i am trying to use echo inside url. i have store data from the form in database and now i am also fetching it on my page and its working well. Now i am trying to print that data i.e. number and date in url.
Is it possible and if possible please help me out
here is my data that i am fetching and it prints the output
echo $number;
echo $yyyymmdd;
and here is my url in which i want to insert ' echo $number; ' and ' echo $yyyymmdd; ' on the place of and .
$json= file_get_contents("http://api.com/api/a2/live/apikey/fc5a69f870fdb03/number/<number>/date/<yyyymmdd>/");
I have also tried something like this but it gives error of syntex error.
$json= file_get_contents("http://api.com/api/a2/live/apikey/fc5a69f870fdb03/number/"echo $number;"/date/"echo $yyyymmdd;"/");
Another way to add changing parameters to a URL (or string) is by using sprintf(). You define your URL and a type specifier like %d as a placeholder for numbers, and %s for strings. See the php doc for the full list of type specifiers.
$urlFormat = "http://api.com/api/a2/live/apikey/fc5a69f870fdb03/number/%d/date/%s/"
^ ^
Then call sprintf with the changing parameters in order of appearance.
$url = sprintf($urlFormat, $number, $yyyymmdd);
$json = file_get_contents($url);
This becomes more convenient especially if you are calling file get contents in a loop.
Create two variables and append those two inside double-quote or single quote, depending upon the quotes which you have opened and close it.
<?php
$number=123;
$yyyymmdd='2018-10-9';
$json= file_get_contents("http://api.com/api/a2/live/apikey/fc5a69f870fdb03/".$number."/<number>/date/<".$yyyymmdd.">/");
?>
$json= file_get_contents("http://api.com/api/a2/live/apikey/fc5a69f870fdb03/number/".$number."/date/".$yyyymmdd."/");
When you compose text, you do not need "echo" but just can write variable.
You can directly use variables in double quotes like this
file_get_contents("http://api.com/api/a2/live/apikey/fc5a69f870fdb03/number/$number/date/$yyyymmdd/");
Sample code below
$number = 344;
$yyyymmdd = "20180301";
$url1 = "http://api.com/api/a2/live/apikey/fc5a69f870fdb03/number/$number/date/$yyyymmdd/";
echo "url1 ".$url1."\n";
$url2 = "http://api.com/api/a2/live/apikey/fc5a69f870fdb03/number/".$number."/date/".$yyyymmdd."/";
echo "url2 ".$url2. "\n";
Related
I have some data resembling the following:
444444444444444
I want to add a mask to the data so it looks like this:
44.444.444.4-444.444
I tried using:
$x_data = preg_replace('~.{3}\K(?!$)~', '.', $x_data);
Which got me:
444.444.444.444.444
How do I modify my preg_replace to give me the exact output I am looking for?
You could use a capture group approach, and then connect the subcomponents according to the format you are expecting.
$x_data = "444444444444444";
echo $x_data . "\n";
$x_data = preg_replace('/^(\d{2})(\d{3})(\d{3})(\d)(\d{3})(\d{3})$/',
'$1.$2.$3.$4-$5.$6',
$x_data);
echo $x_data;
This prints:
444444444444444
44.444.444.4-444.444
I'm sorry that this is basic. When I use this PHP code it works fine:
$data = '{"reportID":1092480021}';
However, when I run my URL like this:
http://localhost:8000/new/reportget.php?type=1092480021
and use this PHP code:
$reportref = $_GET['type'];
$data = '{"reportID:".$reportref."}"';
I get the error
Error_description:reportID is required
I think it's an error with how I am joining my variable to the string but I can't understand where I am going wrong.
Your string is improperly quoted. To match the format in your first example use:
$data = '{"reportID":' . $reportref.'}';
Note there are no double quotes on the last curly.
Even better:
$reportref = 1092480021;
$data = [ 'reportId' => $reportref ];
var_dump(json_encode($data));
Output:
string(23) "{"reportId":1092480021}"
For simple view and understanding, can you try out:
$data = "{\"reportID\":$reportref}";
Think that should sort it out
Use it like this
data = '{"reportID:"'.$reportref.'"}"';
It isn't working because you wrap all the value within single quote and when it come to concatenate the $reprtref you put directly .$reportref without closing the first single quote and after putting the value to concatenate you forget to open another single quote
'{"reportID:".$reportref."}"';
the correct value is
'{"reportID:"' . $reportref . '"}"';
and to match the way you specify your $data value It must be like this
'{"reportID":' . $reportref . '}';
I am making a price crawler for a project but am running into a bit of an issue. I am using the below code to extract values from an html page:
$content = file_get_contents($_POST['url']);
$resultsArray = array();
$sqlresult = array();
$priceElement = explode( '<div>value I want to extract</div>' , $content );
Now when I use this to get certain elements I only get back
Finance: {{value * value2}}
I want to get the actual value that would be displayed on the screen e.g
Finance: 7.96
The other php methods I have tried are:
curl
file_get_html(using simple_html_dom library)
None of these work either :( Any ideas what I can do?
