PHP MYSQL ARRAY check if string is in array - php

Question

I have user input which in this case will be Hello
$command = mysqli_real_escape_string($con,$_POST['command']);
a variable called $dialogue_unlock is populated through some scripts. Which for testing will output 'Hello','Goodbye'
$dialogue_unlock .= ',\''. $discuss_row['discussion_text'].'\'';
Im then trying to see if the user input matches the array
$dialogue_array = array($dialogue_unlock);
if(!in_array("$command", $dialogue_array)){
$err .= 'Invalid Question';
}
As a test im using
echo $err. '<br>';
echo $command. '<br>';
echo $dialogue_unlock;
I get
Invalid Question
Hello
'Hello','Goodbye'
I just cant wrap my head around it as 'hello' is definitely in 'Hello','Goodbye'. Can anybody offer some advise please.
Many thanks.

Answer 1

It looks as though your array contains the 1 element with the text 'Hello','Goodbye' and when you look for Hello it doesn't match. What you should do is add each item of $discuss_row['discussion_text'] to $dialogue_array directly using (in whatever loop you build up $dialogue_unlock)
$dialogue_array[] = $discuss_row['discussion_text'];
So when you add Hello and Goodbye then it will be two separate elements in the array.
Just make sure that before this loop you initialise the array...
$dialogue_array = [];

Answer 2

Try this.
$command = mysqli_real_escape_string($con,$_POST['command']); /// hello
$dialogue_unlock .= ',\''. $discuss_row['discussion_text'].'\''; /// 'Hello','Goodbye'
$dialogue_unlock = explode(',', $dialogue_unlock); /// dialogue_unlock to array
foreach ($dialogue_unlock as $a) {
if (strpos($command, $a) !== FALSE) {
echo "Match found";
}
else
{
echo "Not found!";
}
}