Established connection to database but rendering a blank page - php

Question

I am simply trying to display data from a table in my database.
For some reason, it keeps rendering a blank page.
I have no training at all. SO I am sure my code looks like crap. But I can usually get it to work. I researched but all I could find were connection problems. I get a 'connected successfully' message but no data and no error message.
<?php
$db_host = 'localhost';
$db_user = 'user';
$db_pass = '';
$db_name = '';
$conn = mysqli_connect($db_host, $db_user, $db_pass, $db_name);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
$query = "SELECT * FROM `my_table`";
$result = mysql_query("SHOW COLUMNS FROM `my_table`");
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_assoc($result)) {
mssql_field_name($result,0);
// print_r($row);
}
}
?>

Answer 1

$db_name = ' ' ; is Null write Your Database Name

Answer 2

You should first provide a $db_name, because it's currently blank

Answer 3

$db_pass = '';
you need to provide your database name in here, else your application is literally trying to connect to nothing

Answer 4

You might have to check $mysqli_connect, that the $db_name=''; is null...put your database name inside ''

Answer 5

try like this.
<?php
$conn=mysqli_connect('localhost','root',' ','databasename');
$query="Select * from my_table";
$result = mysqli_query($conn,$query);?>
<table>
<tr>
<th>name</th>
<th>full_name</th>
</tr>
<?php
while($row = mysqli_fetch_assoc($result)) { ?>
<tr>
<td><?php echo $row["name"]; ?></td>
<td><?php echo $row["full_name"]; ?></td>
</tr>
<?php
}
?>

Answer 6

Please add your database name and database password, then you can try like this :
$sql = "Select * from table_name";
if ($result=mysqli_query($conn,$sql))
{
// Fetch one and one row
while ($row=mysqli_fetch_row($result))
{
$response[] = $row;
}
} else {
echo 'Could not run query: ' . mysqli_error();
exit;
}
print_r($response);