PHP break while do from inside of a nested foreach - php

I have a do while loop and a nested foreach loop. And i'm using break 2 to break both(do while and foreach) if $x > N(in this case N = 4). For now it works but...is this a good practice? Or should i break the while loop in some other way?
$arr = ['a', 'b', 'c'];
$x = 0;
do{
//do something here...
//and something here...
foreach($arr as $k => $v){
if($x > 4){
break 2;
} else{
echo '(' . $x . ')' . $k . ' - ' . $v . '<br />';
}
}
$x++;
} while($x < 10);
Thank you! :D

Using a do{}while(); loop should be a very deliberate decision. Its behavior forces an initial iteration and only checks the break condition(s) at the end of each iteration.
Compare this to a while() loop or better for your purposes a for() loop. It performs the conditional check before each iteration AND the counter, the break condition(s), and the incrementation are all in one readable location.
I'm not sure if you actually mean to execute...
//do something here...
//and something here...
...on the same iteration where the break 2 occurs. What circumstance makes this suitable for your project? The logic of your snippet says, that you want to execute those mystery lines of code when $x = 0, 1, 2, 3, 4, and 5; but the foreach() block is only to be executed when $x = 0, 1, 2, 3, and 4.
If I am right that your design logic is slightly flawed then, I do not recommend writing a break point inside your loop with the other processes. I recommend a for() loop.
$arr = ['a', 'b', 'c'];
for ($x = 0; $x <= 4; ++$x) {
//do something here...
//and something here...
foreach ($arr as $k => $v){
echo "($x)$k - $v<br />";
}
}
Because of your break 2, your while($x < 10); condition will never be satisfied, so it is an illogical design inclusion.
If you DO, in fact, need to execute those mystery lines, but not the looped echoes when $x = 5, then relinquish loop control to the break entirely and use while(true) (writing an indefinite loop) to remove developer confusion.
$arr = ['a', 'b', 'c'];
$x = 0;
while (true) {
//do something here...
//and something here...
if ($x > 4) {
break 2;
}
foreach ($arr as $k => $v) {
echo "($x)$k - $v<br />";
}
++$x;
}

In your example break 2 will work fine and yes, it is part of PHP. However, I have always had a concern about breaking out of loops especially when these are nested.
Consider if you were working on code that was much more complex that that included nested loops. When you specified the break out of 2 loops, you would need to be very careful that you took account of the breaks in any new code.
So while using break may work, I always to try to avoid breaks and always consider if there is a different option that works without the need for breaks (especially when you have nested loops). In your example, I would use the code:
$arr = ['a', 'b', 'c'];
$x = 0;
do{
//do something here...
//and something here...
foreach($arr as $k => $v){
echo '(' . $x . ')' . $k . ' - ' . $v . '<br />';
}
$x++;
} while($x <= 4);
This usually leads to neater code that is easier to maintain.

Related

How does this foreach loop code work in php?

I'm having trouble understanding how the foreach loop works in this code. My understanding is that $Score is assigned the arrays of $Die1 + $Die2, but how does $Score gain the value of 1,2,3,4,5,6,5,4,3,2,1? Shouldn't it be 1,2,3,4,5,6,1,2,3,4,5,6 in a sequence since that's how the values are listed in the $FaceValues array? Is there something that's happening in the foreach statements that I'm missing? Can anyone could elaborate on the double foreach statements here?
$FaceValues = array(1, 2, 3, 4, 5, 6);
$ScoreCount = array();
for($PossibleRolls = 2; $PossibleRolls <= 12; ++$PossibleRolls){
$ScoreCount[$PossibleRolls] = 0;
}
foreach ($FaceValues as $Die1) {
foreach ($FaceValues as $Die2) {
// all possible combinations
++$RollCount;
// increment RollCount
$Score = $Die1 + $Die2;
// 1,2,3,4,5,6
// 6,5,4,3,2,1
++$ScoreCount[$Score];
}
}
foreach ($ScoreCount as $ScoreValue => $ScoreTimes){
echo "<p> A combined value of $ScoreValue occured $ScoreTimes of $RollCount times. </p>";
}
On the first iteration $Die1 is 1 and $Die2 is 2. So it begins at 2 and goes up to 7. Then the inner loop is finished and the outer loop proceeds to set $Die1 to 2. You should then see the number 3 through 8.
You can use echo or var_dump() and exit() to print the values at each step and stop if you're having trouble following-along.

