PHP Average Values in Multiple Arrays to 1 Array - php

Question

I have an array full of numbers and I can easily get the average of one array with.
if(count($averageprice)) {
$averageprice= array_filter($averageprice);
$averageprice= array_sum($averageprice)/count($averageprice);
}
But say I have 4 arrays all with prices. They are all in the right order and contain the same amount of values. How can I create a single array that keeps the order of each value but averages it between all arrays?
Thanks!
Edit for better example:
$array1 =array(10,15,20);
$array2 =array(14,13,22);
$array3 =array(12,18,26);
I want a new array that averages all the values in the array into one array. Note the amount of arrays isn't always the same per each time. However no matter how many arrays it is, they will always have the same amount of values in it. (Sometimes 4, sometimes 8, etc)

Answer 1

FIRST WAY: arrays in different variables
$arr0 = [0,10,2];
$arr1 = [0,20,4];
$arr2 = [0,30,6];
Note: array_filter will remove the 0's... For example: the average
of [0, 10, 2] will be 6 (i.e.: (10 + 2) / 2) and NOT (0+10+2)/3 = 4. Is
this really what you mean? Do you want to discard 0's before averaging?
$arr0 = array_filter($arr0);
$arr1 = array_filter($arr1);
$arr2 = array_filter($arr2);
print_r($arr0); // (just to point out again the previous comment)
Array
(
[1] => 10
[2] => 2
)
THIS IS THE IMPORTANT LINE:
$averages = array_map(function($a){return array_sum($a)/count($a);}, [$arr0, $arr1, $arr2]);
print_r($averages)
Array
(
[0] => 6
[1] => 12
[2] => 18
)
SECOND WAY: All the arrays inside a bigger array.
$arrs = [[0,10,2], [0,20,4], [0,30,6]];
$arrs = array_map(function($a){return array_filter($a);}, $arrs);
$result = array_map(function($a){return array_sum($a) / count($a);}, $arrs);
print_r($arrs);
Array
(
[0] => Array
(
[1] => 10
[2] => 2
)
[1] => Array
(
[1] => 20
[2] => 4
)
[2] => Array
(
[1] => 30
[2] => 6
)
)
print_r($result);
Array
(
[0] => 6
[1] => 12
[2] => 18
)