I would like to convert the timestamps from ten minutes ago and now to match the following format:
2018-09-23T04:47:07.237
Here are the timestamps I'd like to convert to match the above format:
$now = date('m/d/y g:i a');
$now = strtotime($now);
$ten_minutes_ago = strtotime('-10 minutes');
How can I do this? Thanks!
Use date_format function instead. You don't need to convert to UNIX timestamp using strtotime function. Instead use DateTime library
Check the following (Rextester Demo):
$now = new DateTime(); // create a datetime object
$sub = new DateInterval("PT10M"); // Interval of 10 mins
$ten_minutes_ago = new DateTime();
$ten_minutes_ago->sub($sub); // subtract 10 minutes
// changed formats
$now_changed = date_format($now, DATE_ISO8601);
$ten_minutes_ago_changed = date_format($ten_minutes_ago, DATE_ISO8601);
// print output
echo $now_changed; //2018-09-23T02:58:25-0400
echo $ten_minutes_ago_changed; // 2018-09-23T02:48:25-0400
Details:
The date_format() function returns a date formatted according to the specified format.
DATE_ISO8601 - ISO-8601 (example: 2013-04-12T15:52:01+0000)
You can check for more formatting options here.
Here is how I would do what you are asking for.
If your data is in a string. Here is the only line of code you need:
$date = date('m/d/y g:i a'); //Gets a date string.
echo substr(date('Y-m-d\TH:i:s.u', strtotime($date . ' -10 minutes')), 0, -3); // PHP < 7.0.0
//echo date('Y-m-d\TH:i:s.v', strtotime($date . ' -10 minutes')); //PHP > 7.0.0
This will produce:
Ex.
09/23/18 12:13 am
To
2018-09-23T00:03:00.000
One thing to note here. The microseconds will always be zeros if your original input date is a string and in the format m/d/y g:i a that you have specified. The reason being is that there is no millisecond information to be had from the date string.
If you create you input date as a dateTime object, the object will be able to keep track of the microseconds for you.
Related
I have a timestamp stored in a session (1299446702).
How can I convert that to a readable date/time in PHP? I have tried srttotime, etc. to no avail.
Use PHP's date() function.
Example:
echo date('m/d/Y', 1299446702);
strtotime makes a date string into a timestamp. You want to do the opposite, which is date. The typical mysql date format is date('Y-m-d H:i:s'); Check the manual page for what other letters represent.
If you have a timestamp that you want to use (apparently you do), it is the second argument of date().
I just added H:i:s to Rocket's answer to get the time along with the date.
echo date('m/d/Y H:i:s', 1299446702);
Output: 03/06/2011 16:25:02
$timestamp = 1465298940;
$datetimeFormat = 'Y-m-d H:i:s';
$date = new \DateTime();
// If you must have use time zones
// $date = new \DateTime('now', new \DateTimeZone('Europe/Helsinki'));
$date->setTimestamp($timestamp);
echo $date->format($datetimeFormat);
result: 2016-06-07 14:29:00
Other time zones:
Africa
America
Antarctica
Arctic
Asia
Atlantic
Australia
Europe
Indian
Pacific
Others
If you are using PHP date(), you can use this code to get the date, time, second, etc.
$time = time(); // you have 1299446702 in time
$year = $time/31556926 % 12; // to get year
$week = $time / 604800 % 52; // to get weeks
$hour = $time / 3600 % 24; // to get hours
$minute = $time / 60 % 60; // to get minutes
$second = $time % 60; // to get seconds
If anyone wants timestamp conversion directly to a DateTime object, there's a simple one-liner:
$timestamp = 1299446702;
$date = DateTime::createFromFormat('U', $timestamp);
Following #sromero comment, timezone parameter (the 3rd param in DateTime::createFromFormat()) is ignored when unix timestamp is passed, so the below code is unnecessary.
$date = DateTime::createFromFormat('U', $timestamp, new DateTimeZone('UTC'); // not needed, 3rd parameter is ignored
You may check PHP's manual for DateTime::createFromFormat for more info and options.
Try this one:
echo date('m/d/Y H:i:s', 1541843467);
$epoch = 1483228800;
$dt = new DateTime("#$epoch"); // convert UNIX timestamp to PHP DateTime
echo $dt->format('Y-m-d H:i:s'); // output = 2017-01-01 00:00:00
In the examples above "r" and "Y-m-d H:i:s" are PHP date formats, other examples:
Format Output
r ----- Wed, 15 Mar 2017 12:00:00 +0100 (RFC 2822 date)
c ----- 2017-03-15T12:00:00+01:00 (ISO 8601 date)
M/d/Y ----- Mar/15/2017
d-m-Y ----- 15-03-2017
Y-m-d H:i:s ----- 2017-03-15 12:00:00
Try it.