You just set the <div>value I want to extract</div> as a delimiter, which means PHP looks for it to separate your string to array whenever this occurs.
In the following code we use , character as a delimiter:
<?php
$string = "apple,banana,lemon";
$array = explode(',', $string);
echo $array[1];
?>
The output should be this:
banana
In your example you set the value you want to extract as a delimiter. That's why this happens to you. You'll need to set a delimiter between your string you want to obtain and other string you won't need at the moment.
For example:
<?php
$string = "iDontNeedThis-dontExtractNow-value I want to extract-dontNeedEither";
$priceElement = explode('-', $string);
echo "<div>".$priceElement[2]."</div>";
?>
The code should output this to your HTML page:
<div>value I want to extract</div>
And it will appear on your page like this:
value I want to extract
If you don't need to save the whole array in a variable, you can save the one index of it to variable instead:
$priceElement = explode('-', $string)[2];
echo $priceElement;
This will save only value I want to extract so you won't have to deal with arrays later on.
I need to get this output.
the result is"random"safdsaf
I am using this piece of code
<?php
$x = "random";
echo 'the result is' .$x. 'safdsaf';
?>
But i am getting this
the result israndomsafdsaf
I have to define random before printing it.
i.e. I do not want to change this piece of code
<?php
$x = "random";
What change should i make inside echo to get the desired output?
If you are using the same type of quotes delimit the quotes in your string like this:
echo "The result is\"" .$x. "\"safdsaf";
or simply use two sets of different quotes:
echo 'the result is"' .$x. '"safdsaf';
Output of either line of code:
The result is"random"safdsaf
Try this
Added the little bit space befor ' and added ", it will give the some out put as you want
echo 'the result is "' .$x. '" safdsaf';
the result will be
The result is "random" safdsaf
If you want to print out double quotes you can include them in single quotes
Something like this would do the trick.
$x = '"random"';
If for whatever reason you don't want to use single quotes you can also escape them like :
$x = "\"random\"";
As you want to keep the string, I suggest you change the original line where you put it in :
echo 'the result is"' .$x. '"safdsaf';
the principle stays the same
Here's some reading material : http://php.net/manual/en/language.types.string.php
You can use simply :-
echo 'the result is "' .$x. '" safdsaf';
OR you can use .
echo "the result is \" $x\" safdsaf";
Using the \ before the quote like this: the result is \"random\" safdsaf.
if you have alot of quotes and such in a string, i would suggest using the addslashes(). This method will do the work for you for you.
For more info, take a look here - http://www.w3schools.com/php/func_string_addslashes.asp
I would appreciate some help here:
What I want to do:
remove &itemsperpage=10 from:
http://localhost/thi/search/filter.html?type=featured&page=2&itemsperpage=10
and create a link from it:
http://localhost/thi/search/filter.html?type=featured&page=2&itemsperpage=15
here's what I have come up with so far:
<a href="<?php echo url::site(url::current()) . http_build_query($_GET) // don't know what follows ?>"
the framework functions I'm using are:
url::current() = returns current url in controller/action format
url::site() = returns absolute url i.e http://localhost/site/controller/action
so I have to remove '&itemsperpage' from the resulting string in the http_build_query function
but I am having trouble with character encodings and such! please help!
so here's the problem with character encoding:
$needle = '&itemsperpage';
$querystring = http_build_query($_GET) . '<br/>';
// echo $querystring . '<br/>';
$pos = strpos($querystring, $needle);
$remove = substr($querystring, ((int)$pos));
echo substr(str_replace($remove, '', $querystring), 1); // returns ';'
I can't remove the string '&itemsperpage' from the result of http_build_query which is:
'type=featured&page=2&itemsperpage=10' and functions like strstr outputs nothing
I would just do this:
$array = $_GET;
$array['itemsperpage'] = 15;
Then just use your code, but with the new variable (and the ?):
<a href="<?php echo url::site(url::current()) . '?' . http_build_query($array)">
The HttpQueryString class has several methods for getting, setting, modifying query strings and 'translating' their charsets.
You can achieve the effect you're looking for by removing the itemsperpage element from the $_GET array before building the query string.
unset($_GET['itemsperpage']);
And then just use the code you already wrote:
<a href="<?php echo url::site(url::current()) . http_build_query($_GET); ?>">
EDIT: I misread your post. I thought you only wanted to remove the field / value pair from the GET request. All you have to do is overwrite the value with the value you want:
$_GET['itemsperpage'] = 15;
And then use the code you already wrote.