I know POST method is pointing to add() in a controller as default in cakephp3. Is it possible to custom that and point POST method to index()? Something like below:
Router::connect(
'/test',
array(
'controller' => 'Test',
'action' => 'index',
'[method]' => 'POST'
)
);
Thanks to #ndm who made a very clear solution for my question.
One of my issue is that I have $routes->resources('Test'); which will disable #ndm's solutions. So first of all, I commented out the line $routes->resources('Test');.
Because of I'm not working on a solid project which is a temporary project for a narrowed purpose, so below code is working perfectly for me now.
Router::scope('/', function ($routes) {
$routes->setExtensions(['json']);
// $routes->resources('Test');
$routes->post(
'/test',
['controller' => 'Test', 'action' => 'add']
);
});
Related
I'm trying to use my index controller to create a url structure like this: mydomain.com/vehiclemake/vehiclemodel/vehiclemodelyear
I don't know how to alter the default route, or alter a duplicate that will work as intended. Every time I load the page once a make has been added to the url, it gives me a blank screen and the logs tell me it can't find a controller with the name of the vehicle make that was in the url. Below is the default and what I've tried.
Route::set('vehicle', '(/<make>(/<model>(/<model_year>)))')
->defaults(array(
'controller' => 'index',
'action' => 'index',
));
Route::set('default', '(<controller>(/<action>(/<id>)))')
->defaults(array(
'controller' => 'index',
'action' => 'index',
));
I've tried looking for an answer here on stackoverflow but I haven't found a question that's similar to mine that has an answer.
I'm not sure if I understand your question right.
Anyway, you won't need the first / before .
Besides that, this structure will require a controller for every make and in that controller an action for every model. I think something like the code below will work for the uri: /ferrari/testarossa/1992
class Ferrari extends controller {
public function action_testarossa() {
// whatever you'd like to do
echo $this->request->param('model_year');
}
}
I think the default in routing always is, but I'm not sure.
1. controller
2. action
3. whateveryoudefine
4. whateveryoudefine
Hope this helps!
You must plan your routing so that one URL cannot be matched to 2 routes. I suggest:
Route::set('vehicle', '/<make>(/<model>(/<model_year>))')
->defaults(array(
'controller' => 'vehicle',
'action' => 'index',
));
Route::set('mainpage', '/')
->defaults(array(
'controller' => 'index',
'action' => 'index',
));
Route::set('default', '<controller>(/<action>(/<id>))', ['controller'=>'(index|user)'])
->defaults(array(
'controller' => 'index',
'action' => 'index',
));
Note that I removed 1 pair of brackets. And for default route correct controllers are: index and user.
I'm trying to load the VideoController.php when url.com/video/ is called.
Here is a piece of code from my routes.php
Router::scope('/', function (RouteBuilder $routes) {
$routes->connect('/video/*', ['controller' => 'Video', 'action' => 'display']);
...
$routes->fallbacks(DashedRoute::class);
});
The result is '404 not found'
EDIT:
Inside Router::scope I have also this piece of code:
$routes->connect('/', ['controller' => 'Pages', 'action' => 'display', 'home']);
When I change the Pages value into Video, the VideoController is called. So how come when I change the '/' into '/video/*' it doesn't work?
Maybe it's something with the scope function parameters?
Enabling URL rewriting from the httpd.config file solved the problem.
cakephp documentation
Recently, I've been studying cake, I've seen the auth library which said to be will take care of the access control over your app, but, it seems like, you can't initialize or even use this auth library when you're not in the 'UsersController', i did not want that, what if it has some admin part wherein i want the URI to be admin/login, or just simply /login, i've been scratching my head over this one, please help.
Another question, why it seems like the functionality of the '$this->redirect' is not effective when i'm putting this one at any method that contains nothing but redirection, or even in the __construct()?
thanks guys, hoping someone could clearly explain to me those things.
you can use the Auth component inside any controller in the application. If you want it will only effect with the admin section then you can add condition in the beforeFilter funciton in you application AppController on Auth initialization like.