<?php
$timestamp=1333342365;
echo gmdate("Y-m-d\TH:i:s\Z", $timestamp);
?>
You can try this:
$mytimestamp = 1465298940;
echo gmdate("m-d-Y", $mytimestamp);
Output :
06-07-2016
Unless you need a custom date and time format, it's easier, less error-prone, and more readable to use one of the built-in date time format constants:
echo date(DATE_RFC822, 1368496604);
echo date("l M j, Y",$res1['timep']);
This is really good for converting a unix timestamp to a readable date along with day. Example:
Thursday Jul 7, 2016
echo 'Le '.date('d/m/Y', 1234567890).' à '.date('H:i:s', 1234567890);
I have used this:
<?php echo date('d/m/Y H:i a', $row['start_time']); ?>
1532131481886863
I tried the code below and don't work it gives me wrong date , i think has something to do with the amount of digits
$epoch = 1532131481886863;
$dt = new DateTime("#$epoch"); // convert UNIX timestamp to PHP DateTime
echo $dt->format('Y-m-d H:i:s');
The only thing I can think of is that the last six digits is microseconds.
So splitting the number will give you correct date and time.
echo date("Y-m-d H:i:s", substr($epoch, 0,-6));
// Optionally you can echo the microseconds also.
echo " " . substr($epoch, -6);
https://3v4l.org/QDQnc
<?php
// Divide by 1000*1000 because given number is epoch with microseconds
// but the DateTime expects time in seconds
// By dividing we will get 1532131481.886863
// We dont need the microseconds so we cast (int) on it to get 1532131481
$epoch = (int)((1532131481886863 /1000) /1000);
$dt = new DateTime("#$epoch"); // convert UNIX timestamp to PHP DateTime
echo $dt->format('Y-m-d H:i:s');
I am trying to add minutes to current date but it returns strange results
date_default_timezone_set('Asia/Karachi');
$currentDate = date("m-d-Y H:i:s");
$currentDate_timestamp = strtotime($currentDate);
$endDate_months = strtotime("+10 minutes", $currentDate_timestamp);
$packageEndDate = date("m-d-Y H:i:s", $endDate_months);
echo " <br> " . $packageEndDate . " <br> ";
echo $currentDate;
I am getting Output
01-01-1970 05:50:00
07-19-2013 20:25:23
It should return
07-19-2013 20:35:23
07-19-2013 20:25:23
After this I need to query to database so date format should be same. Database column is of string type.
Your code is redundant. Why format a timestamp as a string, then convert that string back to a timestamp?
Try
$now = time();
$ten_minutes = $now + (10 * 60);
$startDate = date('m-d-Y H:i:s', $now);
$endDate = date('m-d-Y H:i:s', $ten_minutes);
instead.
Probably the minimalist way would be:
date_default_timezone_set('Asia/Baku');
$packageEndDate = date('Y-m-d H:i:s', strtotime('+10 minute'));
echo $packageEndDate;
Output (Current time in my city at the time of writing):
2017-07-20 12:45:17
Try this:
$now = time();
$tenMinFromNow = date("m-d-Y H:i:s", strtotime('+10 minutes', $time));
$tenMinsFromNow = (new \DateTime())->add(new \DateInterval('PT10M'));
Will leave you with a DateTime object representing a time 10 minutes in the future. Which will allow you to do something like:-
echo $tenMinsFromNow->format('d/m/Y H:i:s');
See it working
PHP version >= 5.4 I'm afraid, but you should be using at least that version by now anyway.
Pakistan, which is the localisation explicitly set, uses "DD-MM-YYYY" format dates so the problem occurs when you cast the date into a string of "MM-DD-YYYY". This American format of date is not parseable by the Pakistan localisation.
If you still want to keep the round-trip to a string and back, use DD-MM-YYYY or the ISO datetime format.
While this is the only (current) answer which actually explains your original issue, I recommend the code be refactored as others have demonstrated.
I'm writing code to subtract two dates. It is for a contract type thingy, where user gets to see the number of days left for his contract to complete. Something like start_date_time="today" and end_date_time=y where the value of y is retrieved from the database (DATETIME type). It is in the mysql datetime format (yyyy-mm-dd HH:mm:ss).
<?php
include_once '../include/connections.php';
$id =$_REQUEST['uid'];
$result= mysql_query("SELECT * FROM data WHERE uid = '$id'");
$test = mysql_fetch_array($result);
echo $test[14];
echo "<br /><br />";
$today=time();
$enddate=strtotime('$test[14]');
$timediff = $enddate - $today;
$days=intval($timediff/86400);
$remaining=$timediff%86400;
$hours=intval($remaining/3600);
$remaining=$remaining%3600;
$mins=intval($remaining/60);
$secs=$remaining%60;
echo "<br>".$days.' days '.$hours.' hours '.$mins.' minutes and '.$secs.' seconds.';
?>
When I echo $test[14];, I get the date and time as stored in the database which is
(2012-09-26 00:00:00)
When i echo $today; then i get it in this format 1348381896. Now, how do i convert this format to the one retrieved from the db so that i can subtract the 2 dates and get the number of days and time left?
