table not get updated after clicking update link - php

Question

I'm new to PHP, trying to update table in php when i clicked on update link it show message "Not Updated".where i went wrong?
following is the code which is executed when update link is clicked.
<?php
$servername='localhost';
$username='root';
$password='';
$dbname = "registration";
$conn=mysqli_connect($servername,$username,$password,$dbname);
$sql= 'UPDATE members_t SET Fname =$_POST[FIRSTNAME], Lname
=$_POST[LASTNAME], Memail = $_POST[EMAIL],Mcontact = $_POST[CONTACT],Mwhtap
= $_POST[WHATSAPP], Maddress = $_POST[ADDRESS], Mprofession =
$_POST[PROFESSION], WHERE id= $_POST[id]';
if(mysqli_query($conn, $sql))
header("refresh:1; url=up.php");
else
echo "Not Updated";
?>

Answer 1

Please execute the following script :
<?php
$servername="localhost";
$username="root";
$password="";
$dbname = "registration";
$conn=mysqli_connect($servername,$username,$password,$dbname);
if (!$conn){
die("Connection failed: " . mysqli_connect_error());
}
$firstName = $_POST["FIRSTNAME"];
$lastName = $_POST["LASTNAME"];
$email = $_POST["EMAIL"];
$contact = $_POST["CONTACT"];
$whatsapp = $_POST["WHATSAPP"];
$address = $_POST["ADDRESS"];
$profession = $_POST["PROFESSION"];
$id = $_POST["id"];
$sql= "UPDATE `members_t` SET `FIRSTNAME` = '$firstName',`LASTNAME` = '$lastName',`EMAIL` = '$email' ,`CONTACT` = $contact,`WHATSAPP` = $whatsapp, `ADDRESS` = '$address', `PROFESSION` = '$profession' WHERE id = $id";
if(mysqli_query($conn, $sql)){
header("refresh:1; url=up.php");
}else{
echo "Not Updated";
}
?>
If any error occurs then execute the sql statement in phpmyadmin or MySQL Workbench and share the error thrown(if any).
You have created a Table with the following column names : FIRSTNAME, LASTNAME , EMAIL, CONTACT, WHATSAPP,ADDRESS,PROFESSION but you're using Fname,Lname,Memail,Mcontact and so on. Also your create table query is not correct , theres a syntax error :
CREATE TABLE MEMBERS_T(id INT(6) NOT NULL PRIMARY KEY AUTO_INCREMENT, FIRSTNAME VARCHAR(30), LASTNAME VARCHAR(30), EMAIL VARCHAR(30), CONTACT INT(20), WHATSAPP INT(20), ADDRESS VARCHAR(50), PROFESSION VARCHAR(30));
The code has been updated according to your table and should work.