Normally data retrieved as an object from database in Laravel when we use get() function. But I want to retrieved data as an array.
In CodeIgnitor we use get_array(). What we use in Laravel ?
I have already tried with toArray(). But no result.
$doctor_result = Doctor::select('*')->toArray();
How to solve that?
I got result. just change the code
$doctor_result = Doctor::all()->toArray();
You can also do like this.
$result = DB::table('tableName')->get();
$resultArray = $result->toArray();
second way, but some tricky.
$resultArray = json_decode(json_encode($result), true);
Related
I have inserted values into database for multiple selection like this somevalue1, somevalue2, somevalue3 in Laravel using implode function.
Controller.php
$project_name=$request->project_name;
$project_id=$request->project_id;
$client_id=$request->client_id;
$project_status=$request->project_status;
$approver = implode(",",Input::get(array('approver')));
I want value in separately not like somevalue1, somevalue2. How can I solved this?
You can use json_encode during saving to database.
$save_approver = json_encode($request->approver);
and json_decode when retrieving from database.
$get_approver = json_decode($your_variable, TRUE);
foreach($get_approver as $value){
// operations
}
I have retrieved some data from db using:
$filtered = DB::table('tmp_table')->distinct()->select('type','description','note')->get();
and I would like to insert what I have retrieved in another table like:
DB::table('tmp_other')->insert($filtered);
but I receive thie error:
Type error: Argument 1 passed to Illuminate\Database\Query\Builder::insert() must be of the type array, object given
which is the best way to do this?
The SQL way to do blunk inserts of this is something more native like :
DB::insert(
"INSERT INTO tmp_other (type,description,note)
SELECT DISTINCT type,description,note FROM tmp_table"
);
This will avoid the whole transfer to webserver/transfer back to the SQL server process.
this will do the trick for you try this :)
$filtered = DB::table('tmp_table')->distinct()->select('type','description','note')->get();
$filtered->toArray();
DB::table('tmp_other')->insert($filtered);
This will do the trick :)
$filtered = DB::table('tmp_table')->distinct()->select('type','description','note')->get()->toArray();
$to_fill = [];
foreach($filtered as $record) {
$to_fill[] = (array)$record;
}
DB::table('tmp_other')->insert($to_fill);
You can do it one line, like this:
Region::insert($tempCollection->toArray());
I have found that:
Region::insert($tempCollection->toArray());
Doesn't work when you have appends in the model. This does not happen if you use getAttributes on each model. Therefore, this should be safe:
Region::insert($tempCollection->map(fn($x) => $x->getAttributes())->toArray()
I have read a-lot of answers on this but they don't seem to be working.
I have the following code:
$amountoflikes=mysql_query("SELECT * FROM `uc_likes` WHERE `dwable` = '372'");
This returns the following:
If I wanted to echo the value of dwable in the 2nd row for instance (not involving the initial query).
I've tried:
while($row3 = mysql_fetch_assoc($amountoflikes)){
$json[] = $row3;
}
echo json_encode($json);
But this returns null.
I'm currently using PHP 5.5 (native).
I'm not using MySQLi or MySQL PDO.
Can someone tell me where I'm going wrong. Ideally I'd prefer not to use a loop but I don't know if that's possible.
Thanks!
Try declaring $json as an array above the while:
$json = array();
declare your array as follows
$json = array();
and see if you have results before your result
if ($amountoflikes)
{
while(){...}
}
I am little bit struggling in setting array in session.
Here is my code:-
Controller:
function taketest(){
$this->load->model('', '');
$questions_for_test = $this->session->userdata('questions_for_test');
$difficulty_level = $this->session->userdata('difficulty_level');
$question_id = $this->session->userdata('question_id');
if($question_id==""){
$question_id = $this->myjcat->returnRandomQuestion($questions_for_test,$difficulty_level);
$this->session->set_userdata('question_id',$question_id);
}
$question_details = $this->myjcat->getQuestion($question_id);
}
Model:
function returnRandomQuestion($questions_for_test, $difficulty_level){
$question_id = array_rand($questions_for_test[$difficulty_level], 1);
$used_question=array();
$used_questions=$questions_for_test[$difficulty_level][$question_id];
$this->session->set_userdata('used_questions',$used_questions);
return $questions_for_test[$difficulty_level][$question_id];
}
But when I call:
$used_questions = $this->session->userdata('used_questions');
in controller
in the controller it will not return me an array.It gives me last value stored in it.
