PHP fetch data from mysql and show accordingly - php

Question

I have a database with products and categories tables. I have managed to show the product category and It's related products. And It's currently looks like following.
But I need this to be done like
Category B
Product 1
Category A
Product 2
Product 3
Product 4
Product 5
Following is my query
<?php
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
?>
<h1><?php echo $row["name"];?></h1>
<p><?php echo $row["prod_desc"];?></p>
<?php echo $row["prod_name"]; ?>
<?php echo $row["quantity"]; ?>
<?php echo $row["buy_price"]; ?>
<?php
}
}
?>

Answer 1

Rearrange array first then try to use it for showing data
<?php
$final_array = [];
if(mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_array($result)){
$final_array[$row["name"]][] = ['prod_desc'=>$row["prod_desc"],'prod_name'=>$row["prod_name"],'quantity'=>$row["quantity"],'price'=>$row["buy_price"]];
}
?>
<?php foreach($final_array as $key=>$val){?>
<h1><?php echo $key;?></h1>
<?php foreach($val as $v){?>
<p><?php echo $v["prod_desc"];?></p>
<?php echo $v["prod_name"]; ?>
<?php echo $row["quantity"]; ?>
<?php echo $row["buy_price"]."<br><br>"; ?>
<?php } ?>
<?php } ?>
<?php }?>

Answer 2

Try to store last used category and check if it changed:
<?php
$category='';
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
if($category!=$row["name"]) {
?>
<h1><?php echo $row["name"];?></h1>
?>
}
$category=$row["name"];
<?php
<p><?php echo $row["prod_desc"];?></p>
<?php echo $row["prod_name"]; ?>
<?php echo $row["quantity"]; ?>
<?php echo $row["buy_price"]; ?>
<?php
}
}
?>
Remember to sort output data by category in SQL query