Passing two variables into a 'foreach' loop

I need help regarding a foreach() loop. aCan I pass two variables into one foreach loop?
For example,
foreach($specs as $name, $material as $mat)
{
echo $name;
echo $mat;
}
Here, $specs and $material are nothing but an array in which I am storing some specification and material name and want to print them one by one. I am getting the following error after running:
Parse error: syntax error, unexpected ',', expecting ')' on foreach line.
In the Beginning, was the For Loop:
$n = sizeof($name);
for ($i=0; i < $n; $i++) {
echo $name[$i];
echo $mat[$i];
}
You can not have two arrays in a foreach loop like that, but you can use array_combine to combine an array and later just print it out:
$arraye = array_combine($name, $material);
foreach ($arraye as $k=> $a) {
echo $k. ' '. $a ;
}
Output:
first 112
second 332
But if any of the names don't have material then you must have an empty/null value in it, otherwise there is no way that you can sure which material belongs to which name. So I think you should have an array like:
$name = array('amy','john','morris','rahul');
$material = array('1w','4fr',null,'ff');
Now you can just
if (count($name) == count($material)) {
for ($i=0; $i < $count($name); $i++) {
echo $name[$i];
echo $material[$i];
}
Just FYI: If you want to have multiple arrays in foreach, you can use list:
foreach ($array as list($arr1, $arr2)) {...}
Though first you need to do this: $array = array($specs,$material)
<?php
$abc = array('first','second');
$add = array('112','332');
$array = array($abc,$add);
foreach ($array as list($arr1, $arr2)) {
echo $arr1;
echo $arr2;
}
The output will be:
first
second
112
332
And still I don't think it will serve your exact purpose, because it goes through the first array and then the second array.
You can use the MultipleIterator of SPL. It's a bit verbose for this simple use case, but works well with all edge cases:
$iterator = new MultipleIterator();
$iterator->attachIterator(new ArrayIterator($specs));
$iterator->attachIterator(new ArrayIterator($material));
foreach ($iterator as $current) {
$name = $current[0];
$mat = $current[1];
}
The default settings of the iterator are that it stops as soon as one of the arrays has no more elements and that you can access the current elements with a numeric key, in the order that the iterators have been attached ($current[0] and $current[1]).
Examples for the different settings can be found in the constructor documentation.
This is one of the ways to do this:
foreach ($specs as $k => $name) {
assert(isset($material[$k]));
$mat = $material[$k];
}
If you have ['foo', 'bar'] and [2 => 'mat1', 3 => 'mat2'] then this approach won't work but you can use array_values to discard keys first.
Another apprach would be (which is very close to what you wanted, in fact):
while ((list($name) = each($specs)) && (list($mat) = each($material))) {
}
This will terminate when one of them ends and will work if they are not indexed the same. However, if they are supposed to be indexed the same then perhaps the solution above is better. Hard to say in general.
Do it using a for loop...
Check it below:
<?php
$specs = array('a', 'b', 'c', 'd');
$material = array('x', 'y', 'z');
$count = count($specs) > count($material) ? count($specs) : count($material);
for ($i=0;$i<$count;$i++ )
{
if (isset($specs[$i]))
echo $specs[$i];
if (isset($material[$i]))
echo $material[$i];
}
?>
OUTPUT
axbyczd
Simply use a for loop. And inside that loop, extract values of your array:
For (I=0 to 100) {
Echo array1[i];
Echo array2[i]
}

Repeat ForEach Loop (PHP) But Break [duplicate]

I have a php array $numbers = array(1,2,3,4,5,6,7,8,9)
if I am looping over it using a foreach foreach($numbers as $number)
and have an if statement if($number == 4)
what would the line of code be after that that would skip anything after that line and start the loop at 5? break, return, exit?
You are looking for the continue statement. Also useful is break which will exit the loop completely. Both statements work with all variations of loop, ie. for, foreach and while.
$numbers = array( 1, 2, 3, 4, 5, 6, 7, 8, 9 );
foreach( $numbers as $number ) {
if ( $number == 4 ) { continue; }
// ... snip
}
continue;
Continue will tell it to skip the current iteration block, but continue on with the rest of the loop. Works in all scenerios (for, while, etc.)
Break; will stop the loop and make compiler out side the loop. while continue; will just skip current one and go to next cycle.
like:
$i = 0;
while ($i++)
{
if ($i == 3)
{
continue;
}
if ($i == 5)
{
break;
}
echo $i . "\n";
}
Output:
1
2
4
6 <- this won't happen
I suppose you are looking for continue statement. Have a look at http://php.net/manual/en/control-structures.continue.php
dinel