I could be misreading things, but it looks like you are only storing one value.
// this code:
$used_questions=$questions_for_test[$difficulty_level][$question_id];
$this->session->set_userdata('used_questions',$used_questions);
// is the same as this code
$this->session->set_userdata('used_questions',$questions_for_test[$difficulty_level][$question_id]);
You're probably looking for this:
// fetch the stored copy first.
$used_questions = $this->session->userdata('used_questions');
if(!is_array($used_questions)) $used_questions = array();
// note the []
$used_questions[] = $questions_for_test[$difficulty_level][$question_id];
$this->session->set_userdata('used_questions',$used_questions);
You can set array values in session data like this :-
$this->session->set_userdata('used_questions', json_encode($used_questions));
And retrieve the data as :-
json_decode($this->session->userdata('used_questions'));
If you want the retrieved array data as associative array :-
json_decode($this->session->userdata('used_questions'), true);
Hope it hepls you :)
The problem is that $used_questions is storing the value stored in $questions_for_test[$difficulty_level][$question_id] and not the array.
So do this $this->session->set_userdata('used_questions',$questions_for_test);
This is because the data you pass to the $used_questions is a value.
You might want to do something like this:
array_push($used_questions, $questions_for_test[$difficulty_level][$question_id]);
*appending / adding a new value to an array
I have the following in php:
$query = mysql_query($sql);
$rows = mysql_num_rows($query);
$data['course_num']=$rows;
$data['course_data'] = array();
while ($fetch = mysql_fetch_assoc($query) )
{
$courseData = array(
'course_name'=>$fetch['course_name'],
'training_field'=>$fetch['training_field'],
'speciality_field'=>$fetch['speciality_field'],
'language'=>$fetch['language'],
'description'=>$fetch['description'],
'type'=>$fetch['type'],
);
array_push($data['course_data'],$courseData);
}
echo json_encode($data);
when I receive the result of this script in jquery (using post)
I log it using :
console.log(data['course_data']);
and the output is :
[Object { course_name="Introduction to C++", training_field="Engineering" , speciality_field="Software", more...}]
But I can't seem to figure out how to access the elements.
I tried
data['course_data'].course_name
data['course_data']['course_name']
Nothing worked. Any ideas
When you array_push($data['course_data'],$courseData); you are actually putting $courseData at $data['course_data'][0] and therefore you would access it in JavaScript as data['course_data'][0]['course_name'].
If you only intend to have one result, instead of array_push($data['course_data'],$courseData); you should just specify $data['course_data'] = $courseData. Otherwise, you should iterate over data['course_data'] like so:
for (i in data['course_data']) {
console.log(data['course_data'][i]['course_name']);
}
You should specify the index in the first array for instance
data['course_data'][0]['course_name'];
you could make it better if you had defined the first array just as variable not a variable within an array
$data['course_data'][0]['course_name']
should do the trick. If not please send the output of var_dump($data)
Assuming the PHP code is correct, you will receive a JSON data like:
{
"course_num":34,
"course_data":[
{
"course_name":"name_value",
....
},
....etc (other object based on SQL result)
]
}
So, if you want to access to the total number of result:
data.course_num
If you want to access to the first element of the list of result:
data.course_data[0]
If you want to access to the name of the first element of the list of result:
data.course_data[0].course_name
or
data.course_data[0]['course_name']
use jquery's parseJSON method to get all the goodies out of the json object...
http://api.jquery.com/jQuery.parseJSON/