of them is alerted.
My Console shows this:
Any help would be appreciated. Thanks.
Testing your script, i found that the submit button is not sent to your login.php script. If you e.preventDefault() and then later trigger the submit, javascript was submitting the form but not the button. To fix your issue create a hidden field with name submit and value Sign Up and remove the name attribute from your submit button (don't need that) and it should work fine.
<form method="post" id="signup">
<input type="hidden" name="submit" value="Sign Up"> <!-- note this hidden field -->
<div class="form-group">
<input type="fname" name="fname" id="fname" value="" class="form-control" placeholder="Your First name" />
</div>
<div class="form-group">
<input type="lname" name="lname" id="lname" value="" class="form-control" placeholder="Your Last name" />
</div>
<div class="form-group">
<input type="email" name="email" id="email" value="" class="form-control" placeholder="Your Email" />
</div>
<div class="form-group">
<input type="password" name="password" id="password" value="" class="form-control" placeholder="Your Password" />
</div>
<div class="form-group submit-btn">
<input id="signupsumbit" type="submit" value="Sign Up" class="btn btn-success btn-lg"/><!-- note the removed name attribute -->
</div>
</form>
i do have multiple text boxes called first name,last name,phone no and so on.. and i want to clear/refresh the input typed in it on button click called as refresh or clear.the problem is that the input in these text boxes are not getting refreshed because the data in it is coming from other page and it is getting refreshed when we type some thing in it
my code is as follows:
<div class="control-group">
<input value="<?php echo $model['pros']['oppid'] ?>" name="oppid" type="hidden" id="prospectid" />
<label class="control-label">First Name </label>
<div class="controls">
<input type="text" name="f_name" pattern="[-a-zA-Z]+" required="" title="First Name is required" value="<?php echo $model['pros']["f_name"]; ?>" />
</div>
</div>
<div class="control-group">
<label class="control-label">Last Name </label>
<div class="controls">
<input type="text" name="l_name" pattern="[-a-zA-Z]+" required="" title="Last Name is required" value="<?php echo $model['pros']["l_name"];?>" />
</div>
</div>
<div class="control-group">
<label class="control-label">Primary phone </label>
<div class="controls">
<input type="tel" required="" pattern="[-0-9]+" title="Please Enter correct phone" name="pri_phone" value="<?php echo $model['pros']["pri_phone"];?>" />
</div>
</div>
and the button as
<button class="btn">New</button>
please suggest me on this...
use the following code:
$("#elementid").live('click',function(){
$(this).parents('form').find('input[type="text"]').val('');
});
Assuming that your input elements are inside of a form, and so too is your button, you can do this using jQuery:
$('button.btn').click(function(e) {
e.preventDefault();
$(this).parents('form').find('input[type="text"], input[type="tel"]').val('');
});
you can write code in jquery as:
$('#new').live('click',function(){
$('#fname').val('');
$('#lname').val('');
$('#tel').val('');
});
If your button is not within the form you can use the following
$('button.btn').click(function() {
$('.control-group input:not(:submit)').val('');
});
This will reset any type of input within the control-group divs except for submit inputs
If your reset button is within the form then BenM's answer is what you want.
$(".clearform").live('click',function(){
$(this).parents('form').find('input[type="text"], input[type="tel"],input[type="time"],input[type="email"],input[type="number"],input[type="date"],select').val('');
});