You can use these 2 functions to convert dates to each other,
Use this for timestamp to MySQL datetime:
$timestamp = '1348381896';
$date = date('Y-m-d H:i:s', $timestamp);
echo $date;
Use this one for MySQL datetime to timestamp:
$date = '2012-09-26 00:00:00';
$timestamp = strtotime($date);
echo $timestamp;
Also if you are willing to Subtract your dates in MySQL side, you can use the DATEDIFF and or TIMEDIFF functions:
Also you can work with timestamps in MySQL too, using TIMESTAMPDIFF and UNIX_TIMESTAMP functions ...
You could use PHP's DateTime classes for this:-
$today = new DateTime();
$mysqlDate = "2012-12-15 13:40:20"; //for example
// To match your code this would be $mysqlDate = $test[14];
$mysqlFormat = 'Y-m-d H:i:s';
$endDate = DateTime::createFromFormat($mysqlFormat, $mysqlDate);
$diff = $today->diff($endDate);
echo "You have {$diff->d} days, {$diff->h} hours and {$diff->m} minutes left";
This will give the following output:-
You have 22 days, 6 hours and 5 minutes left
(This will change depending on when you run the code).
$diff is an instance of DateInterval.
date formats acceptable to DateTime::createFromFormat() can be found here http://www.php.net/manual/en/function.date.php
I have a timestamp stored in a session (1299446702).
How can I convert that to a readable date/time in PHP? I have tried srttotime, etc. to no avail.
Use PHP's date() function.
Example:
echo date('m/d/Y', 1299446702);
strtotime makes a date string into a timestamp. You want to do the opposite, which is date. The typical mysql date format is date('Y-m-d H:i:s'); Check the manual page for what other letters represent.
If you have a timestamp that you want to use (apparently you do), it is the second argument of date().
I just added H:i:s to Rocket's answer to get the time along with the date.
echo date('m/d/Y H:i:s', 1299446702);
Output: 03/06/2011 16:25:02
$timestamp = 1465298940;
$datetimeFormat = 'Y-m-d H:i:s';
$date = new \DateTime();
// If you must have use time zones
// $date = new \DateTime('now', new \DateTimeZone('Europe/Helsinki'));
$date->setTimestamp($timestamp);
echo $date->format($datetimeFormat);
result: 2016-06-07 14:29:00
Other time zones:
Africa
America
Antarctica
Arctic
Asia
Atlantic
Australia
Europe
Indian
Pacific
Others
If you are using PHP date(), you can use this code to get the date, time, second, etc.
$time = time(); // you have 1299446702 in time
$year = $time/31556926 % 12; // to get year
$week = $time / 604800 % 52; // to get weeks
$hour = $time / 3600 % 24; // to get hours
$minute = $time / 60 % 60; // to get minutes
$second = $time % 60; // to get seconds
If anyone wants timestamp conversion directly to a DateTime object, there's a simple one-liner:
$timestamp = 1299446702;
$date = DateTime::createFromFormat('U', $timestamp);
Following #sromero comment, timezone parameter (the 3rd param in DateTime::createFromFormat()) is ignored when unix timestamp is passed, so the below code is unnecessary.
$date = DateTime::createFromFormat('U', $timestamp, new DateTimeZone('UTC'); // not needed, 3rd parameter is ignored
You may check PHP's manual for DateTime::createFromFormat for more info and options.
Try this one:
echo date('m/d/Y H:i:s', 1541843467);
$epoch = 1483228800;
$dt = new DateTime("#$epoch"); // convert UNIX timestamp to PHP DateTime
echo $dt->format('Y-m-d H:i:s'); // output = 2017-01-01 00:00:00
In the examples above "r" and "Y-m-d H:i:s" are PHP date formats, other examples:
Format Output
r ----- Wed, 15 Mar 2017 12:00:00 +0100 (RFC 2822 date)
c ----- 2017-03-15T12:00:00+01:00 (ISO 8601 date)
M/d/Y ----- Mar/15/2017
d-m-Y ----- 15-03-2017
Y-m-d H:i:s ----- 2017-03-15 12:00:00
Try it.
<?php
$timestamp=1333342365;
echo gmdate("Y-m-d\TH:i:s\Z", $timestamp);
?>
You can try this:
$mytimestamp = 1465298940;
echo gmdate("m-d-Y", $mytimestamp);
Output :
06-07-2016
Unless you need a custom date and time format, it's easier, less error-prone, and more readable to use one of the built-in date time format constants:
echo date(DATE_RFC822, 1368496604);
echo date("l M j, Y",$res1['timep']);
This is really good for converting a unix timestamp to a readable date along with day. Example:
Thursday Jul 7, 2016
echo 'Le '.date('d/m/Y', 1234567890).' à '.date('H:i:s', 1234567890);
I have used this:
<?php echo date('d/m/Y H:i a', $row['start_time']); ?>