// for component initialization.
public $components = array(
'Auth' => array(
'authenticate' => array(
'userModel' => 'Customer', // you can also specify the differnt model instead of user
'Form' => array(
'fields' => array('username' => 'email')
)
)
)
}
and you can bind this on the admin routing like
function beforeFilter(){
// only works with admin routing.
if(isset($this->request->params['prefix']) && ($this->request->params['prefix'] == 'admin')){
$this->Auth->loginRedirect = array('admin' => true, 'controller' => 'pages', 'action' => 'index');
$this->Auth->logoutRedirect = array('controller' => 'users', 'action' => 'login', 'admin' => true);
$this->Auth->loginAction = array('admin' => true, 'controller' => 'customers', 'action' => 'login');
}
}
If you're using cake 2.3.x or later then make sure you have specified the redirect action in correct format like.
return $this->redirect('action_name'); // you can also specify the array of parameters.
I obviously have a fundamental misunderstanding of how pagination works in CakePHP.
I have the following route set up which shows all posts in a category:
Router::connect('/:parent/:category',
array('controller' => 'posts', 'action' => 'viewCategory'),
array('parent' => '[a-z0-9-]+', 'category' => '[a-z0-9-]+'));
The pages work fine, however the pagination helper is outputting the wrong links for pagination.
I'm using $this->Paginator->numbers().
It's outputting links in this format: mysite.com/posts/viewCategory?page=2
rather than like this: mysite.com/parent-category/sub-category?page=2.
I've tried adding the following route after the first one and it still doesn't work:
Router::connect('/:parent/:category/:page',
array('controller' => 'posts', 'action' => 'viewCategory'),
array('parent' => '[a-z0-9-]+',
'category' => '[a-z0-9-]+',
'page' => '[0-9]+'));
For reference, my pagination options set in my view are as so:
<?php $this->Paginator->options(
array('url' =>
array('controller' => 'posts', 'action' => 'viewCategory')
)); ?>
What am I doing wrong here?
You are setting the url yourself
This is your paginator options call:
<?php
$this->Paginator->options(array(
'url' => array(
'controller' => 'posts',
'action' => 'viewCategory'
)
));
?>
Where you are overriding the current url - and explicitly requesting that the paginator uses the the '/posts/viewCategory' url (with no arguments) as it's base url.
Just don't define the url
Simply don't call options and the helper will use the current url - that should mean that if the current url is:
/parent-category/sub-category
Then page 2 will be (assuming you are using the paramType option to use GET arguments rather than named parameters):
/parent-category/sub-category?page=2
If that's not the case there's information missing from the question; it's important to distinguish between "vanity routes not being used" and "the url is not equivalent (the current situation).
Just had a battle fixing something similar and came across this post. Though old, but I think my answer might save someone the time I had to spend fixing it.
Basically, what you need to do is call the Paginator->options() before Paginator->numbers(), thus:
$this->Paginator->options(
array(
'controller' => 'parent-category',
'action' => 'sub-category'
)
);
Though the controller and action do not exist, it just tricks CakePHP to use them "AS IS", since the reverse routing isn't working!
And for those (like me), who want have set up a route similar to
Router::connect(
'/go/page:id',
array(
'controller' => 'blog',
'action' => 'paginated'
)
);
There might be difficulty setting up the Paginator options. This, however, worked for me:
$this->Paginator->options(
array(
'controller' => 'go',
'action' => '/'
)
);
I guess you know why it worked ;)
I've set the following routes for in Zf:
$router->addRoute(
'page',
new Zend_Controller_Router_Route('stranka/:niceuri/:id', array('controller' => 'page', 'action' => 'index'))
);
$router->addRoute(
'cat',
new Zend_Controller_Router_Route('kategoria/:niceuri/:id', array('controller' => 'category', 'action' => 'index'))
);
The problem is that the 'cat' route keeps overwriting the other 'page' route and simle $this->url() routes aswell. That means, that any links using the 'page' route and having the param 'niceuri' defined have the the value of 'niceuri' equal to the currently open page using the 'cat' route - which they sholdn't have. (sorry, does that make sense to you?) Any ideas on how to solve this behavior? Thanks a lot.
I didn't exactly understand what did you mean, but...
When you calling $this->uri helper in view you can set the name of the preffered router to use to assemble the url. Something like this:
echo $this->uri(array('niceuri' => 'Ololo', 'id' => '123'), 'page');
Hope this helps.