Retrieve data based on user id (CodeIgniter) - php

Question

Im fairly new with php so please bear with me. I have two tables in my database, users and onlineform tables. The onlineform table have userid field as a foreign key for the id field in users table. Im trying to display data from onlineform table based on current user login. The problem is, it display data from all users and not the one who logged in. I have setup a query in my form_model but i dont know if the query is correct
this is the model
form_model.php:
function getEmployees()
{
$this->db->select("users.id, onlineform.date, onlineform.day, onlineform.in1,
onlineform.out1, onlineform.in2, onlineform.out2");
$this->db->from('users');
$this->db->join('onlineform','users.id = onlineform.userid', 'left');
$this->db->order_by('date asc');
$query = $this->db->get();
return $query->result();
}
this is the controller
form.php
public function table()
{
if($this->session->userdata('username') != '')
{
$this->load->model('form_model');
$query = $this->form_model->getEmployees();
$data['EMPLOYEES'] = null;
if($query) {
$data['EMPLOYEES'] = $query;
}
}
else
{
redirect(base_url() . 'index.php/form/login');
}
$this->load->view('table.php', $data);
}
and this is my view
table.php
<?php
foreach($EMPLOYEES as $employee)
{?>
<tr>
<td align="center"
<?php if($employee->day === "SAT" || $employee->day === "SUN"): ?> style="background-color:#A9A9A9; color: white;" <?php endif; ?>>
<strong><?=$employee->day;?></strong>
</td>
<td align="center"
<?php if($employee->day === "SAT" || $employee->day === "SUN"): ?> style="background-color:#A9A9A9; color: white;" <?php endif; ?>>
<strong><?=$employee->date;?></strong>
</td>
<td><?=$employee->out1;?></td>
<td><?=$employee->in1;?></td>
<td><?=$employee->out2;?></td>
<td><?=$employee->in2;?></td>
</tr>
<?php }?>

Answer 1

You can pass the current logged in userId into the model through getEmployees($userid)
$query = $this->form_model->getEmployees($userid);
And then use it in your query to get current userId that matches logged in user, to user in database;
function getEmployees($userid)
{
$this->db->select("users.id, onlineform.date, onlineform.day, onlineform.in1,
onlineform.out1, onlineform.in2, onlineform.out2");
$this->db->from('users');
$this->db->where('onlineform','users.id',$userid); //add this line
$this->db->join('onlineform','users.id = onlineform.userid', 'left');
$this->db->order_by('date asc');
$query = $this->db->get();
return $query->result();
}
And then pass it normally to your view.
Hope this helps.

Answer 2

You can save the current logged in userid in session then you can use it when you retrieve the data from database.
change your form_model.php code to this
function getEmployees()
{
$this->db->select("users.id, onlineform.date, onlineform.day, onlineform.in1,
onlineform.out1, onlineform.in2, onlineform.out2");
$this->db->from('users');
$this->db->join('onlineform','users.id = onlineform.userid', 'left');
$this->db->where("users.id", $this->session->userdata('current_user_id'));
$this->db->order_by('date asc');
$query = $this->db->get();
return $query->result();
}