echo a number in php

I am trying to learn php, and I am playing around with while loops. I was wondering how to print out a specific number in an array in php. Fx:
$a = [1,3,5,7,9,11,13];
$s = 3;
while($a == 3) {
echo $s.' is in the row';
$a++;
}
In this example I would like to run through the $a and see if 3 exist there. If it does it has to echo '3 is in the row' I tried to make a while loop, but it is not correct. Can anyone see what I am doing wrong? Just to say it, I think it is very wrong, but I don't know how to solve it, if I have to use the while loop?
Best Regards
Mads
Your while condition reads: "While the value of $a equals 3", but $a is an array, so its value can't ever be 3. The loop will never be executed. In PHP, we would write:
if (in_array($s, $a))
echo $s, ' was found in the array';
Or, if you insist on writing loops:
foreach ($a as $key => $value)
{
if ($value == $s)
{
echo $s, ' was found at offset ', $key;
break;//end terminate loop
}
}
Of course, you could also write:
for ($i=0, $j=count($a);$i<$j;++$j)
{
if ($a[$i] == $s)
{//you could move this condition to the loop itself, even
echo $s, ' found in array at offset ', $i;
break;
}
}
You can, if you want use a while loop, too, but that wouldn't be the best choice for your particular case. Just read through the manual on php.net. There are many, many array_* functions available, and there are many ways to iterate over your data.
Another worry is your using the array name as a sort-of C-style pointer: $a++; in C, an pointer can be incremented to set it to point to the next value in an array (if the new memory address is valid, and the pointer is valid, and all of the other things you have to worry about in C). PHP does not work this way. An array isn't really an array: it's a hash map. incrementing an array, therefore, is pointless and most likely to be a bug. The for loop is the closest you can get to traversing an array using the ++ operator.
You're looking for in_array. This checks if a value exists in an array, in the form of:
in_array ( mixed $needle , array $haystack )
So, in your case, you'd want to do:
$a = [1,3,5,7,9,11,13];
$s = 3;
if (in_array($s, $a)) {
echo $s.' is in the row';
}
foreach($a as $b) {
if($b == 3)
echo $b.' is in the row';
}
Modify slightly your code changing while condition:
$a = array(1,3,5,7,9,11,13);
$s = 3;
$counter = 0;
while($counter < count($a)) {
if ( $a[$counter] == $s )
echo $s.' is in the row';
$counter++;
}
Added counter to iterate through while loop until end of array.
count() method returns number of items in array.
This solution prints all occurences of your number.
To have better code, change names of variables:
$numbers = array(1,3,5,7,9,11,13);
$target = 3;
$counter = 0;
while($counter < count($numbers)) {
if ( $numbers[$counter] == $target )
echo $target.' is in the row';
$counter++;
}
There are two ways to do it,
First, you can loop through all items in the array using a foreach() loop.
That way, you can go through them all and if you have multiple conditions, it makes your code a bit more readable.
And example of that loop is like this:
foreach($array as $array_item) {
if($array_item === 3) {
echo "3 is in the array";
}
}
The alternative is to use a built in function to find if something is in the array. THis is probably much faster, though I haven't benchmarked the difference.
if(in_array(3, $array)) {
echo "3 is in the array";
}
you can use
array_search ,in_array , and forearch or for loops to itertate through the array.
For learning purposes
$a = [1,3,5,7,9,11,13];
$s = 3;
for($i=0;$i<count($a);$i++)
{
if($a[$i]==$s){
echo $s.' is in the row';
}
}
of course in real life
if (in_array(3, $a)) {
// Do something
}
would be better;
<?php
$a = [1,3,5,7,9,11,13];
$s = 3;
for($a=0;$a < 20; $a++)
{
while($a == 3) {
echo $s.' is in the row';
//$a++;
}
}
?>

Stop loop and continue from stopping point

problem Solved..... thanks alot
I want to break the loop and continue loop from the point that the loop stop. E.g., if I have array like this:
$arr = array('1', '2', '3', '4', '5');
I want to stop looping on number '3' and take an action and continue from '4'. I tried this code:
$x = 0;
foreach($arr as $key){
if($x == 3) break; // here I stop loop in number 3
echo $key;
$x++;
// I want to continue loop from 4
}
why stop?
use
$x = 0;
foreach($arr as $key){
if($x == 3)
doSomething();
else
echo $key;
$x++;
}
it will continue with iteration 4, after "doing Something". (Correctly spoken: It will iterate from 1 to n, and only perform an action, when $x==3, otherwhise print the key.)
If you just want to avoid key "3" beeing printed, you can use the continue statement:
$x = 0;
foreach($arr as $key){
if($x++ == 3)
continue; //proceed with next iteration
echo $key;
}
but then you need to use $x++ in your comparrision, otherwhise it will get stuck at $x==3, cause the increment will always be skipped.
Sidenode: If you NEED $x to be the correct line number, use a for() instead of foreach() - use foreach(), if you dont care about the actual line number, but need to process ALL entries within an array.
Sidenode 2: foreach($arr as $key) is wrong. This expression will give you the value for each array entry, not the key. use foreach($arr as $key=>$value) or foreach($arr as $value) to have a correct name on the variable(s).

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