PHP Not inserting record due to Null id - php

Question

I want insert record into database using
I have 3 files
config.php (For database connection )
function.php (It's for create function of CRUD)
emp.php (Hear i called function from functions.php)
1. config.php file
<?php
$servername = "localhost";
$username = "root";
$password = "";
// Create connection
$conn = mysqli_connect($servername, $username, $password) ;
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$db =mysqli_select_db($conn,"test");
?>
2. function.php
<?php
include('config.php');
function addRecord($table,$columns,$val){
$insertQuery = "INSERT INTO ".$table." ($columns) VALUES('".$val."')";
return $insertQuery;
}
?>
3. emp.php
Hear i called addRecord function from function.php file for add record into database.
<?php
include('config.php');
include('function.php');
$columns= array('employee_name','employee_salary','employee_age');
$values =array('Jack','12000','15');
$val = "".implode("','", $values)."";
$col = "`".implode("`,`", $columns)."`";
addRecord('employee',$col,$val);
It's given me warning because of i passed NULL in $values array so during add record it's display Warning: Missing argument
Note: id is auto increment in DB
When i print query it's showing
INSERT INTO employee VALUES('Jack','12000','15');
And i used same query in mysql it's given error
#1136 - Column count doesn't match value count at row 1
Someone please help me where i need to change in my code.

Answer 1

Your functions are slightly off.
function addRecord($table,$coloumn,$values){
$insertQuery = "INSERT INTO ".$table." VALUES('".$values."')";
}
This does not return anything, also, the variable $coloumn is never used.
I cannot see where your actual mysql insert is happening, but as that function doesn't do anything except assign a string to a variable, it cannot do anything.
It's given me warning because of i passed NULL in $values array so during add record it's display
You are calling this function as addRecord('employee',$val);, and as you can see, you are passing $val where $coloumn should be, remove $coloumn from the function, and that warning will go away
Also
$columns= array('id','employee_name','employee_salary','employee_age');
$values =array(NULL,'Jack','12000','15');
should be
$columns= array('employee_name','employee_salary','employee_age');
$values =array('Jack','12000','15');
Then:
function addRecord($table,$values){
return "INSERT INTO ".$table." VALUES('".$values."')";
}
$addQuery = addRecord('employee',$val);
and use $addQuery in your statement.
1136 - Column count doesn't match value count at row 1
This is because you are not specifying which columns to insert, and MySQL knows that there are 4 columns, including the ID, and you are giving it three values.
Your query should be:
INSERT INTO employee (employee_name, employee_salary, employee_age) VALUES('Jack','12000','15');

Answer 2

Change :
$columns= array('id','employee_name','employee_salary','employee_age');
$values =array(NULL,'Jack','12000','15');
to
$columns= array('employee_name','employee_salary','employee_age');
$values =array('Jack','12000','15');